Definitions Bank
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24–30% OF THE PAPER
Section I Β· Give the definition accurately Β· 3 marks each

The Definitions Bank

Eight to ten terms, three marks each. It is the first section of every paper, the most predictable block of marks on it, and the one where knowing the material is not enough β€” a definition is graded on shape, not on how much you can say.

136Terms
15Set in a real paper
9With expected phrasing
3β€²Per term
01

How a three-mark definition is actually marked

The instruction on the paper is worth reading closely: β€œGive the definition accurately for the following specialized terms.” Not describe, not discuss β€” define, accurately. You are being asked to produce a specific object, and the examiner has a mark scheme with three boxes on it. Write beautifully around the boxes and you score nothing.

Almost every biochemistry term is one of three kinds of thing, and each has its own shape. Work out which kind you are looking at and the structure of the answer follows automatically:

  • A molecule or structure (haem, zwitterion, nucleosome, domain) β€” say what class of thing it is, then its defining composition. β€œA cyclic tetrapyrrole consisting of four pyrrole rings linked by methyne bridges, with one atom of ferrous iron at the centre.”
  • A process or phenomenon (transamination, glycolysis, the Bohr effect, allosteric regulation) β€” say what is converted into what, or what is coupled to what, and where it happens. β€œTransfer of an amino group from an amino acid to a keto acid…”
  • A quantity or parameter (pI, Km, Pβ‚…β‚€) β€” say what it measures, and state the condition that defines it. β€œThe pH at which a molecule bears no net charge and therefore does not migrate in a direct-current electrical field.”
⭐ The same term, answered two ways
❌ What a 1-mark answer looks like
β€œThe isoelectric point is when an amino acid has no charge. It is important in electrophoresis and it is different for different amino acids.”
True, and nearly worthless. β€œNo charge” is imprecise β€” it is no net charge, which is a different claim. There is no statement of the condition that makes it measurable, and the last sentence answers a question that was not asked.
βœ… What a 3-mark answer looks like
β€œThe pH value at which a molecule bears no net charge and therefore does not migrate in a direct-current electrical field. It is the pH midway between the pKa values flanking the isoelectric species; above its pI a molecule is net negative, below it net positive.”
Same knowledge. Three ticks: the quantity, the condition, the consequence. Thirty seconds to write.
Three rules that cost nothing and earn marks

1 Β· Open with the category noun. β€œA cyclic tetrapyrrole…”, β€œThe pH at which…”, β€œA section of protein structure that…”. Never open with β€œIt is when” or β€œThis is where” β€” those phrases signal to an examiner that you are about to describe rather than define.

2 Β· Put the numbers in. If the term has a number attached β€” 3.6 residues per turn, 8.5 kDa, 26 mm Hg, one proton per two Oβ‚‚ β€” write it. Numbers are the cheapest possible evidence that you know the thing rather than the word.

3 Β· One sentence of significance, then stop. The marks are in the definition. A third sentence about clinical importance earns nothing when the question says define β€” and with eight to ten terms in twenty-four minutes, you do not have time to give it away.

Test yourself
  • What are the three kinds of term, and the shape each takes? → Molecule/structure β†’ class then composition Β· Process β†’ what converts to what, and where Β· Quantity β†’ what it measures and the defining condition
  • Why is β€œno charge” wrong for pI? → It is no net charge β€” the molecule is a zwitterion, carrying equal positive and negative charges
  • How long should a 3-mark definition take? → About three minutes including thinking β€” roughly two to four sentences
02

What Section I has actually asked

These are the eighteen terms set in the two papers whose text we can read β€” the 2019 paper (ten terms, 30%) and the 2020/21 paper (eight terms, 24%). Two terms were repeated across both papers: transamination and oxidative phosphorylation. That repetition is the single most useful fact on this page.

PaperTermModuleStatus
2019DegeneracyMolecular Biologycovered
2019TransaminationNitrogen Metabolism & Integrationcovered
2019ApolipoproteinsLipid Metabolismcovered
2019NucleosomesMolecular Biologycovered
2019Isoelectric pointProteins & Enzymescovered
2019Oxidative phosphorylationBioenergetics & Carbohydratescovered
2019Allosteric regulationProteins & Enzymescovered
2019PromoterMolecular Biologycovered
2019GlycolysisBioenergetics & Carbohydratescovered
2019One-carbon unitsNitrogen Metabolism & Integrationcovered
2020–21PromoterMolecular Biologycovered
2020–21TransaminationNitrogen Metabolism & Integrationcovered
2020–21LipoproteinsLipid Metabolismcovered
2020–21AnticodonMolecular Biologycovered
2020–21DomainProteins & Enzymescovered
2020–21Oxidative phosphorylationBioenergetics & Carbohydratescovered
2020–21TelomeresMolecular Biologycovered
2020–21Covalent regulationProteins & Enzymescovered
Read the pattern, not just the list

Only four of the eighteen came from Module A β€” isoelectric point, allosteric regulation, domain and covalent regulation. The rest are spread across metabolism and molecular biology, with molecular biology alone supplying six. Section I is not weighted towards the beginning of the course; it samples the whole of it.

Which means two things. First, the terms in this bank that are badged β˜… asked deserve to be word-perfect β€” they have already been set once. Second, the bank is incomplete by design until the remaining modules are written, and the table above is the checklist for finishing it.

A note on where the β€œexpected phrasing” boxes come from

Some cards below carry an amber Expected phrasing box. Those come from completed answer sheets for the 2020/21 paper, in which three different students give near-identical wording for the same term β€” strong evidence of a definition dictated in class and therefore of what the marking key rewards.

Two cautions. Those sheets are students' own work, not an official key, so every definition here is still written from Harper's and cited to it β€” the phrasing box tells you how to say it, not what is true. And the sheets carry the students' names and roll numbers, which is why none appear anywhere on this site.

0 / 136 marked
🧬 Proteins & Enzymes59 terms Β· Units 1–7
Isoelectric point (pI) β˜… asked 2019
+

The pH at which a molecule bears no net charge and therefore does not migrate in a direct-current electrical field.

The marks are in these
  • Numerically it is the pH midway between the pKa values of the ionisations on either side of the isoelectric species. For alanine (pKa 2.35 and 9.69) the pI is about 6.0.
  • Above its pI a molecule carries a net negative charge and migrates to the anode; below its pI it is net positive and migrates to the cathode.
Why it matters

The basis of electrophoresis, isoelectric focusing and isoelectric precipitation. Acidic amino acids (Asp, Glu) have a low pI; basic ones (Lys, Arg, His) a high pI.

Expected phrasing

The 2019 sheet gives: β€œpH value at which an amino acid bears no net charge and thus does not move in a direct current electrical field.” Write it in almost exactly those words.

Harper's ch.3, p.20 Read the unit β†’
Zwitterion
+

A molecule that contains an equal number of positively and negatively charged groups and therefore bears no net charge.

The marks are in these
  • Amino acids exist as zwitterions in blood and most tissues β€” the carboxyl group as –COO⁻ and the amino group as –NH₃⁺.
  • The fully uncharged structure cannot exist in aqueous solution, because there is no pH at which the carboxyl group is protonated and the amino group is not.
Why it matters

Explains why amino acids are highly water-soluble crystalline solids with very high melting points, and why they act as buffers.

Harper's ch.3, p.20 Read the unit β†’
Peptide bond
+

The amide linkage formed between the Ξ±-carboxyl group of one amino acid and the Ξ±-amino group of the next, with the elimination of a molecule of water.

The marks are in these
  • It possesses partial double-bond character, so the peptide unit is rigid and planar and normally in the trans configuration.
  • Rotation in the backbone is therefore restricted to the N–CΞ± bond (Ο†, phi) and the Cα–C bond (ψ, psi).
Why it matters

That restriction is what makes reproducible folding possible β€” the Ξ±-helix and Ξ²-sheet are simply the permitted combinations of Ο† and ψ.

Harper's ch.3, p.15 Read the unit β†’
Essential amino acid
+

An amino acid that humans cannot synthesise in amounts adequate to support infant growth or maintain adult health, and which must therefore be supplied in the diet.

The marks are in these
  • Harper's counts ten nutritionally essential L-Ξ±-amino acids.
Why it matters

The basis of protein quality in nutrition, and of the amino-acid requirements in parenteral feeding.

Harper's ch.3, p.15 Read the unit β†’
Selenocysteine
+

The 21st protein L-Ξ±-amino acid, in which a selenium atom replaces the sulfur of its analogue cysteine.

The marks are in these
  • Present in proteins from every domain of life; humans have about two dozen selenoproteins, including certain peroxidases and reductases and the iodothyronine deiodinases that convert thyroxine (Tβ‚„) to T₃.
  • Incorporated co-translationally at a recoded UGA codon rather than having a codon of its own.
Why it matters

⚠️ Your slide says the genetic code specifies 20 amino acids; Harper's calls selenocysteine the 21st. Answer β€œ20” if asked how many, but mention selenocysteine β€” both are right at different levels of detail.

Harper's ch.3, p.16 Read the unit β†’
Chirality of the Ξ±-carbon
+

The Ξ±-carbon of an amino acid bears four different groups β€” an amino group, a carboxyl group, a hydrogen and an R group β€” and is therefore chiral (asymmetric), making the molecule optically active.

The marks are in these
  • The sole exception is glycine, whose R group is a hydrogen atom, so the Ξ±-carbon carries two identical substituents and is not chiral.
  • Only L-isomers occur in proteins, although free D-serine and D-aspartate exist in brain tissue.
Why it matters

The structural basis of enzyme stereospecificity β€” enzymes act on L-amino acids but not D, and on D-sugars but not L.

Harper's ch.3, p.22 Β· TMU Lecture 1 Slide 14 Read the unit β†’
Primary structure
+

The linear sequence of amino acid residues in a polypeptide chain, joined by peptide bonds and read from the N-terminus to the C-terminus.

The marks are in these
  • It is determined by the nucleotide sequence of the gene, and dictates every higher order of structure and therefore the protein's function.
Why it matters

Clinically it serves as a molecular fingerprint identifying the protein, and as a route back to the gene that encodes it. Sickle cell disease shows how one residue can produce a disease.

Harper's ch.4, p.25 Read the unit β†’
Gel filtration (size-exclusion) chromatography
+

A chromatographic method that separates proteins according to their Stokes radius, using porous beads as the stationary phase.

The marks are in these
  • Proteins whose Stokes radius is too large to enter the pores are excluded, remain in the flowing mobile phase and elute first.
  • Smaller proteins enter the pores, are retarded, and elute later β€” so proteins emerge in descending order of Stokes radius.
Why it matters

This is Practical Exp 1. Note the counter-intuitive elution order: large first. Writing β€œseparates by molecular weight” loses the mark that β€œStokes radius” earns.

Harper's ch.4, p.27 Read the unit β†’
Stokes radius
+

The radius of the sphere a protein occupies as it tumbles in solution.

The marks are in these
  • It is a function of both molecular mass and shape: a rapidly tumbling elongated protein sweeps out a larger effective volume than a spherical protein of the same mass, and so behaves as the larger molecule.
Why it matters

Why gel filtration is defined on Stokes radius rather than on mass alone.

Harper's ch.4, p.27 Read the unit β†’
Affinity chromatography
+

Purification of a protein by exploiting its specific, high-affinity binding to a ligand immobilised on the stationary phase β€” a substrate, product, coenzyme or inhibitor.

The marks are in these
  • In theory only proteins that interact with the immobilised ligand adhere; all others wash through.
  • Bound protein is eluted by competition with free soluble ligand, or less selectively with urea, guanidine hydrochloride, mildly acidic pH or high salt.
  • Recombinant examples: a Ni²⁺ matrix binding a polyhistidine tag, a glutathione matrix binding a GST fusion.
Why it matters

The most selective single purification step available, because it separates on biological specificity rather than a bulk physical property.

Harper's ch.4, p.28 Read the unit β†’
SDS-PAGE
+

Polyacrylamide gel electrophoresis in the presence of the anionic detergent sodium dodecyl sulfate, in which separation depends on relative molecular mass (Mr) alone.

The marks are in these
  • SDS binds at about one molecule per two peptide bonds, denaturing the polypeptide and conferring an approximately uniform charge-to-mass ratio β€” so charge is eliminated as a variable.
  • Used with 2-mercaptoethanol or dithiothreitol to reduce disulfide bonds, it resolves the individual subunits of a multimeric protein.
  • Bands are visualised with a dye such as Coomassie Blue.
Why it matters

The standard method for assessing protein purity.

Harper's ch.4, p.28 Read the unit β†’
Isoelectric focusing (IEF)
+

Electrophoretic separation of proteins in a pH gradient generated within a polyacrylamide matrix by ionic buffers called ampholytes together with an applied electric field.

The marks are in these
  • Each protein migrates until it reaches the region where the pH equals its isoelectric point (pI) β€” the pH at which its net charge is zero β€” and there it stops.
  • The method is self-sharpening: a molecule diffusing either way regains charge and is driven back.
Why it matters

Combined with SDS-PAGE it gives two-dimensional electrophoresis, separating by pI in one dimension and Mr in the other β€” the basis of first-generation proteomics.

Harper's ch.4, p.29 Read the unit β†’
The Edman reaction
+

Phenylisothiocyanate (Edman reagent) derivatises the amino-terminal residue of a peptide as a phenylthiohydantoic acid.

The marks are in these
  • Treatment with acid in a non-hydroxylic solvent then releases a phenylthiohydantoin (PTH) amino acid, identified by its chromatographic mobility, together with a peptide one residue shorter.
  • Because the remaining peptide bonds are untouched, the process can be repeated on the newly exposed N-terminus β€” typically for 5–30 cycles.
Why it matters

The non-hydroxylic solvent is the whole trick: water would let the acid hydrolyse internal peptide bonds and destroy the chain.

Harper's ch.4, pp.29–30 Read the unit β†’
Tandem mass spectrometry (MS–MS)
+

The use of two mass spectrometers linked in series, which allows complex peptide mixtures to be analysed without prior purification.

The marks are in these
  • The first spectrometer separates individual peptides by mass and directs one selected peptide into the second, where it is fragmented and the masses of the fragments determined.
Why it matters

Used clinically to screen newborn blood for amino acids, fatty acids and other metabolites β€” diagnostic of phenylketonuria, ethylmalonic encephalopathy and glutaric acidaemia type 1. This is the biochemistry behind the heel-prick test.

Harper's ch.4, p.33 Read the unit β†’
The proteome
+

The set of all the proteins expressed by an individual cell at a particular time.

The marks are in these
  • Unlike the genome it is not fixed: genes are switched on and off, different cell types express different proteins, expression changes with growth, differentiation and external stimuli, and many proteins are modified post-translationally.
  • It is therefore described as a moving target.
Why it matters

Proteomics aims to identify proteins whose expression correlates with medically significant events. Note the two qualifiers that earn the marks: β€œan individual cell” and β€œat a particular time”.

Harper's ch.4, p.33 Read the unit β†’
Domain β˜… asked 2020–21
+

A section of protein structure that folds independently into a stable conformation, sufficient to perform a particular chemical or physical task β€” such as binding a substrate or interacting with a regulatory molecule.

The marks are in these
  • Different domains work together to provide the complete function of the protein.
  • A small polypeptide such as triose phosphate isomerase or myoglobin may consist of a single domain; protein kinases contain two β€” a Ξ²-sheet-rich amino-terminal domain that binds ATP and an Ξ±-helix-rich carboxyl-terminal domain that binds the substrate.
Why it matters

Set in the 2020/21 paper. Do not confuse with a motif (short conserved region) or with supersecondary structure (10–40 residues, intermediate between secondary and tertiary).

Expected phrasing

All three 2020/21 answer sheets converge on: β€œa section of protein structure that folds independently into a stable conformation. It is sufficient to perform a particular chemical or physical task such as binding of a substrate or other ligand. Different domains work together to provide the complete function.” Reproduce that shape β€” including the last sentence, which most students omit.

Harper's ch.5, pp.40–41 Read the unit β†’
Secondary structure
+

The folding of short (3- to 30-residue), contiguous segments of polypeptide backbone into geometrically ordered units.

The marks are in these
  • It arises when a series of consecutive aminoacyl residues adopt similar Ο† and ψ angles.
  • The two commonest forms are the Ξ±-helix and the Ξ²-pleated sheet, together with bends, turns and loops.
  • Stabilised principally by hydrogen bonds between backbone carbonyl oxygens and amide hydrogens.
Why it matters

Side chains are not involved in forming secondary structure, though they help determine its stability and type. That sentence is worth stating explicitly.

Harper's ch.5, p.36 Β· TMU Lecture 3 Slide 9 Read the unit β†’
The Ξ±-helix
+

A regular secondary structure in which the polypeptide backbone is twisted by an equal amount about each Ξ±-carbon, with Ο† β‰ˆ βˆ’57Β° and ψ β‰ˆ βˆ’47Β°.

The marks are in these
  • A complete turn contains an average of 3.6 residues and rises 0.54 nm (the pitch).
  • The R groups face outward; because proteins contain only L-amino acids, only right-handed Ξ±-helices occur.
  • Stability arises from hydrogen bonds parallel to the helix axis, between the carbonyl oxygen of one peptide bond and the amide hydrogen of the fourth residue down the chain.
Why it matters

Broken by proline (its peptide nitrogen has no hydrogen to donate) and by glycine (too small and flexible).

Harper's ch.5, p.38 Read the unit β†’
Quaternary structure
+

The number and types of polypeptide subunits (protomers) of an oligomeric protein and their spatial arrangement.

The marks are in these
  • Monomeric proteins consist of one chain and have no quaternary structure.
  • Greek letters distinguish subunit types and subscripts their number: Ξ±β‚„ is a homotetramer, Ξ±β‚‚Ξ²β‚‚ (adult haemoglobin) a heterotetramer.
  • Stabilised by the same non-covalent forces as tertiary structure, and sometimes by interchain disulfide bonds.
Why it matters

The single structural difference between myoglobin and haemoglobin β€” and the source of every functional difference between them.

Harper's ch.5, p.41 Read the unit β†’
Motif
+

A short, conserved region of a protein, frequently the most conserved part of a domain and critical to that domain's function β€” in an enzyme it may contain the active site.

The marks are in these
  • The zinc finger: about 30 residues forming an elongated loop held at its base by a single Zn²⁺ ion coordinated to four residues β€” four Cys, or two Cys and two His.
  • Other examples: nuclear localisation sequences, the Rossmann fold that binds NAD(P)H, EF hands that bind Ca²⁺.
Why it matters

Motifs are what bioinformatics algorithms look for β€” find the motif and you have a strong hypothesis about a new protein's function before running any assay.

TMU Lecture 3 Slides 20, 22 Β· Harper's ch.5 Read the unit β†’
Supersecondary structure
+

Combinations of secondary structure, 10–40 residues in length, found recurrently in numerous proteins β€” structurally intermediate between secondary and tertiary structure.

The marks are in these
  • The commonest are combinations of Ξ±-helix and Ξ²-sheet.
  • The helix-loop-helix motif, which provides the oligonucleotide-binding portion of DNA-binding proteins such as repressors and transcription factors, is the standard example.
Why it matters

Distinguish carefully from domain β€” a domain folds independently and performs a task; a supersecondary structure is a recurring structural theme.

Harper's ch.5, p.39 Β· TMU Lecture 3 Slide 20 Read the unit β†’
Molten globule
+

A partially folded polypeptide formed during the second stage of protein folding, when the forces driving hydrophobic regions into the interior away from solvent collapse the chain.

The marks are in these
  • Within it, the modules of secondary structure rearrange until the mature, native conformation is attained.
  • The process is orderly but not rigid β€” considerable flexibility exists in the order in which elements may be rearranged.
Why it matters

It is the answer to the paradox that a polypeptide with β‰₯10⁡⁰ possible conformations folds in milliseconds: folding is modular, not a random search.

Harper's ch.5, pp.44–45 Read the unit β†’
Prion
+

A protein particle that lacks nucleic acid and causes fatal transmissible neurodegenerative disease β€” Creutzfeldt-Jakob disease in humans, scrapie in sheep, bovine spongiform encephalopathy in cattle.

The marks are in these
  • Prion diseases are protein conformation diseases: the pathological isoform PrPSc acts as a template converting the host's normal PrPc β€” monomeric and Ξ±-helix rich β€” into the Ξ²-sheet-rich PrPSc, which aggregates into insoluble, protease-resistant deposits.
  • The amino acid sequence is unchanged; only the conformation differs.
Why it matters

Prion disease can manifest as infectious, genetic or sporadic β€” the reason no viral or bacterial gene could ever be found.

Harper's ch.5, pp.45–46 Read the unit β†’
Conformation (versus configuration)
+

Conformation is the spatial relationship of every atom in a molecule; interconversion between conformers occurs without rupture of covalent bonds, with retention of configuration, typically by rotation about single bonds.

The marks are in these
  • Configuration is the geometric relationship between a given set of atoms β€” for example that which distinguishes L- from D-amino acids β€” and its interconversion requires breaking covalent bonds.
Why it matters

The one-line test: do you have to break a covalent bond to get from one to the other? If yes, configuration. If no, conformation.

Harper's ch.5, p.36 Read the unit β†’
Haem
+

A cyclic tetrapyrrole consisting of four molecules of pyrrole linked by methyne bridges, with one atom of ferrous iron (Fe²⁺) at the centre of the planar ring, bonded to all four pyrrole nitrogens.

The marks are in these
  • The Ξ²-position substituents are methyl, vinyl and propionate.
  • The iron forms six coordination bonds: four to the pyrrole nitrogens, a fifth to the proximal histidine F8, and a sixth reserved for oxygen or left unoccupied.
  • Its network of conjugated double bonds absorbs visible light and colours haem deep red.
Why it matters

Oxidation of Fe²⁺ to Fe³⁺ destroys biological activity β€” the opposite of the cytochromes, where redox cycling of the metal is essential.

Harper's ch.6, p.52 Read the unit β†’
Prosthetic group
+

A small non-protein molecule that forms a permanent part of a protein and is necessary for its function.

The marks are in these
  • Some proteins consist of polypeptide alone; others, such as myoglobin and haemoglobin, require a prosthetic group β€” in their case haem, held in a hydrophobic pocket by non-covalent bonding.
  • In enzymes, prosthetic groups are tightly and stably incorporated by covalent or non-covalent forces; metal ions are the commonest type.
Why it matters

Distinguish from a cofactor (binds reversibly, must be present in the medium) and a coenzyme (a recyclable substrate shuttle).

Harper's ch.7, p.62 Β· TMU Lecture 4 Slide 34 Read the unit β†’
Cooperative binding
+

The phenomenon whereby a molecule of Oβ‚‚ binds to a haemoglobin tetramer more readily if other Oβ‚‚ molecules are already bound.

The marks are in these
  • It permits haemoglobin to maximise both the quantity of Oβ‚‚ loaded at the pOβ‚‚ of the lungs and the quantity released at the pOβ‚‚ of the peripheral tissues.
  • It is the reason the dissociation curve is sigmoid rather than hyperbolic.
Why it matters

Cooperative interactions are an exclusive property of multimeric proteins β€” which is why monomeric myoglobin cannot show cooperativity, a sigmoid curve, or the Bohr effect.

Harper's ch.6, p.55 Read the unit β†’
Pβ‚…β‚€
+

The partial pressure of oxygen at which a given haemoglobin reaches half-saturation β€” a measure of its oxygen affinity.

The marks are in these
  • A high Pβ‚…β‚€ indicates LOW affinity, and therefore better release of oxygen at the tissues. In all instances Pβ‚…β‚€ exceeds the pOβ‚‚ of the peripheral tissues.
  • HbA: 26 mm Hg. HbF: 20 mm Hg.
Why it matters

HbF's lower Pβ‚…β‚€ lets it extract oxygen from maternal HbA across the placenta β€” but the same high affinity limits delivery to the tissues after birth.

Harper's ch.6, p.55 Read the unit β†’
T and R states
+

T (taut) is the low-affinity, deoxygenated conformation of haemoglobin, stabilised by salt bridges between the carboxyl-terminal residues of the four subunits; R (relaxed) is the high-affinity, oxygenated conformation.

The marks are in these
  • The transition is triggered when Oβ‚‚ binding pulls the haem iron into the plane of the ring, moving His F8, rupturing the salt bridges and rotating one Ξ±/Ξ² pair through 15Β°.
  • It does not occur at a fixed number of bound Oβ‚‚ β€” it becomes progressively more probable with each successive oxygen.
Why it matters

The same terms describe the low- and high-affinity conformations of allosteric enzymes (Unit 7). Everything that stabilises T β€” protons, COβ‚‚, chloride, BPG β€” lowers affinity and improves tissue delivery.

Harper's ch.6, pp.55–56 Read the unit β†’
The Bohr effect
+

The reciprocal coupling of proton and oxygen binding by haemoglobin.

The marks are in these
  • In the tissues: COβ‚‚ forms carbonic acid, which dissociates to bicarbonate and protons. Deoxyhaemoglobin binds one proton for every two Oβ‚‚ released, acting as a buffer; the lower pH stabilises the T state and enhances Oβ‚‚ delivery.
  • In the lungs: oxygen uptake releases protons, which combine with bicarbonate to form carbonic acid; carbonic anhydrase dehydrates this to COβ‚‚, which is exhaled. Oxygen binding therefore drives COβ‚‚ exhalation.
  • The protons arise from rupture of salt bridges involving Ξ²-chain His 146.
Why it matters

The effect depends on cooperativity and is therefore absent in myoglobin.

Harper's ch.6, p.56 Read the unit β†’
Haemoglobinopathy
+

A condition in which a mutation in the gene encoding an Ξ± or Ξ² subunit of haemoglobin compromises its biological function.

The marks are in these
  • Of the over 1100 known mutations affecting human haemoglobins, almost all are extremely rare and benign and present no clinical abnormality; the term is reserved for those that impair function.
  • More than 7% of the world's population carry a haemoglobin disorder.
Why it matters

⚠️ Your slide gives β€œover 800” mutations, Harper's β€œover 1100” β€” an edition difference. Quote the lecturer's figure.

Harper's ch.6, p.57 Read the unit β†’
Methaemoglobin
+

Haemoglobin in which the haem iron is ferric (Fe³⁺) rather than ferrous, and which can therefore neither bind nor transport oxygen.

The marks are in these
  • Normally the enzyme methaemoglobin reductase reduces Fe³⁺ back to Fe²⁺.
  • Methaemoglobinaemia arises from oxidation by agents such as sulfonamides, from hereditary haemoglobin M (in which His F8 is replaced by tyrosine, whose phenolate anion stabilises Fe³⁺), or from reduced methaemoglobin reductase activity.
Why it matters

Contrast HbS, where a surface mutation leaves oxygen binding intact but makes the protein sticky, with HbM, where a mutation at the iron-bonded residue abolishes binding outright.

Harper's ch.6, pp.57–58 Read the unit β†’
Enzyme specificity
+

The property whereby an enzyme is specific both for the type of reaction it catalyses and for a single substrate or a small set of closely related substrates.

The marks are in these
  • Enzymes are additionally stereospecific, typically catalysing the reaction of only one stereoisomer β€” D- but not L-sugars, L- but not D-amino acids.
  • Stereospecificity arises from binding at at least three points of attachment, which fixes the substrate's orientation so that apparently identical groups become distinguishable.
Why it matters

Specificity is what allows a cell to conduct and independently control a broad spectrum of biochemical processes simultaneously in the same small volume.

Harper's ch.7, p.61 Read the unit β†’
The active site
+

The three-dimensional catalytic centre of an enzyme β€” a cleft or pocket formed by the residues that bind the substrate and carry out catalysis.

The marks are in these
  • It comprises only a small part of the molecule.
  • The catalytic residues are far apart in the primary structure and are brought together only by the three-dimensional fold.
  • It lies in a cleft or crevice, shielding the substrate from water, and provides a microenvironment whose polarity, hydrophobicity, acidity or alkalinity may differ markedly from the cytoplasm.
Why it matters

A TMU study question asks for the characteristics, not just the definition β€” so give the four points above. The residues being far apart in sequence is the fact most often tested.

Harper's ch.7, pp.62–63 Read the unit β†’
Cofactor
+

A non-protein component that associates reversibly and transiently with the enzyme or with the substrate, and which must therefore be present in the surrounding medium for catalysis to occur.

The marks are in these
  • Most cofactors are metal ions; enzymes requiring one are called metal-activated enzymes, as distinct from the metalloenzymes in which a tightly bound metal serves as a prosthetic group.
Why it matters

The distinction from a prosthetic group is entirely one of tightness of binding.

Harper's ch.7, p.62 Read the unit β†’
Coenzyme
+

A recyclable shuttle that transports substrates from one point within the cell to another.

The marks are in these
  • Its role is twofold: to stabilise reactive species such as hydride ions (NADH) or hydrogen atoms (FADH), which are too reactive to persist freely; and to act as an adaptor or handle facilitating recognition of small groups such as acetate (CoA) or glucose (UDP) by target enzymes.
  • Many are derivatives of B vitamins β€” nicotinamide β†’ NAD⁺/NADP⁺, riboflavin β†’ FMN/FAD, pantothenic acid β†’ coenzyme A, thiamin β†’ thiamin pyrophosphate.
Why it matters

Coenzymes, cofactors and prosthetic groups all exist to extend catalytic capability beyond the limited functional groups of amino acid side chains. ⚠️ Not every enzyme requires one.

Harper's ch.7, p.62 Read the unit β†’
Isozymes (isoenzymes)
+

Distinct enzyme forms that catalyse the SAME reaction, arising through gene duplication.

The marks are in these
  • Although the reaction is identical, their physical, chemical and immunological properties differ significantly β€” which is what allows them to be separated by electrophoresis.
  • Lactate dehydrogenase is a tetramer of H (heart) and M (muscle) subunits, giving five isozymes; LDH-1 predominates in heart, LDH-5 in liver.
Why it matters

Catalysing the same reaction is the only similarity β€” a favourite MCQ. Clinically, the plasma isozyme pattern reveals which organ has been damaged.

Harper's ch.7, pp.66, 69 Read the unit β†’
Induced fit
+

Daniel Koshland's model, which states that when a substrate approaches and binds an enzyme it induces a conformational change β€” analogous to placing a hand (substrate) into a glove (enzyme).

The marks are in these
  • Substrate and enzyme induce mutual conformational changes that facilitate both substrate recognition and catalysis.
  • It replaced Emil Fischer's β€œlock and key” model, which pictured a rigid complementary site and failed to account for the dynamic changes that accompany catalysis.
Why it matters

Not merely a nicer picture: a rigid site could hold a substrate but never distort it, whereas a site that closes around its substrate can strain the bond destined for cleavage.

Harper's ch.7, pp.62–64 Read the unit β†’
Conserved residues
+

Specific amino acids present in the same relative position in every member of a protein family, from which the family's common ancestry can be inferred.

The marks are in these
  • Proteins that diverged from a common ancestor and share a large number of conserved residues are said to be homologous.
  • Among the most highly conserved residues are those that participate directly in catalysis.
Why it matters

Evolution tolerates change almost anywhere except the active site β€” which is why sequence comparison can identify an unknown enzyme's mechanism.

Harper's ch.7, p.66 Read the unit β†’
Ribozyme
+

A catalytic RNA molecule β€” an enzyme that is not a protein.

The marks are in these
  • With the exception of the ribozymes, the vast majority of enzymes are proteins.
Why it matters

This is why the safe formulation is β€œenzymes are mostly protein catalysts”. A statement that all enzymes are proteins is false, and that is a frequent MCQ.

Harper's ch.7, p.60 Β· TMU Lecture 7 Slide 22 Read the unit β†’
Km (the Michaelis constant)
+

The substrate concentration at which the initial velocity is half of the maximal velocity (Vmax/2) attainable at a particular enzyme concentration.

The marks are in these
  • It has the dimensions of substrate concentration, not of rate.
  • It varies inversely with affinity: a low Km means high affinity.
  • It is independent of enzyme concentration (which affects Vmax instead), but is affected by the nature of the enzyme and substrate, by temperature and by pH.
  • A competitive inhibitor raises the apparent Km; a non-competitive inhibitor leaves it unchanged.
Why it matters

Physiologically: hexokinase has a low Km and works even at low blood glucose, whereas hepatic glucokinase has a high Km and acts only after a meal. Same reaction, two Km values, two roles.

Harper's ch.8, p.79 Read the unit β†’
The Michaelis–Menten equation
+

vi = Vmax[S] / (Km + [S]) β€” the mathematical expression of the relationship between the initial reaction velocity and the substrate concentration.

The marks are in these
  • When [S] β‰ͺ Km, vi is directly proportional to [S].
  • When [S] = Km, vi = Vmax/2 β€” which defines Km.
  • When [S] ≫ Km, vi β‰ˆ Vmax and is unaffected by further substrate.
Why it matters

For any fraction f of Vmax, [S] = Km Γ— f/(1βˆ’f). So 80% needs 4 Km, 90% needs 9, and 99% needs 99 β€” which is why Lineweaver–Burk exists.

Harper's ch.8, p.79 Read the unit β†’
Vmax
+

The maximal initial velocity attainable at a given enzyme concentration.

The marks are in these
  • It is reached when the enzyme is saturated β€” when all the enzyme is present as the ES complex and no free enzyme remains available to bind further substrate.
Why it matters

Memorise the phrase β€œno free enzyme remains available”; it is what earns the mark when asked to explain saturation kinetics.

TMU Lecture 6 Slide 18 Β· Harper's ch.8 Read the unit β†’
Competitive inhibition
+

Reversible inhibition in which an inhibitor that typically resembles the substrate structurally binds the active site, blocking access by the substrate.

The marks are in these
  • It acts by decreasing the number of free enzyme molecules available to form ES, and is overcome by raising [S].
  • Kinetics: apparent Km INCREASED, Vmax UNCHANGED. On a double-reciprocal plot the lines converge on the y-axis.
Why it matters

Classic example: malonate inhibiting succinate dehydrogenase β€” it binds the active site but has only one methylene carbon, so it cannot be dehydrogenated. The statins are the clinical example.

Harper's ch.8, p.82 Read the unit β†’
Non-competitive inhibition
+

Reversible inhibition in which the inhibitor bears little or no structural resemblance to the substrate and binds at a site distinct from the substrate-binding site, binding either E or ES.

The marks are in these
  • Because inhibitor binding does not affect substrate binding, Km is unchanged; but the EI complex, while it can still bind substrate, is less efficient at transforming it into product.
  • Kinetics: Km UNCHANGED, Vmax DECREASED. The inhibition cannot be overcome by excess substrate, and the lines converge on the x-axis.
Why it matters

Raising [S] only helps when the problem is access to the site. Here it never was.

Harper's ch.8, pp.82–83 Read the unit β†’
Irreversible inhibition
+

Inhibition in which the inhibitor acts by chemically modifying the enzyme β€” generally by making or breaking covalent bonds with aminoacyl residues essential for substrate binding, catalysis, or maintenance of the enzyme's functional conformation.

The marks are in these
  • Because these covalent changes are relatively stable, an enzyme β€œpoisoned” by a heavy metal atom or an acylating reagent remains inhibited even after the inhibitor is removed from the surrounding medium.
Why it matters

The key contrast with reversible inhibitors, from which fully active enzyme is recovered simply by washing the inhibitor away. Suicide inhibitors are substrate analogues that the enzyme's own machinery converts into an irreversible poison.

Harper's ch.8, p.83 Read the unit β†’
Ki and ICβ‚…β‚€
+

Ki is the equilibrium dissociation constant of the enzyme-inhibitor complex; the lower the Ki, the more effective the inhibitor. ICβ‚…β‚€ is the concentration of inhibitor producing 50% inhibition.

The marks are in these
  • ICβ‚…β‚€ is a less rigorous measure, because unlike an equilibrium constant its numerical value varies with the conditions β€” substrate concentration and so on β€” under which it is determined.
Why it matters

Ki is calculable from the x-intercept of a Lineweaver–Burk plot once Km is known, or from a Dixon plot.

Harper's ch.8, pp.82–83 Read the unit β†’
Catalytic efficiency (kcat/Km)
+

The ratio of the catalytic constant kcat (Vmax divided by the number of active sites) to Km β€” the best measure for comparing different enzymes or different substrates.

The marks are in these
  • A ratio is used because the benefit of a high kcat can only be realised if Km is sufficiently low β€” processing speed is worthless if the enzyme cannot capture substrate at physiological concentrations.
  • Enzymes for which formation of the ES complex is rate-limiting are termed diffusion-limited or β€œcatalytically perfect”.
Why it matters

Related measures: specific activity = Vmax Γ· protein concentration (impure preparations); turnover number = Vmax Γ· moles of enzyme.

Harper's ch.8, p.80 Read the unit β†’
Q₁₀ (temperature coefficient)
+

The factor by which the rate of a biological process increases for a 10 Β°C rise in temperature.

The marks are in these
  • Raising temperature increases both the kinetic energy of molecules β€” so more exceed the activation-energy barrier β€” and the frequency of collisions.
  • This holds only over a limited range: continued heating causes the enzyme to denature, so every enzyme has a temperature optimum.
TMU Lecture 6 Slide 14 Β· Harper's ch.8, p.77 Read the unit β†’
Enzyme kinetics
+

The field of biochemistry concerned with the quantitative measurement of the rates of enzyme-catalysed reactions and the systematic study of the factors that affect those rates.

The marks are in these
  • Enzymes are not changed by the reaction they catalyse; they do not change the equilibrium, and so cannot force an energetically unfavourable reaction; they increase rates by decreasing the activation energy.
TMU Lecture 6 Slide 4 Β· Harper's ch.8 Read the unit β†’
Allosteric regulation β˜… asked 2019
+

Regulation in which a small molecule binds at an allosteric site, spatially distinct from the catalytic site of the target enzyme, to change its intrinsic catalytic efficiency.

The marks are in these
  • Allosteric enzymes are accordingly those whose catalysis at the active site may be modulated by the presence of effectors at an allosteric site.
  • Jacques Monod reasoned that because most feedback inhibitors bear no structural similarity to the substrate, they are not isosteric but allosteric β€” β€œoccupying another space”.
  • K-series enzymes: the inhibitor raises Km without affecting Vmax. V-series: it lowers Vmax without affecting Km.
Why it matters

Set in the 2019 paper. Most feedback inhibition works this way, and many hormones act through allosteric second messengers.

Expected phrasing

The 2019 sheet gives: β€œsmall molecule binds at an allosteric site spatially distinct from the catalytic site of the target enzyme to change in intrinsic catalytic efficiency” β€” which is the TMU slide wording verbatim. Learn that sentence.

Harper's ch.9, p.91 Β· TMU Lecture 7 Slide 8 Read the unit β†’
Covalent regulation β˜… asked 2020–21
+

Regulation of enzyme activity by transferring or removing a chemical group from the enzyme, which triggers a conformational change that alters its catalytic efficiency.

The marks are in these
  • Reversible modifications include phosphorylation (by far the commonest), acetylation, methylation and ADP-ribosylation. Protein kinases transfer the terminal Ξ³-phosphoryl group of ATP to seryl, threonyl or tyrosyl residues; protein phosphatases remove it hydrolytically.
  • Irreversible modification is partial (selective) proteolysis, as in the activation of zymogens.
  • Both are short-term regulation, acting within seconds, unlike induction of protein synthesis which takes hours.
Why it matters

Set in the 2020/21 paper. Note the subtlety: β€œreversible” means the protein can be restored, not that the same reaction runs backwards β€” removal uses a different, separately favourable reaction.

Expected phrasing

Two of the three 2020/21 sheets give, almost identically: β€œtransferring or removing a group from enzymes triggers conformational change that alters catalytic efficiency of enzymes.” Open with that sentence, then add the phosphorylation example.

Harper's ch.9, pp.92–93 Β· TMU Lecture 7 Slide 15 Read the unit β†’
Feedback inhibition
+

The process by which the end product of a multistep biosynthetic pathway binds to and inhibits an enzyme catalysing one of the early steps of that pathway.

The marks are in these
  • In most cases it operates by allosteric regulation.
  • In branched pathways, fine control is achieved by multiple feedback loops, by cooperative feedback inhibition (two end products acting additively or more than additively), or by multiple isoforms each sensitive to a different end product.
Why it matters

⚠️ Distinguish from feedback regulation, a phenomenological term devoid of mechanistic implications. Inhibiting an early step is the point β€” inhibiting the last enzyme would leave intermediates accumulating uselessly.

Harper's ch.9, pp.90–91 Read the unit β†’
Proenzyme (zymogen)
+

The inactive precursor form of an enzyme, converted to the active enzyme by selective (partial) proteolysis.

The marks are in these
  • Proteolysis produces conformational changes that properly configure the active site β€” in chymotrypsin it aligns the Asp102–His57–Ser195 catalytic triad.
  • Examples: pepsinogen β†’ pepsin, trypsinogen β†’ trypsin, chymotrypsinogen β†’ chymotrypsin, proinsulin β†’ insulin, procollagen β†’ collagen, and the clotting and complement factors.
  • Physiologically irreversible, because cells cannot reunite the two portions of a protein produced by hydrolysis of a peptide bond.
Why it matters

Three reasons cells use them: protection of the tissue of origin from autodigestion (pancreatitis); rapid mobilisation on demand, since synthesis would be far too slow to respond to blood loss; and economy.

Harper's ch.9, pp.92–93 Read the unit β†’
Constitutive enzyme
+

An enzyme whose concentration remains essentially constant over time.

The marks are in these
  • By contrast, the concentrations of many enzymes depend on the presence of inducers β€” typically substrates or structurally related compounds β€” that initiate their synthesis.
Why it matters

Induction of protein synthesis requires hours, so changes in enzyme level serve long-term adaptive requirements rather than rapid change.

Harper's ch.9, pp.89–90 Read the unit β†’
Rate-limiting step
+

The slowest reaction of a metabolic pathway β€” the β€œbottleneck” β€” whose enzyme acts as the natural β€œgovernor” of metabolic flux.

The marks are in these
  • Decreasing the quantity or catalytic efficiency of that enzyme immediately reduces flux through the entire pathway; increasing either enhances it.
Why it matters

Such enzymes are efficient drug targets: the statins inhibit HMG-CoA reductase, the rate-limiting enzyme of cholesterogenesis. Acetyl-CoA carboxylase plays the same role in fatty acid synthesis.

Harper's ch.9, p.89 Read the unit β†’
Ubiquitination
+

The covalent attachment of one or more molecules of ubiquitin β€” a small, approximately 8.5 kDa protein, highly conserved among eukaryotes β€” to the side-chain amino groups of lysyl residues, catalysed by a large family of E3 ligases.

The marks are in these
  • It targets proteins to the interior of the 26S proteasome, a complex of more than 30 subunits forming a hollow cylinder whose proteolytic active sites face inward, preventing indiscriminate degradation.
Why it matters

Degrades both regulated proteins (the cyclins) and proteins damaged by loss of a prosthetic group or oxidation of residues. Its dysfunction contributes to the misfolded-protein accumulation of several neurodegenerative diseases.

Harper's ch.9, p.90 Read the unit β†’
Second messenger
+

An intracellular signalling molecule generated in response to an extracellular signal, which regulates enzymes allosterically.

The marks are in these
  • Examples include cAMP, 3β€²,5β€²-cGMP, Ca²⁺, nitric oxide and the polyphosphoinositols produced by hormone-regulated phospholipases.
Why it matters

The kinases and phosphatases responding to these signals constitute a β€œbio-organic computer” that integrates complex environmental information into a coherent cellular response.

Harper's ch.9, pp.91–92 Read the unit β†’
Homeostasis
+

The maintenance of a relatively constant intracellular and intra-organ environment despite wide fluctuations in the external environment, achieved by appropriate changes in the rates of biochemical reactions in response to physiological need.

The marks are in these
  • Achieved passively, because substrate concentrations sit near Km where the curve is steepest, so flux tracks [S] automatically;
  • and actively, by changing the quantity (hours) or catalytic efficiency (seconds) of the enzyme catalysing the committed, rate-limiting reaction.
Why it matters

A TMU study question asks β€œhow is this achieved?” β€” give both the passive and the active levels, and name the two timescales.

Harper's ch.9, p.87 Read the unit β†’
⚑ Bioenergetics & Carbohydrates24 terms Β· Units 8–14
Bioenergetics
+

The study of the energy changes accompanying biochemical reactions.

The marks are in these
  • Biological systems are essentially isothermic and therefore use chemical energy, not heat, to power living processes β€” there is no temperature gradient to exploit, so energy must be moved around chemically.
Why it matters

This constraint is why a carrier molecule such as ATP has to exist at all.

Harper's ch.11, p.113 Read the unit β†’
Free energy (Ξ”G)
+

That portion of the total energy change in a system that is available for doing work β€” the useful energy, or chemical potential.

The marks are in these
  • Ξ”G = Ξ”H βˆ’ TΞ”S, combining the two laws of thermodynamics.
  • Negative Ξ”G = EXERGONIC: proceeds spontaneously; if large, essentially irreversible. Positive = ENDERGONIC: needs energy supplied. Zero = equilibrium.
  • Ξ”G⁰′ is the standard free-energy change at pH 7.0, related to the equilibrium constant by Ξ”G⁰′ = βˆ’RT ln Kβ€²eq.
Why it matters

The sign rules govern every later pathway β€” they are what makes three steps of glycolysis irreversible and therefore regulable.

Harper's ch.11, p.114 Read the unit β†’
High-energy phosphate
+

A phosphate compound whose standard free energy of hydrolysis is greater than that of ATP (βˆ’30.5 kJ/mol).

The marks are in these
  • The group comprises anhydrides (1,3-bisphosphoglycerate), enolphosphates (phosphoenolpyruvate) and phosphoguanidines (creatine phosphate, arginine phosphate).
  • Low-energy phosphates β€” the ester phosphates of the glycolytic intermediates β€” fall below ATP.
  • The symbol ~β„— denotes that transfer of the group yields the larger quantity of free energy; β€œgroup transfer potential” is preferred to β€œhigh-energy bond”.
Why it matters

ATP's intermediate position is the whole point: it can be regenerated by the compounds above it and can phosphorylate everything below.

Harper's ch.11, pp.115–116 Read the unit β†’
The ATP/ADP cycle
+

The continuous consumption and regeneration of ATP that connects those processes which generate high-energy phosphate to those which utilise it.

The marks are in these
  • It turns over very rapidly, because the total ATP/ADP pool is sufficient to maintain an active tissue for only a few seconds.
  • The three sources of ~β„—: oxidative phosphorylation (the greatest quantitative source), glycolysis (net 2, at phosphoglycerate kinase and pyruvate kinase) and the citric acid cycle (1, at succinate thiokinase).
Why it matters

ATP is not a store of energy but a flow β€” made continuously at the rate it is spent, which is why interrupting the respiratory chain kills within minutes.

Harper's ch.11, p.116 Read the unit β†’
Phosphagen
+

A storage form of high-energy phosphate β€” creatine phosphate in vertebrate skeletal muscle, heart, spermatozoa and brain, and arginine phosphate in invertebrate muscle.

The marks are in these
  • Phosphagens permit ATP concentration to be maintained when it is rapidly utilised, and accumulate when the ATP/ADP ratio is high.
Why it matters

Creatine phosphate lies above ATP in the free-energy table (βˆ’43.1 kJ/mol), which is precisely what lets it rephosphorylate ADP instantly.

Harper's ch.11, p.117 Read the unit β†’
Oxidative phosphorylation β˜… asked 2019 Β· 2020–21
+

The system in mitochondria that couples respiration to the generation of the high-energy intermediate, ATP.

The marks are in these
  • Electrons pass down the respiratory chain in the inner mitochondrial membrane to their final reaction with oxygen to form water.
  • The free energy released is used by Complexes I, III and IV, acting as proton pumps, to translocate H⁺ into the intermembrane space.
  • The resulting proton motive force drives ATP synthase to phosphorylate ADP.
Why it matters

⭐ Set in BOTH readable papers β€” one of only two terms proven to repeat. It is also the greatest quantitative source of high-energy phosphate in aerobic organisms.

Expected phrasing

The 2019 sheet gives: β€œthe system in mitochondria that couples respiration to the generation of the high-energy intermediate, ATP.” Open with that sentence, then add the mechanism.

Harper's ch.13, pp.130–131 Read the unit β†’
The chemiosmotic theory
+

Peter Mitchell's theory (1961) that the energy from oxidation in the respiratory chain is coupled to the translocation of protons from the inside to the outside of the inner mitochondrial membrane.

The marks are in these
  • The resulting proton motive force β€” an electrochemical potential difference, negative on the matrix side β€” drives ATP synthesis.
  • Complexes I, III and IV act as proton pumps; because the inner membrane is impermeable to protons, they accumulate in the intermembrane space.
Why it matters

The insight was that there is no chemical intermediate linking oxidation to phosphorylation β€” the link is a gradient. It explains uncouplers, oligomycin and respiratory control in one idea.

Harper's ch.13, p.130 Read the unit β†’
Uncoupler of oxidative phosphorylation
+

A compound that dissociates oxidation in the respiratory chain from phosphorylation, by allowing leakage of H⁺ across the inner membrane and so collapsing the electrochemical proton gradient.

The marks are in these
  • Uncouplers are toxic in vivo, causing respiration to become uncontrolled, since its rate is no longer limited by ADP or Pi; the energy is released as heat. The commonest is 2,4-dinitrophenol (DNP).
Why it matters

Contrast oligomycin, which blocks H⁺ conduction through Fβ‚€ and therefore stops both oxidation and phosphorylation. Uncoupler: oxidation accelerates. Oligomycin: both stop.

Harper's ch.13, pp.132–133 Read the unit β†’
Respiratory control
+

Control of the rate of mitochondrial respiration by the availability of ADP.

The marks are in these
  • It arises because oxidation and phosphorylation are tightly coupled: oxidation cannot proceed without concomitant phosphorylation of ADP.
  • Most cells at rest are in state 4, ADP-limited.
Why it matters

The regulator is the substrate itself β€” demand automatically creates its own supply signal, with no allosteric machinery required.

Harper's ch.13, pp.131–132 Read the unit β†’
P:O ratio TMU term
+

The number of moles of inorganic phosphate incorporated into ATP per half-mole of oxygen consumed β€” that is, per pair of electrons.

The marks are in these
  • ⚠️ Your sources disagree. Lecture 9 slide 16 gives 3 (NADH) and 2 (FADHβ‚‚). Harper's p.131 gives 2.5 and 1.5.
  • The rest of your course agrees with Harper's: Lecture 10 slide 13 states 2.5 and 1.5 explicitly; Lecture 11 slide 36 gives 32 ATP per glucose, only possible with those values; and Lecture 9 slide 27 itself concedes β€œpossibly 2.5”.
  • The values are non-integer because 10 H⁺ pumped per NADH Γ· about 4 H⁺ per ATP exported does not divide evenly.
Why it matters

Use 2.5 and 1.5. They match Harper's, the majority of your slides, and the 10-per-turn and 32-per-glucose figures. Explain with the proton count β€” worth more than either pair of numbers.

Harper's ch.13, p.131 vs TMU Lecture 9 Slides 16, 27 Read the unit β†’
Glycolysis β˜… asked 2019
+

The major pathway for glucose metabolism, which occurs in the cytosol of all cells. It is unique in that it can function either aerobically or anaerobically.

The marks are in these
  • Overall anaerobic equation: glucose + 2 ADP + 2 Pi β†’ 2 lactate + 2 ATP + 2 Hβ‚‚O.
  • Regulated at three markedly exergonic, physiologically irreversible steps β€” hexokinase (and glucokinase), phosphofructokinase and pyruvate kinase.
  • It is also the main pathway for the metabolism of fructose, galactose and other dietary carbohydrates.
Why it matters

Net 2 ATP anaerobically, up to 32 aerobically. Erythrocytes rely on it entirely, which is why glycolytic enzyme defects present as haemolytic anaemia.

Expected phrasing

The 2019 sheet gives: β€œthe major initial pathway for glucose metabolism, occurs in the cytosol of all cells.” Open with almost exactly that.

Harper's ch.17, p.168 Read the unit β†’
Hexokinase and glucokinase
+

Both phosphorylate glucose to glucose 6-phosphate using ATP, but differ in Km and in distribution.

The marks are in these
  • Hexokinase β€” most tissues, high affinity (low Km), so saturated even at low blood glucose.
  • Glucokinase β€” liver and pancreatic Ξ² islet cells, Km very much higher, so active only when glucose is high.
  • In liver it removes glucose from the blood after a meal, providing G6P in excess of glycolytic needs for glycogen synthesis and lipogenesis. In pancreas, the G6P formed signals glucose availability and leads to insulin secretion.
Why it matters

The clearest demonstration in the course that Km is not an abstraction β€” same reaction, two values, two physiological roles.

Harper's ch.17, p.170 Read the unit β†’
The pyruvate dehydrogenase complex
+

The multienzyme complex catalysing the oxidative decarboxylation of pyruvate to acetyl-CoA β€” the irreversible route from glycolysis to the citric acid cycle.

The marks are in these
  • Three catalytic enzymes: pyruvate dehydrogenase, dihydrolipoamide transacetylase, dihydrolipoamide dehydrogenase.
  • Five cofactors: TPP, lipoic acid, NAD⁺, FAD and CoASH β€” four of them B-vitamin derived.
  • Regulated by end-product inhibition (acetyl-CoA, NADH) and by covalent modification β€” phosphorylation of three serine residues inactivates; the dephosphorylated form is active.
Why it matters

Its irreversibility is why fat cannot be converted to glucose. Its inhibition during starvation spares carbohydrate for the brain.

Harper's ch.17, p.173 Read the unit β†’
The citric acid cycle
+

A series of reactions in mitochondria that oxidise acetyl residues (as acetyl-CoA) and reduce coenzymes that, upon reoxidation, are linked to the formation of ATP.

The marks are in these
  • It is the final common pathway for the aerobic oxidation of carbohydrate, lipid and protein, because glucose, fatty acids and most amino acids are metabolised to acetyl-CoA or to cycle intermediates.
  • Located in the mitochondrial matrix. Acetyl-CoA condenses with oxaloacetate to form citrate; two COβ‚‚ are released and oxaloacetate is regenerated, so it plays a catalytic role.
  • One turn yields 10 ATP: 3 NADH Γ— 2.5, 1 FADHβ‚‚ Γ— 1.5, and 1 substrate-level ATP at succinate thiokinase.
Why it matters

⭐ Its significance in the metabolism of carbohydrate, triacylglycerol and amino acids was a Section II question in both readable papers.

Harper's ch.16, p.161 Β· TMU Lecture 10 Slide 3 Read the unit β†’
Amphibolic
+

Functioning in both oxidative (catabolic) and synthetic (anabolic) processes.

The marks are in these
  • The citric acid cycle is not only a pathway for oxidation of two-carbon units; it is also a major pathway for the interconversion of metabolites arising from transamination and deamination, and it provides substrates for amino acid synthesis, gluconeogenesis and fatty acid synthesis.
Why it matters

The exit to gluconeogenesis is PEP carboxykinase (using GTP); the exit to lipogenesis is citrate, cleaved in the cytosol by ATP-citrate lyase.

Harper's ch.16, p.164 Read the unit β†’
Anaplerotic reaction
+

A reaction producing net transfer of metabolites INTO the citric acid cycle, replenishing its intermediates.

The marks are in these
  • The most important is the carboxylation of pyruvate to oxaloacetate by pyruvate carboxylase, maintaining an adequate concentration of oxaloacetate for condensation with acetyl-CoA.
  • If acetyl-CoA accumulates it acts BOTH as an allosteric activator of pyruvate carboxylase AND as an inhibitor of pyruvate dehydrogenase β€” ensuring its own supply of oxaloacetate.
Why it matters

This is the mechanism behind β€œfat burns in the flame of carbohydrate”, and therefore behind starvation ketosis.

Harper's ch.16, pp.164–165 Read the unit β†’
Glycogen
+

The major storage carbohydrate in animals, corresponding to starch in plants; a branched polymer of Ξ±-D-glucose.

The marks are in these
  • Liver: up to 6%. Muscle: rarely over 1% β€” but because of its greater mass, muscle contains three to four times as much in total.
  • Muscle glycogen supplies glycolysis within the muscle itself; liver glycogen stores and exports glucose to maintain blood glucose, and is almost totally depleted after 12–18 hours of fasting.
Why it matters

The difference is one enzyme: glucose-6-phosphatase is present in liver and kidney but not muscle, so only the liver can release free glucose to the blood.

Harper's ch.18, p.176 Read the unit β†’
Glycogenolysis
+

The breakdown of glycogen β€” not the reverse of glycogenesis, but a separate pathway.

The marks are in these
  • Glycogen phosphorylase catalyses the rate-limiting step, the phosphorolytic cleavage by inorganic phosphate of the 1β†’4 linkages to yield glucose 1-phosphate.
  • Residues are removed until about four remain on either side of a 1β†’6 branch; a transferase moves a trisaccharide to expose the branch point, and debranching enzyme hydrolyses the 1β†’6 linkage.
  • In liver and kidney only, glucose-6-phosphatase then yields free glucose for export.
Why it matters

Phosphorolysis, not hydrolysis β€” the product is already phosphorylated, saving the ATP hexokinase would otherwise spend.

Harper's ch.18, pp.177–178 Read the unit β†’
Glycogen storage disease
+

One of a group of inherited disorders characterised by deficient mobilisation of glycogen or deposition of abnormal forms of glycogen, leading to muscular weakness or even death.

The marks are in these
  • Von Gierke's disease (type I) β€” glucose-6-phosphatase deficiency: hepatic glycogen accumulates but cannot be exported, causing fasting hypoglycaemia.
  • McArdle's syndrome (type V) β€” muscle glycogen phosphorylase deficiency: exercise intolerance and cramps, with no rise in blood lactate.
Why it matters

Two diseases, two tissues, two purposes β€” derivable from the liver/muscle distinction rather than memorised.

Harper's ch.18, pp.176, 179 Read the unit β†’
Gluconeogenesis
+

The term used to include all pathways responsible for converting non-carbohydrate precursors to glucose or glycogen.

The marks are in these
  • Major substrates: the glucogenic amino acids, lactate, glycerol and propionate. Major tissues: liver and kidney.
  • It uses the reversible glycolytic reactions plus four bypass enzymes that circumvent the three irreversible steps: pyruvate carboxylase (mitochondrial, ATP, biotin) and PEP carboxykinase (GTP); fructose 1,6-bisphosphatase; and glucose-6-phosphatase.
  • It clears lactate produced by muscle and erythrocytes and glycerol produced by adipose tissue.
Why it matters

Acetyl-CoA is not a substrate β€” pyruvate dehydrogenase is irreversible, which is why fat cannot be converted to glucose and starvation eventually consumes muscle protein.

TMU Lecture 12b Slide 3 Β· Harper's ch.19, pp.184–186 Read the unit β†’
Fructose 2,6-bisphosphate
+

The most potent positive allosteric effector of phosphofructokinase-1 and inhibitor of fructose-1,6-bisphosphatase in liver β€” one molecule with opposite effects on the key enzymes of glycolysis and gluconeogenesis.

The marks are in these
  • It is formed by phosphorylation of fructose 6-phosphate by phosphofructokinase-2; the same enzyme protein is also responsible for its breakdown, since it has fructose-2,6-bisphosphatase activity β€” a bifunctional enzyme.
  • Which activity dominates is set by cAMP-dependent phosphorylation, so glucagon lowers it and switches the liver to gluconeogenesis.
Why it matters

⚠️ It is a regulatory signal only, NOT a pathway intermediate β€” unlike fructose 1,6-bisphosphate. Examiners set this confusion deliberately.

Harper's ch.19, pp.188–189 Read the unit β†’
The Cori cycle
+

The cycle in which lactate produced by anaerobic glycolysis in muscle and erythrocytes is carried to the liver, reconverted to glucose by gluconeogenesis, and returned to the muscle.

The marks are in these
  • It is energetically expensive for the liver, which must supply the ATP and GTP.
Why it matters

The resulting rise in oxygen consumption is the oxygen debt after exercise, and the same mechanism underlies the hypermetabolism of cancer cachexia.

Harper's ch.19, p.191 Read the unit β†’
The pentose phosphate pathway
+

An alternative route for the metabolism of glucose which does not generate ATP but has two major functions: the formation of NADPH for the synthesis of fatty acids and steroids, and the synthesis of ribose for nucleotide and nucleic acid formation.

The marks are in these
  • Cytosolic. Oxidation is by dehydrogenation, but NADP⁺ and not NAD⁺ is the hydrogen acceptor, and COβ‚‚ β€” not produced in glycolysis at all β€” is a characteristic product.
  • An oxidative, non-reversible phase (G6PD, gluconolactone hydrolase, 6-phosphogluconate dehydrogenase β†’ 2 NADPH + COβ‚‚ + ribulose 5-phosphate) and a non-oxidative, reversible phase (mainly transketolase and transaldolase).
  • It is called a shunt because it begins at glucose 6-phosphate and rejoins glycolysis at glyceraldehyde 3-phosphate and fructose 6-phosphate.
Why it matters

Three ways to recognise it in a question: NADP appears Β· COβ‚‚ appears Β· no ATP appears.

TMU β€œChapter 20” Slides 2, 4, 10 Β· Harper's ch.20 Read the unit β†’
Glucose-6-phosphate dehydrogenase deficiency
+

Genetic deficiency of the first enzyme of the pentose phosphate pathway β€” a major cause of haemolysis of red blood cells, resulting in haemolytic anaemia and affecting approximately 100 million people worldwide.

The marks are in these
  • Mechanism: no G6PD β†’ no NADPH β†’ glutathione reductase (an FAD flavoprotein) cannot regenerate reduced glutathione β†’ glutathione peroxidase (which contains selenocysteine at its active site) cannot remove Hβ‚‚Oβ‚‚ β†’ oxidative damage to the cell membrane β†’ haemolysis.
  • The erythrocyte is uniquely vulnerable because it has no other source of NADPH and no nucleus with which to make more enzyme.
Why it matters

This is what Unit 1's β€œ21st amino acid” is actually for β€” and why selenium is a dietary trace element.

TMU β€œChapter 20” Slides 8, 16 Read the unit β†’
🫧 Lipid Metabolism19 terms Β· Units 15–19
Lipids
+

A heterogeneous group of compounds related more by their physical than by their chemical properties β€” they are relatively insoluble in water but soluble in nonpolar solvents such as ether and chloroform.

The marks are in these
  • Classification: simple lipids (fats and waxes β€” esters of fatty acids with alcohols); complex lipids (phospholipids, glycolipids β€” esters containing an additional group); precursor and derived lipids (fatty acids, glycerol, steroids, ketone bodies, fat-soluble vitamins, hormones).
  • Functions: the most concentrated form of energy storage (9 kcal/g against 4 for carbohydrate and protein); structural components of membranes; thermal insulation and mechanical protection; carriers of the fat-soluble vitamins A, D, E and K; and precursors of steroid hormones and eicosanoids.
Why it matters

The definition is a solubility definition, not a structural one β€” that is the point examiners look for. Say β€œrelated by physical rather than chemical properties” and the first mark is yours.

Harper's ch.21, p.211 Read the unit β†’
Essential fatty acids
+

Fatty acids that cannot be synthesised in the body and must be supplied in the diet β€” linoleic acid (Ο‰-6) and Ξ±-linolenic acid (Ο‰-3).

The marks are in these
  • Mammals possess Ξ”9, Ξ”6, Ξ”5 and Ξ”4 desaturases but no desaturase beyond carbon 9, so they cannot introduce a double bond in the Ο‰-6 or Ο‰-3 position.
  • Arachidonic acid can be made from linoleic acid and is therefore essential only when linoleic acid is lacking. It is the precursor of the eicosanoids.
  • Deficiency causes a scaly dermatitis with increased water loss through the skin, impaired growth and impaired wound healing.
Why it matters

The dietary requirement at one end of the chain determines the availability of prostaglandins, thromboxanes and leukotrienes at the other.

Harper's ch.23, pp.244–245 Read the unit β†’
Eicosanoids
+

Short-lived local signalling molecules derived from 20-carbon polyunsaturated fatty acids, chiefly arachidonic acid. The name is from the Greek eikosi, twenty.

The marks are in these
  • Three classes: prostaglandins (PG), which have a cyclopentane ring; thromboxanes (TX), in which that ring contains an oxygen atom; and leukotrienes (LT), which have no ring but three conjugated double bonds.
  • Two routes from arachidonic acid: the cyclooxygenase pathway gives prostaglandins and thromboxanes, the lipoxygenase pathway gives leukotrienes.
  • Actions: PGs mediate inflammation, pain and fever and protect the gastric mucosa; TXAβ‚‚ causes platelet aggregation and vasoconstriction, PGIβ‚‚ (prostacyclin) does the opposite; leukotrienes cause bronchoconstriction and are important in asthma.
Why it matters

The pathway is the pharmacology. Aspirin and NSAIDs inhibit cyclooxygenase β€” which is why they are both anti-inflammatory and ulcerogenic; low-dose aspirin is antiplatelet through TXAβ‚‚; leukotriene antagonists treat asthma.

Harper's ch.21, pp.213–215 Β· Harper's ch.23 Read the unit β†’
Amphipathic lipids
+

Lipids possessing both a polar (hydrophilic) and a nonpolar (hydrophobic) region in the same molecule β€” for example phospholipids, sphingolipids, bile salts and cholesterol.

The marks are in these
  • In an aqueous environment they orient themselves so that the polar groups face the water and the hydrocarbon chains face each other, forming bilayers, micelles, liposomes and the surface monolayer of lipoproteins.
  • This single property underlies the structure of every biological membrane, the emulsifying action of bile salts, and the solubility of lipoproteins in plasma.
Why it matters

One physical principle explains membranes, fat digestion and lipid transport at once β€” worth naming explicitly in any of those three answers.

Harper's ch.21, pp.220–221 Read the unit β†’
Lipogenesis
+

The de novo synthesis of long-chain fatty acids from acetyl-CoA, occurring in the cytosol of the liver, adipose tissue and lactating mammary gland.

The marks are in these
  • Acetyl-CoA is the immediate substrate and free palmitate is the end product. Reducing equivalents are supplied as NADPH, chiefly from the pentose phosphate pathway; the acyl carrier is acyl carrier protein (ACP).
  • Overall: acetyl-CoA + 7 malonyl-CoA + 14 NADPH + 14 H⁺ β†’ palmitate + 7 COβ‚‚ + 6 Hβ‚‚O + 8 CoA-SH + 14 NADP⁺.
  • Acetyl-CoA reaches the cytosol as citrate, cleaved there by ATP-citrate lyase β€” the citrate shuttle.
Why it matters

Note that the tissues with active lipogenesis are exactly those with an active pentose phosphate pathway, and that both pathways are cytosolic so NADPH passes freely between them.

Harper's ch.23, pp.232–234 Read the unit β†’
Acetyl-CoA carboxylase
+

The enzyme catalysing the carboxylation of acetyl-CoA to malonyl-CoA β€” the initial and controlling step in fatty acid synthesis.

The marks are in these
  • It requires bicarbonate as the source of COβ‚‚, ATP, and the B vitamin biotin, and acts in two steps: carboxylation of biotin involving ATP, then transfer of the carboxyl group to acetyl-CoA.
  • Activated allosterically by citrate, which converts the inactive dimer into an active polymeric form of several million daltons; citrate rises in the well-fed state and is an indicator of a plentiful supply of acetyl-CoA.
  • Inhibited by phosphorylation (glucagon, epinephrine) and by long-chain acyl-CoA β€” negative feedback by a product of the pathway.
Why it matters

Malonyl-CoA is also the inhibitor of carnitine palmitoyltransferase-I, so this one enzyme reciprocally regulates fatty acid synthesis and oxidation across two compartments.

Harper's ch.23, pp.233, 237 Read the unit β†’
Fatty acid synthase
+

The multienzyme polypeptide complex in which the individual enzymes of fatty acid synthesis are linked, incorporating the acyl carrier protein (ACP).

The marks are in these
  • It is a homodimer of two identical subunits, each containing six enzymes and an ACP, arranged in an X shape. ACP contains the vitamin pantothenic acid as 4β€²-phosphopantetheine and has a function similar to CoA in Ξ²-oxidation.
  • Two advantages of the multienzyme arrangement: it achieves the effect of compartmentalisation without the erection of permeability barriers, since the intermediates never leave the complex; and synthesis of all the enzymes is coordinated, being encoded by a single gene.
  • The priming acetyl-CoA forms carbons 15 and 16 of palmitate; all subsequent Cβ‚‚ units come from malonyl-CoA. Thioesterase releases free palmitate.
Why it matters

Propionyl-CoA primes the synthesis of odd-chain fatty acids, found particularly in ruminant fat and milk.

Harper's ch.23, pp.233–234 Read the unit β†’
Ξ²-Oxidation
+

The pathway by which fatty acids are degraded two carbons at a time in the mitochondrial matrix, so named because oxidation occurs at the Ξ²-carbon.

The marks are in these
  • The fatty acid is first activated to acyl-CoA by acyl-CoA synthetase at the cost of two high-energy phosphates (ATP β†’ AMP + PPi), then carried into the matrix by the carnitine shuttle.
  • Each cycle comprises oxidation (FAD) β†’ hydration β†’ oxidation (NAD⁺) β†’ thiolytic cleavage, yielding one acetyl-CoA, one FADHβ‚‚, one NADH and an acyl-CoA two carbons shorter β€” 4 ATP per cycle from the reducing equivalents alone.
  • Complete oxidation of palmitate yields 106 ATP net (7 cycles: 7 FADHβ‚‚ + 7 NADH + 8 acetyl-CoA, less 2 for activation).
  • Odd-chain acids end with propionyl-CoA, converted via methylmalonyl-CoA (biotin) to succinyl-CoA (vitamin B₁₂).
Why it matters

Fatty acids are not glucogenic, because pyruvate dehydrogenase is irreversible β€” the propionyl-CoA of odd-chain acids is the sole exception. A frequently examined negative fact.

Harper's ch.22, pp.226–228 Β· TMU Lecture 15 p.23 Read the unit β†’
The carnitine shuttle
+

The transport system carrying long-chain acyl groups across the inner mitochondrial membrane, which acyl-CoA cannot itself penetrate.

The marks are in these
  • Carnitine (Ξ²-hydroxy-Ξ³-trimethylammonium butyrate) is widely distributed and particularly abundant in muscle.
  • Three components in sequence: CPT-I on the outer membrane forms acylcarnitine; the carnitine-acylcarnitine translocase exchanges it inwards for free carnitine; CPT-II on the inner surface regenerates acyl-CoA in the matrix. Carnitine is returned, so it is a catalytic carrier, not a consumed substrate.
  • CPT-I is the rate-limiting step of fatty acid oxidation and is inhibited by malonyl-CoA.
  • Carnitine deficiency causes hypoglycemia, hypoketonemia, and lipid accumulation with muscular weakness; it responds to oral carnitine.
Why it matters

Do not confuse it with the citrate shuttle, which carries acetyl units OUT for fatty acid synthesis. Carnitine carries acyl groups IN.

Harper's ch.22, pp.227, 229–230 Read the unit β†’
Ketone bodies
+

The collective term for acetoacetate, D-3-hydroxybutyrate and acetone, water-soluble products of acetyl-CoA formed in the mitochondria of the liver when fatty acid oxidation is rapid.

The marks are in these
  • The liver is the only organ that adds significant quantities of ketone bodies to the blood; extrahepatic tissues consume them. The liver cannot use them, because it lacks succinyl-CoA-acetoacetate CoA transferase.
  • 3-hydroxybutyrate is quantitatively predominant in blood and urine in ketosis; the acetoacetate/3-hydroxybutyrate ratio depends on the mitochondrial [NAD⁺]/[NADH] ratio. Acetone is not metabolised and is exhaled, giving the ketotic breath.
  • They are normal fuels of respiration, important for heart muscle and renal cortex, and cross the blood-brain barrier, which albumin-bound free fatty acids cannot β€” so the brain uses them in prolonged starvation, sparing body protein.
  • Formation: 2 acetyl-CoA β†’ acetoacetyl-CoA β†’ (HMG-CoA synthase, the regulatory enzyme) β†’ HMG-CoA β†’ (HMG-CoA lyase) β†’ acetoacetate.
Why it matters

Ketogenesis is the overflow route for acetyl-CoA the citric acid cycle cannot accept, because oxaloacetate has been drawn into gluconeogenesis β€” β€œfat burns in the flame of carbohydrate.”

Expected phrasing

Set as a Section II question in the 2019 paper: β€œWhat are ketone bodies? Try to describe their metabolic properties.” Lead with the three names and the hepatic origin.

Harper's ch.22, pp.229–231 Read the unit β†’
Ketosis
+

The condition in which the rate of ketone body synthesis exceeds the capacity of extrahepatic tissues to oxidise them, so that they accumulate in the blood.

The marks are in these
  • It manifests as ketonemia, ketonuria and a ketotic (acetone) breath.
  • Mild ketosis occurs normally in starvation, after exercise and in pregnancy; it is severe in diabetes mellitus, where insulin lack removes the restraint on lipolysis. Since acetoacetate and 3-hydroxybutyrate are relatively strong acids, the result is ketoacidosis.
  • In ruminants it is a serious problem in lactating cattle and pregnant ewes.
Why it matters

Ketosis is a matter of rate, not of a defective pathway β€” state that and the definition is already half made.

Harper's ch.22, pp.230–231 Read the unit β†’
Lipoproteins β˜… asked 2020/21
+

Macromolecular complexes of lipid and protein that transport water-insoluble lipids in the blood plasma.

The marks are in these
  • Structure: a nonpolar core of triacylglycerol and cholesteryl ester, surrounded by a surface monolayer of amphipathic phospholipid, free cholesterol and apolipoprotein, polar faces outward to the plasma.
  • Four major classes, in order of increasing density and decreasing size: chylomicrons (intestine; dietary triacylglycerol; apo B-48); VLDL (liver; endogenous triacylglycerol; apo B-100); LDL (from VLDL; cholesterol-rich; delivers cholesterol to tissues); HDL (reverse cholesterol transport; apo A-I; highest protein content, about 50%).
  • Since protein is denser than lipid, the more lipid a particle carries the larger and the less dense it is β€” density and diameter run in opposite directions.
Why it matters

LDL correlates positively and HDL inversely with the incidence of atherosclerosis, because the two carry cholesterol in opposite directions.

Harper's ch.25, pp.254–255 Read the unit β†’
Apolipoproteins β˜… asked 2019
+

The protein moieties of the plasma lipoproteins, situated in the amphipathic surface monolayer.

The marks are in these
  • Three functions: structural β€” they hold the particle together and confer solubility; enzyme cofactors; and ligands for cell-surface receptors, determining where the particle is delivered.
  • apo B-100 β€” liver; VLDL, IDL, LDL; the ligand for the LDL receptor. apo B-48 β€” intestine; chylomicrons; 48% of the length of B-100, from the same gene by RNA editing, and lacking the receptor-binding domain.
  • apo A-I β€” HDL; activates LCAT. apo C-II β€” activates lipoprotein lipase. apo E β€” mediates hepatic uptake of chylomicron remnants and IDL.
Why it matters

Because apo B-48 lacks the receptor-binding domain, chylomicron remnants must be cleared through apo E instead β€” the two facts belong together in an answer.

Harper's ch.25, pp.255–258 Read the unit β†’
Lipoprotein lipase
+

The enzyme on the capillary endothelium of extrahepatic tissues β€” chiefly adipose tissue, heart and skeletal muscle β€” which hydrolyses the triacylglycerol of chylomicrons and VLDL, releasing fatty acids for uptake.

The marks are in these
  • It requires apo C-II as an activator and phospholipid as a cofactor, so a lipoprotein effectively licenses its own digestion by carrying the right apolipoprotein.
  • Insulin induces its synthesis in adipose tissue, directing fat to storage in the fed state.
  • Do not confuse with hormone-sensitive lipase, which is intracellular, releases fatty acids out of the adipocyte, is activated by phosphorylation in response to epinephrine and glucagon, and is inhibited by insulin β€” the principal antilipolytic hormone.
  • Deficiency causes familial hypertriacylglycerolemia (type I) with chylomicronemia.
Why it matters

Two lipases, opposite jobs, opposite hormonal control β€” the single most common confusion in this unit.

Harper's ch.25, pp.256, 262–263 Read the unit β†’
Reverse cholesterol transport
+

The process by which HDL removes cholesterol from extrahepatic tissues and returns it to the liver β€” the only organ that can excrete cholesterol, in bile as cholesterol or bile acids.

The marks are in these
  • Nascent discoidal HDL takes up free cholesterol from cell membranes via the transporter ABCA1.
  • LCAT, activated by apo A-I, esterifies it using a fatty acid from phosphatidylcholine; the nonpolar ester moves into the core, keeping the surface concentration low so that more cholesterol can flow in, and the disc becomes spherical HDL₃ then HDLβ‚‚.
  • The cholesteryl ester returns to the liver directly via scavenger receptor B1 or indirectly, transferred by CETP to VLDL and LDL.
  • ABCA1 deficiency = Tangier disease, with near-absent HDL.
Why it matters

This is the mechanistic reason for the inverse relationship between HDL concentration and coronary risk.

Harper's ch.25, pp.261–262 Read the unit β†’
Fatty liver (hepatic steatosis)
+

Accumulation of triacylglycerol in the liver, occurring when the rate at which triacylglycerol enters or is formed exceeds the rate at which it is exported as VLDL or oxidised.

The marks are in these
  • Category 1 β€” too much fat arriving: raised plasma free fatty acids from adipose tissue, as in starvation, diabetes mellitus and high-fat diets; accompanied by ketosis.
  • Category 2 β€” a metabolic block in VLDL production: a block in apolipoprotein synthesis (abetalipoproteinemia; carbon tetrachloride, chloroform, phosphorus, lead, arsenic, puromycin; protein deficiency); a failure to provide phospholipid β€” as in choline deficiency, whose reversal is the lipotropic action; or a failure of the secretory mechanism.
  • Ethanol causes fatty liver by raising the NADH/NAD⁺ ratio, which inhibits fatty acid oxidation and the citric acid cycle and favours esterification. Prolonged steatosis may progress to fibrosis and cirrhosis.
Why it matters

The phospholipid route ties pathology back to structure: no phosphatidylcholine means no lipoprotein surface monolayer, so no VLDL can be assembled.

Harper's ch.25, pp.264–265 Read the unit β†’
Cholesterol
+

A 27-carbon amphipathic steroid alcohol, a major component of the plasma membrane where it modulates fluidity, and the precursor of bile acids, steroid hormones and vitamin D.

The marks are in these
  • All its carbon atoms are provided by acetyl-CoA. Synthesis is cytosolic and occurs in virtually all tissues β€” chiefly liver, intestine, adrenal cortex and reproductive tissues β€” with NADPH supplying reducing equivalents. About 700 mg is synthesised daily, more than the diet supplies.
  • Five stages: acetyl-CoA β†’ mevalonate (C6) β†’ isoprenoid units (C5) β†’ squalene (C30) β†’ lanosterol β†’ cholesterol (C27).
  • The steroid nucleus cannot be degraded to COβ‚‚ and water in the body. Cholesterol is eliminated only by conversion to bile acids or excretion as neutral steroids, about 1 g per day, roughly half by each route.
Why it matters

That negative fact β€” the ring cannot be broken down β€” is why reverse cholesterol transport, and therefore HDL, matters so much.

Harper's ch.26, pp.267–273 Read the unit β†’
HMG-CoA reductase
+

The rate-limiting enzyme of cholesterol biosynthesis, in the endoplasmic reticulum membrane, catalysing the irreversible reduction of HMG-CoA to mevalonate using two NADPH.

The marks are in these
  • Regulated at four levels: transcription, via SREBP, activated when cellular sterol is low and increasing transcription of both the reductase and the LDL receptor; regulated degradation of the enzyme protein; covalent modification β€” phosphorylation inactivates; and feedback inhibition by cholesterol, dietary or delivered in LDL.
  • Insulin and thyroid hormone increase activity; glucagon and glucocorticoids decrease it.
  • It is the target of the statins, competitive inhibitors which lower plasma LDL chiefly by an indirect route: falling intracellular cholesterol de-represses LDL-receptor synthesis, so the liver clears more LDL from blood.
Why it matters

Do not confuse with HMG-CoA SYNTHASE, the mitochondrial regulatory enzyme of ketogenesis, or with HMG-CoA lyase. Three enzymes, one substrate name, three different exam answers.

Harper's ch.26, pp.268–274 Read the unit β†’
Bile acids
+

C24 steroid acids formed from cholesterol in the liver β€” the principal route of cholesterol excretion and the detergents that emulsify dietary lipid.

The marks are in these
  • The primary bile acids are cholic acid and chenodeoxycholic acid; 7Ξ±-hydroxylase is the rate-limiting enzyme, and it is feedback-inhibited by bile acids.
  • Before secretion they are conjugated with glycine or taurine, which keeps them ionised and therefore better detergents at intestinal pH. Secondary bile acids β€” deoxycholic and lithocholic β€” are produced by intestinal bacteria.
  • Enterohepatic circulation: 98–99% is reabsorbed in the ileum and returned to the liver, the pool cycling six to ten times a day, with only about 0.5 g lost daily in the feces.
Why it matters

Interrupting that cycle with bile acid sequestrants such as cholestyramine β€” or with soluble dietary fibre β€” forces the liver to convert more cholesterol into bile acids, and so lowers plasma cholesterol.

Harper's ch.26, pp.273–274 Read the unit β†’
πŸ”¬ Nitrogen Metabolism & Integration16 terms Β· Units 20–22
Transamination β˜… asked 2019
+

The reversible transfer of an Ξ±-amino group from an Ξ±-amino acid to an Ξ±-keto acid, interconverting pairs of Ξ±-amino acids and Ξ±-keto acids.

The marks are in these
  • Catalysed by aminotransferases (transaminases), all of which carry pyridoxal phosphate (PLP), a derivative of vitamin B₆, at the catalytic site, where it acts as the carrier of the amino group via an enzyme-bound Schiff base. The mechanism is β€œping-pong” β€” alternate addition of a substrate and release of a product.
  • The reaction is freely reversible, with an equilibrium constant close to unity, so it serves in both amino acid catabolism and biosynthesis. All the common amino acids except lysine, threonine, proline and hydroxyproline participate.
  • Significance: since alanine is also a substrate for glutamate aminotransferase, the Ξ±-amino nitrogen of all amino acids that undergo transamination can be concentrated in glutamate β€” the only amino acid oxidatively deaminated at an appreciable rate. Transamination is therefore the collection system for nitrogen disposal.
  • Clinically: AST (SGOT) is raised in myocardial infarction, ALT (SGPT) in viral hepatitis.
Why it matters

⭐ The single most reliably examined term in the whole subject β€” set in Section I of BOTH the 2019 and the 2020/21 paper. Say β€œreversible” and name pyridoxal phosphate in the first sentence.

Expected phrasing

Lead with the definition, then PLP, then the glutamate rationale. Both papers set it as a 3-mark Section I term, so three sentences is the right length.

Harper's ch.28, pp.290–291 Read the unit β†’
The urea cycle
+

The hepatic cyclic pathway that converts toxic ammonia into nontoxic, water-soluble urea for excretion β€” the final stage of nitrogen disposal in ureotelic animals.

The marks are in these
  • Synthesis of 1 mol of urea requires 3 mol of ATP, 1 mol each of ammonium ion and of aspartate, and employs five enzymes. NH₃, COβ‚‚ and the amide nitrogen of aspartate provide the atoms of urea.
  • 1 Β· COβ‚‚ + NH₄⁺ + 2 ATP β†’ carbamoyl phosphate (carbamoyl phosphate synthase I, the rate-limiting enzyme, active only with N-acetylglutamate) β€” mitochondrial
    2 Β· + ornithine β†’ citrulline (ornithine transcarbamoylase) β€” mitochondrial
    3 Β· + aspartate + ATP β†’ argininosuccinate (argininosuccinate synthase) β€” cytosolic
    4 Β· β†’ arginine + fumarate (argininosuccinate lyase) β€” cytosolic
    5 Β· β†’ urea + ornithine (arginase) β€” cytosolic
  • Ornithine is regenerated, so there is no net loss or gain of ornithine, citrulline, argininosuccinate or arginine. The fumarate links the cycle to the citric acid cycle, and the aspartate-fumarate skeleton acts as a carrier of nitrogen rather than a consumable.
  • Disorders of every enzyme are known, characterised by hyperammonemia, encephalopathy and respiratory alkalosis.
Why it matters

Ammonia intoxication is most severe when the block is at reactions 1 or 2, for if citrulline can be synthesized, some ammonia has already been removed by being covalently linked to an organic metabolite.

Harper's ch.28, pp.292–295 Read the unit β†’
Nitrogen balance
+

Nitrogen balance = nitrogen ingested (primarily as protein) βˆ’ nitrogen excreted (primarily as urea).

The marks are in these
  • Nitrogen equilibrium (balance = 0): protein synthesis = protein degradation β€” the normal adult state.
  • Positive nitrogen balance: an excess of ingested over excreted nitrogen; synthesis exceeds degradation. Accompanies growth and pregnancy.
  • Negative nitrogen balance: output exceeds intake. May follow surgery, advanced cancer, and the nutritional disorders kwashiorkor and marasmus.
  • Related figures: humans turn over 1% to 2% of total body protein daily, principally muscle protein, and about 75% of the liberated amino acids are reutilized.
Why it matters

Excess amino acids are not stored β€” those not immediately incorporated into protein are rapidly degraded. That single fact is why nitrogen disposal must be continuous.

Harper's ch.28, pp.287–288 Read the unit β†’
Glutamate dehydrogenase (GDH)
+

The hepatic enzyme that occupies a central position in nitrogen metabolism, catalysing the oxidative deamination of L-glutamate: L-glutamate + NAD(P)⁺ + Hβ‚‚O β†’ Ξ±-ketoglutarate + NH₃ + NAD(P)H.

The marks are in these
  • It can use either NAD⁺ or NADP⁺. The reaction is reversible but strongly favours glutamate formation, and therefore serves in amino acid biosynthesis as well as catabolism.
  • Allosterically inhibited by ATP, GTP and NADH; activated by ADP β€” it runs when the cell needs fuel, since its product Ξ±-ketoglutarate is a citric acid cycle intermediate.
  • Its concerted action with glutamate aminotransferase is termed transdeamination, and it is the route by which the formation of ammonia from Ξ±-amino groups mainly occurs.
Why it matters

Although the equilibrium favours glutamate, the reaction is pulled in the deaminating direction because the ammonia is immediately consumed by carbamoyl phosphate synthase I. The urea cycle is what makes deamination possible.

Harper's ch.28, p.291 Read the unit β†’
Ammonia intoxication
+

The clinical syndrome of hyperammonemia, arising when ammonia is not cleared by the liver.

The marks are in these
  • Normally only traces (10–20 ΞΌg/dL) are present in peripheral blood, because ammonia from enteric bacteria and from tissues is rapidly removed by the liver. Toxic levels arise if portal blood bypasses the liver β€” in severely impaired hepatic function, or through collateral portal-systemic links in cirrhosis β€” or in inherited urea cycle defects.
  • Symptoms: tremor, slurred speech, blurred vision, coma and ultimately death.
  • Mechanism: ammonia reacts with Ξ±-ketoglutarate to form glutamate; the resulting depletion of Ξ±-ketoglutarate impairs function of the TCA cycle in neurons.
Why it matters

This is the anaplerosis problem of the citric acid cycle in clinical dress β€” and it explains why hyperammonemia and hypoglycemia produce such similar neurological pictures: both are failures of neuronal ATP supply.

Harper's ch.28, pp.291–292 Read the unit β†’
Glucogenic and ketogenic amino acids
+

Glucogenic (glycogenic): the carbon skeleton is degraded to pyruvate or a citric acid cycle intermediate and can give rise to glucose. Ketogenic: the skeleton is degraded to acetyl-CoA, acetoacetyl-CoA or acetoacetate and can give rise to ketone bodies and fat but never to glucose.

The marks are in these
  • Exclusively ketogenic: LEUCINE and LYSINE only.
    Both: isoleucine, phenylalanine, tryptophan, tyrosine.
    All the remainder are glucogenic.
  • The reason for the division is a single irreversible reaction: pyruvate dehydrogenase. Carbon entering as acetyl-CoA cannot return to pyruvate, and the two carbons entering the citric acid cycle are balanced by two leaving as COβ‚‚ β€” so there is no net oxaloacetate and therefore no net glucose.
  • Entry points: pyruvate (Ala, Trp, Cys, Ser, Gly, Thr) Β· oxaloacetate (Asn, Asp) Β· Ξ±-ketoglutarate (Arg, His, Gln, Pro, Glu) Β· succinyl-CoA (Ile, Met, Val) Β· fumarate (Phe, Tyr) Β· acetyl-CoA/acetoacetyl-CoA (Leu, Lys, Phe, Trp, Tyr).
Why it matters

⚠️ TMU Lecture 19 slide 58 lists seven amino acids as β€œketogenic”, including threonine, which Harper's Table 29-1 classifies as glycogenic. That is the β€œketogenic or partly ketogenic” list; the lecture's own question slide asks for the exclusively ketogenic pair, which is Leu and Lys.

Harper's ch.29, Table 29-1, p.298 Read the unit β†’
Phenylketonuria (PKU)
+

Type I (classic) phenylketonuria is a defect in phenylalanine hydroxylase, the enzyme that converts phenylalanine to tyrosine, with a frequency of 1 in 10,000 births.

The marks are in these
  • Phenylalanine accumulates and undergoes transamination to phenylpyruvate, which accumulates in blood and tissues and is excreted in the urine; some is reduced to phenylacetate, which gives the characteristic odour to the urine.
  • Brain damage: accumulation of phenylalanine in early life impairs normal development of the brain, partly because excess phenylalanine competes with other amino acids for transport across the blood-brain barrier.
  • Treatment: mental retardation can be prevented by a rigid diet providing only enough phenylalanine for growth β€” a restriction, not an elimination, since phenylalanine is nutritionally essential.
  • Types II and III are defects of dihydrobiopterin reductase, types IV and V of dihydrobiopterin biosynthesis; collectively the hyperphenylalaninemias.
Why it matters

⚠️ TMU Lecture 19 slides 59–60 call the enzyme β€œphenylalanine carboxylase”. That is an error β€” the lecture's own slide 66 and Harper's both give hydroxylase. Write hydroxylase in the exam.

Harper's ch.29, p.304 Read the unit β†’
PRPP (5-phosphoribosyl-1-pyrophosphate)
+

An important precursor of both purine and pyrimidine nucleotides (and of some amino acids), formed from ribose 5-phosphate + ATP by PRPP synthase.

The marks are in these
  • The overall determinant of the rate of de novo purine nucleotide biosynthesis is the concentration of PRPP, which depends on the availability of ribose 5-phosphate β€” from the pentose phosphate pathway β€” and on PRPP synthase, feedback inhibited by AMP, ADP, GMP and GDP.
  • Its role differs between the two pathways: in purine synthesis it is the scaffold on which the ring is built; in pyrimidine synthesis it joins only after the ring is complete, at OMP.
  • Because it is common to both, PRPP synthase is the pivot of the coordinated, mole-for-mole regulation of purine and pyrimidine synthesis.
Why it matters

Whenever PRPP rises, purine synthesis rises and urate follows. That one sentence explains both von Gierke disease (extra ribose 5-phosphate) and Lesch-Nyhan syndrome (PRPP not consumed by salvage).

Harper's ch.33, pp.350–354 Read the unit β†’
The purine salvage pathway
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Reactions that convert purines, their ribonucleosides and their deoxyribonucleosides to mononucleotides, and which require far less energy than de novo synthesis.

The marks are in these
  • Mechanism 1 β€” phosphoribosylation by PRPP: Pu + PRPP β†’ Pu-RP + PPi, catalysed by adenine phosphoribosyltransferase (adenine β†’ AMP) and hypoxanthine-guanine phosphoribosyltransferase (HGPRT) (hypoxanthine β†’ IMP, guanine β†’ GMP).
  • Mechanism 2 β€” phosphoryl transfer from ATP: Pu-R + ATP β†’ PuR-P + ADP, catalysed by adenosine kinase and deoxycytidine kinase.
  • Liver is the major site of de novo synthesis and supplies purines to tissues incapable of it β€” brain, which has a low level of PRPP glutamyl amidotransferase, and erythrocytes and polymorphonuclear leukocytes, which cannot make 5-phosphoribosylamine at all.
Why it matters

Because the brain depends partly on salvage, a defect in HGPRT produces a neurological syndrome β€” Lesch-Nyhan. The tissue distribution of the enzyme predicts the phenotype.

Harper's ch.33, p.350 Read the unit β†’
Gout
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A metabolic disorder of purine catabolism in which serum urate exceeds the solubility limit, sodium urate crystallizes in soft tissues and joints, and causes an inflammatory reaction β€” gouty arthritis.

The marks are in these
  • Why humans are susceptible: humans lack uricase, which in other mammals converts uric acid to the soluble product allantoin, so uric acid is the end product of purine catabolism in humans.
  • Uric acid has a pKa of 5.8 β€” relatively insoluble as the free acid at acidic pH, more soluble as sodium urate near neutrality. This explains both uric acid stones in acid urine and deposition in cool peripheral joints.
  • Causes: various genetic defects in PRPP synthase β€” elevated Vmax, increased affinity for ribose 5-phosphate, or resistance to feedback inhibition β€” cause overproduction; but most cases of gout reflect abnormalities in RENAL handling of uric acid. Urate crystals are diagnostic.
  • Treatment: allopurinol, which inhibits xanthine oxidase, so the more soluble hypoxanthine and xanthine are excreted instead.
Why it matters

Contrast pyrimidines: since the end products of pyrimidine catabolism are highly water-soluble, pyrimidine overproduction results in few clinical signs or symptoms. The difference is structural β€” a fused bicyclic ring versus a single small one.

Harper's ch.33, pp.354–357 Read the unit β†’
Lesch-Nyhan syndrome
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An overproduction hyperuricemia characterized by frequent episodes of uric acid lithiasis and a bizarre syndrome of self-mutilation, reflecting a defect in hypoxanthine-guanine phosphoribosyl transferase (HGPRT), an enzyme of purine salvage.

The marks are in these
  • Mechanism of the overproduction: salvage normally consumes PRPP; when HGPRT fails, the accompanying rise in intracellular PRPP results in purine overproduction. The patient therefore both fails to recycle purines and makes too many new ones.
  • The neurological features follow from the fact that brain has a low level of PRPP glutamyl amidotransferase and depends in part on exogenous purines.
  • Causative mutations include deletions, frameshift mutations, base substitutions and aberrant mRNA splicing.
Harper's ch.33, pp.354–355 Read the unit β†’
Jaundice (icterus)
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The yellow discolouration of tissues caused by hyperbilirubinemia. Hyperbilirubinemia is a blood level exceeding 1 mg/dL (17 ΞΌmol/L); at 2 to 2.5 mg/dL bilirubin diffuses into the tissues, which turn yellow.

The marks are in these
  • Two mechanisms: retention hyperbilirubinemia, from overproduction (unconjugated), and regurgitation hyperbilirubinemia, from reflux into the bloodstream because of biliary obstruction (conjugated).
  • Prehepatic β€” haemolytic anaemias; ↑ indirect, urine urobilinogen increased, urine bilirubin ABSENT (acholuric).
    Hepatic β€” hepatitis, cirrhosis; both fractions rise, ALT and AST markedly elevated.
    Posthepatic β€” gallstone in the common bile duct, cancer of the head of the pancreas; ↑ direct, urine bilirubin PRESENT (choluric), urobilinogen absent, pale stools, alkaline phosphatase elevated.
  • Only unconjugated bilirubin crosses the blood-brain barrier β€” hence kernicterus; only conjugated bilirubin appears in urine.
Why it matters

Both rules follow from one property. Two solubilities, two diseases β€” reconstruct the whole laboratory table from that and you never need to memorise it.

Harper's ch.31, pp.332–334 Read the unit β†’
The well-fed (absorptive) state TMU term
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The metabolic state following a meal, in which the ratio of insulin to glucagon is high, indicating that fuel storage is taking place.

The marks are in these
  • Liver: glucokinase traps large influxes of glucose from the hepatic portal vein β€” its Km of 10 mM (against 0.1 mM for hexokinase) means it works only above the fasting level of 5 mM, and unlike hexokinase it is not inhibited by glucose 6-phosphate. High insulin/glucagon increases the activity of glycogen synthase and pyruvate dehydrogenase.
  • Muscle: insulin increases glycogen synthase activity and protein synthesis. Except for short elevations in energy demand, the preferential fuel for muscle is fat.
  • Adipose tissue: insulin induces lipoprotein lipase and inhibits hormone-sensitive lipase.
  • Brain: burns glucose, as always.
Why it matters

The glucokinase kinetics are Unit 6 doing physiology: a high-Km, non-inhibited enzyme takes up glucose only when there is a surplus, so the liver never competes with the brain.

TMU Lecture 18 Slides 4–7 Β· Harper's ch.14 Read the unit β†’
Starvation TMU term
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The prolonged fasted state, whose adaptations show an attempt by the body to conserve blood glucose and to spare PROTEIN from continual degradation.

The marks are in these
  • The first priority of metabolism is to provide sufficient glucose to the brain and red blood cells, and the blood glucose level must be maintained above 2.2 mM.
  • Gluconeogenesis slows down; free fatty acids continue to be mobilized and the oxidation of fatty acids continues unabated, so oxaloacetate is drawn into gluconeogenesis and the surplus acetyl-CoA becomes ketone bodies. Muscle increases its reliance on free fatty acids and spares ketones for use by the brain.
  • Fuel table (g/24 h), day 3 β†’ day 40: brain glucose 100 β†’ 40; brain ketone bodies 50 β†’ 100; muscle-protein degradation 75 β†’ 20; adipose lipolysis 180 β†’ 180, unchanged; liver glucose output 150 β†’ 80; liver ketone bodies 150 β†’ 150.
Why it matters

Ketone bodies exist to spare protein. The brain switches fuel rather than reducing consumption, and the payoff is that muscle degradation falls from 75 to 20 g a day.

TMU Lecture 18 Slides 12–15 Read the unit β†’
The metabolic picture of untreated diabetes mellitus TMU term
+

Untreated diabetes resembles starvation in several ways β€” without insulin the tissues cannot take up glucose and behave as though there were none, despite hyperglycemia. A low insulin/glucagon ratio results eventually in hyperglycemia, muscle wasting and ketosis.

The marks are in these
  • Liver: hepatic output of glucose is increased because of stimulation of glycogenolysis and gluconeogenesis. The increased supply of FFA to the liver, combined with the removal of oxaloacetate by the gluconeogenic pathway, shunts excessive amounts of acetyl-CoA into the production of ketone bodies β€” at a rate much greater than is seen in starvation.
  • Adipose tissue: the low ratio signals fasting, so lipolysis is unopposed; reduced lipoprotein lipase activity causes elevation of chylomicrons and VLDL; and too little glucose is taken up.
  • Skeletal muscle: skeletal muscle needs insulin to keep proteins from being degraded; without it, protein synthesis is decreased and degradation is increased.
Why it matters

Starvation in the midst of plenty. Ketoacidosis exceeds starvation ketosis for two reasons: lipolysis is completely unopposed (insulin is the principal antilipolytic hormone), and the ketone bodies are not consumed, because no fuel switch occurs when blood glucose is high.

TMU Lecture 18 Slides 16–19 Read the unit β†’
One-carbon units β˜… asked 2019
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Single-carbon fragments carried between metabolites by TETRAHYDROFOLATE (Hβ‚„folate) β€” and, at the most reduced level, by S-adenosylmethionine. They exist at several oxidation states: formyl, formimino, methenyl, methylene and methyl.

The marks are in these
  • Where they come from: chiefly the glycine cleavage complex of liver mitochondria, which splits glycine to COβ‚‚ and NH₄⁺ and forms N⁡,N¹⁰-methylene tetrahydrofolate; the interconversion of serine and glycine by glycine hydroxymethyltransferase; the catabolism of histidine, whose N-formiminoglutamate (Figlu) transfers its formimino group to tetrahydrofolate; and the demethylation reactions of sarcosine.
  • What they are used for: purine biosynthesis β€” N¹⁰-formyl-tetrahydrofolate supplies C2 and C8 of the purine ring, so antifolate drugs and glutamine analogs inhibit purine biosynthesis; thymidylate synthesis β€” the only reaction of pyrimidine nucleotide biosynthesis that requires a tetrahydrofolate derivative, in which the methylene group of N⁡,N¹⁰-methylene-tetrahydrofolate becomes the methyl group of TMP; and methylation reactions generally, via S-adenosylmethionine.
  • Clinical significance: in folic acid deficiency, transfer of the formimino group is impaired and Figlu is excreted β€” excretion of Figlu following a dose of histidine can therefore be used to detect folic acid deficiency. Methotrexate blocks dihydrofolate reductase, so tetrahydrofolate cannot be regenerated after thymidylate synthase consumes it.
Why it matters

⭐ A proven 2019 Section I term. Because N⁡,N¹⁰-methylene-tetrahydrofolate is required for thymidylate synthesis, disorders of folate and vitamin B₁₂ metabolism result in deficiencies of TMP β€” and hence in megaloblastic anaemia: cells that grow but cannot divide.

Harper's ch.29, pp.301–302 Β· ch.30, p.318 Β· ch.33, pp.349, 353 Read the unit β†’
🧫 Molecular Biology18 terms Β· Units 23–26
Nucleosomes β˜… asked 2020/21
+

The fundamental packaging unit of chromatin: dense spherical particles, approximately 10 nm in diameter, connected by DNA filaments, composed of DNA wound around an octameric complex of histone molecules.

The marks are in these
  • Structure: the octamer is two each of H2A, H2B, H3 and H4. In the nucleosome, the DNA is supercoiled in a LEFT-HANDED helix over the surface of the disk-shaped histone octamer; 1.75 superhelical turns of DNA are wrapped around the surface, protecting 145 to 150 bp and forming the nucleosome core particle.
  • Assembly: the (H3-H4)β‚‚ tetramer itself can confer nucleosome-like properties on DNA; addition of two H2A-H2B dimers stabilizes the primary particle. H1 is NOT part of the core β€” it is the histone least tightly bound to chromatin, easily removed with a salt solution, binds the linker DNA, and is not necessary for reconstitution of the nucleosome core.
  • Function: condensation. The human haploid genome consists of about 3 Γ— 10⁹ bp and about 1.7 Γ— 10⁷ nucleosomes, and must be compressed about 8000-fold to generate the structure of a condensed metaphase chromosome.
Why it matters

Packaging IS regulation. Acetylation of lysines in the histone tails reduces their positive charge, decreases affinity for DNA and disrupts nucleosomal structure, giving transcription factors access β€” see [[unit 26]].

Harper's ch.35, pp.371–375 Read the unit β†’
Telomeres β˜… asked 2020/21
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The structures at the ends of each chromosome, which consist of short TG-rich repeats. Human telomeres have a variable number of repeats of the sequence 5β€²-TTAGGG-3β€², which can extend for several kilobases.

The marks are in these
  • Why they are needed β€” the end-replication problem: DNA polymerases synthesise only 5β€²β†’3β€² and cannot initiate a chain, so on the lagging strand the final RNA primer at the chromosome end is removed and the gap cannot be filled. Every round of replication would otherwise shorten the chromosome; telomeres are expendable non-coding repeats that absorb the loss.
  • Telomerase β€” a multisubunit RNA template-containing complex related to viral RNA-dependent DNA polymerases (reverse transcriptases) β€” is the enzyme responsible for telomere synthesis and thus for maintaining the length of the telomere.
  • Since telomere shortening has been associated with both malignant transformation and aging, this enzyme has become an attractive target for cancer chemotherapy and drug development.
Why it matters

Do not confuse with the centromere β€” an A-T-rich region of repeated DNA bound by CENP-A nucleotomes to form the kinetochore, the anchor for the mitotic spindle.

Harper's ch.35, pp.374–375 Read the unit β†’
Melting temperature (Tm) of DNA
+

The midpoint of the temperature range over which the two strands of a DNA molecule separate.

The marks are in these
  • Denaturation is accompanied by HYPERCHROMICITY OF DENATURATION β€” an increase in the optical absorbance of the purine and pyrimidine bases, because the bases unstack β€” and by a loss of viscosity, since double-stranded DNA exhibits properties of a rigid rod.
  • DNA rich in G-C pairs, which have three hydrogen bonds, melts at a higher temperature than that rich in A-T pairs, which have two.
  • A 10-fold increase of monovalent cation concentration increases the Tm by 16.6 Β°C, by neutralizing the intrinsic interchain repulsion between the highly negatively charged phosphates. Formamide destabilizes hydrogen bonding between bases, thereby lowering the Tm.
  • Separated strands renature when appropriate temperature and salt conditions are achieved; this reannealing is often referred to as HYBRIDIZATION β€” the basis of Southern (DNA/DNA) and Northern (RNA/DNA) blotting.
Why it matters

Note the dimensions of B-DNA that go with it: 10 bp per turn, 3.4 nm (34 Γ…) per turn, 2 nm (20 Γ…) wide, found under physiologic conditions of low salt and high hydration.

Harper's ch.34, p.361 Read the unit β†’
Semiconservative replication
+

The mode of DNA replication in which each of the two strands of DNA is used as a template for synthesis of a new, complementary strand, so that each daughter duplex is composed of one strand derived from the original parental duplex and one strand that was newly synthesized.

The marks are in these
  • It follows directly from base pairing: since A pairs only with T and G only with C, each strand already contains the information needed to rebuild the other.
  • Replication starts at an origin (ori) β€” bound by dnaA in E. coli, by the origin recognition complex (ORC) in eukaryotes β€” beside an ~80-bp A+T-rich DNA unwinding element (DUE), and proceeds bidirectionally as a replication bubble.
  • Because DNA polymerases synthesise only 5β€²β†’3β€² and the strands are antiparallel, the polymerase functions asymmetrically: the leading strand is synthesized continuously and the lagging strand in short 1–5 kb Okazaki fragments, each primed by RNA and later sealed by DNA ligase.
Why it matters

Two constraints on DNA polymerase β€” 5β€²β†’3β€² only and cannot initiate a chain β€” generate every complication at the fork, and, at a chromosome end, the end-replication problem that [[telomeres]] exist to solve.

Harper's ch.34, p.363 Β· Harper's ch.35, pp.381–385 Read the unit β†’
Promoter β˜… asked 2019
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A promoter is the DNA sequence to which RNA polymerase binds to initiate transcription of a gene.

The marks are in these
  • DNA-dependent RNA polymerase attaches at this specific site on the template strand. This is followed by initiation of RNA synthesis at the starting point, and the process continues until a termination sequence is reached.
  • The promoter determines two things: where transcription is to commence along the DNA, and how frequently this event is to occur.
  • In bacteria, promoters are approximately 40 nucleotides long, with an eight-nucleotide-pair sequence about 35 bp upstream of the start site and a six-nucleotide-pair A+T-rich sequence about 10 nucleotides upstream. The Οƒ subunit helps the core enzyme recognize and bind to the promoter region.
  • In eukaryotes, promoters are more complex: TATA box, initiator sequence (Inr) and downstream promoter element (DPE), plus promoter-proximal elements (50–200 bp) and distal enhancers and repressors (1000–10⁡ bp). The TATA box has a particularly rigid requirement for both position and orientation, and is bound by TFIID through its TATA-binding protein (TBP) subunit.
Why it matters

⭐ Set in Section I of BOTH papers. Distinguish it from the transcription unit β€” the region of DNA that includes the signals for transcription initiation, elongation and termination β€” which is often set alongside it.

Expected phrasing

Write the one-line definition verbatim, then add the two things a promoter determines. That is the full three marks.

TMU Lecture 22 Β· Harper's ch.36, p.398 Read the unit β†’
Transcription
+

RNA biosynthesis from a DNA template. Its products are mRNA, tRNA and rRNA.

The marks are in these
  • Catalysed by DNA-dependent RNA polymerase, the enzyme responsible for the polymerization of ribonucleotides into a sequence complementary to the template strand of the gene, in three general steps: initiation, elongation and termination.
  • Key features: 5β€²β†’3β€² polarity, with the template strand read 3β€²β†’5β€²; substrates ATP, GTP, CTP and UTP, U replacing T; and a primer is NOT involved, as RNA polymerases can initiate synthesis de novo. Only the template strand is copied, and it will not necessarily be the same strand of the double helix for every gene.
  • The transcription bubble is 20 bp and the whole complex covers 30–75 bp. Bacterial core enzyme Ξ±β‚‚Ξ²Ξ²β€²; holoenzyme Ξ±β‚‚Ξ²Ξ²β€²Οƒ.
  • Termination in bacteria is by an intrinsic terminator β€” an inverted, hyphenated repeat followed by a stretch of AT base pairs, whose transcript forms a hairpin that causes RNA polymerase to pause β€” or by rho, an ATP-dependent RNA-stimulated helicase.
Why it matters

Mammalian cells possess three distinct nuclear DNA-dependent RNA polymerases: Pol I (rRNA), Pol II (mRNA), Pol III (tRNA, 5S). Ξ±-Amanitin distinguishes them.

TMU Lecture 22 Β· Harper's ch.36 Read the unit β†’
Introns and exons
+

EXONS are the RNA sequences that appear in mature RNAs. INTRONS are intervening sequences that interrupt the exons of mRNA-encoding genes and that neither appear in mature mRNA nor contribute to the genetic information ultimately translated into the amino acid sequence of a protein.

The marks are in these
  • The intron RNA sequences are cleaved out of the transcript, and the exons are appropriately spliced together IN THE NUCLEUS before the resulting mRNA molecule appears in the cytoplasm for translation.
  • Splicing depends on consensus sequences at the splice junctions and an internal branch site, and is carried out by the spliceosome, assembled from snRNAs (small nuclear RNAs) and snRNPs (small nuclear ribonucleoprotein particles). The catalysis is performed by RNA β€” the snRNAs are ribozymes.
  • Alternative splicing provides for different mRNAs, so one gene may specify several proteins.
Why it matters

The related device of alternative promoter utilization: in the glucokinase gene, the Ξ²-cell promoter and exon 1B lie about 30 kbp upstream of the liver promoter and exon 1L, while exons 2–10 are identical and the proteins have identical kinetic properties β€” two jobs, two control systems, one coding sequence.

TMU Lecture 22 Β· Harper's ch.36, p.404 Read the unit β†’
Post-transcriptional processing of eukaryotic mRNA
+

The three modifications converting a pre-mRNA primary transcript into a mature message. Processing occurs primarily within the nucleus and is cotranscriptionally coupled through the phosphorylated CTD of RNA polymerase II.

The marks are in these
  • 1 Β· Capping. Mammalian mRNA molecules contain a 7-methylguanosine cap structure at their 5β€² terminal. The 5β€² cap is required both for efficient translation initiation and protection of the 5β€² end from attack by 5β€²β†’3β€² exonucleases.
  • 2 Β· Polyadenylation. The mRNA is first cleaved about 20 nucleotides downstream from an AAUAAA sequence; poly(A) polymerase adds a tail subsequently extended to about 200 A residues. The poly(A) tail both protects the 3β€² end from 3β€²β†’5β€² exonuclease attack and facilitates translation. (Histone mRNA lacks a poly(A) tail.)
  • 3 Β· Splicing β€” introns removed, exons joined, by the spliceosome.
  • The cap and poly(A) tail structures have a synergistic effect on protein synthesis, because initiation factors bridge them and circularise the message.
Why it matters

Each end is protected against the exonuclease that attacks from its own direction, and both promote translation. Circularisation is also a quality check β€” only a completed, properly processed transcript can be circularised.

TMU Lecture 22 Β· Harper's ch.36 Read the unit β†’
Degeneracy of the genetic code β˜… asked 2019
+

β€œDegeneracy” in the genetic code means that MULTIPLE CODONS DECODE THE SAME AMINO ACID.

The marks are in these
  • Of the 64 possible codons (4Β³), three are nonsense codons used as termination signals β€” UAA, UAG, UGA, and the remaining 61 code for the 20 naturally occurring amino acids. Since 61 > 20, most amino acids have several codons: six different codons β€” UCU, UCC, UCA, UCG, AGU, AGC β€” all specify serine, while methionine and tryptophan have a single codon.
  • Degeneracy is NOT ambiguity. For any specific codon, only a single amino acid is specified; with rare exceptions the genetic code is unambiguous. The distinction between ambiguity and degeneracy is an important concept. The code is degenerate but unambiguous β€” translation is reliable, back-translation is not.
  • In general, the third nucleotide in a codon is less important than the first two in determining the specific amino acid to be incorporated β€” the basis of WOBBLE.
Why it matters

The redundancy is a shock absorber β€” many base changes are silent β€” and it allows 31 cytoplasmic tRNA species to read 61 codons (mitochondria manage with 22).

Harper's ch.37, p.414 Read the unit β†’
Anticodon β˜… asked 2020/21
+

A specific sequence in a tRNA molecule, complementary to a codon in mRNA.

The marks are in these
  • The anticodon region (arm) consists of seven nucleotides, and it recognizes the three-letter codon in mRNA. Reading 3β€²β†’5β€², the loop is variable base (N) β€” modified purine (Pu*) β€” XYZ (the anticodon) β€” pyrimidine (Py) β€” pyrimidine (Py).
  • This direction of reading the anticodon is 3β€²β†’5β€², whereas the genetic code is read 5β€²β†’3β€², since the codon and the anticodon loop are ANTIPARALLEL in their complementarity, just like all other intermolecular interactions between nucleic acid strands.
  • Significance: for a given codon in the mRNA, only a single species of tRNA molecule possesses the proper anticodon; since each tRNA can be charged with only one specific amino acid, each codon therefore specifies only one amino acid β€” this is why the code is unambiguous. However, some tRNA molecules can utilize the anticodon to recognize more than one codon β€” wobble.
  • The other arms: acceptor arm (3β€²-CCA, carries the amino acid), TψC arm (binds the ribosomal surface), D arm (recognised by the aminoacyl-tRNA synthetase).
Harper's ch.37, pp.415–416 Read the unit β†’
Wobble
+

The pairing of the codon and anticodon can β€œwobble” at the LAST nucleotide of the codon triplet β€” that is, the base pairing between this last nucleotide and the corresponding nucleotide of the anticodon is not strictly by the Watson-Crick rule.

The marks are in these
  • The degeneracy of the genetic code resides mostly in this last nucleotide. For example, the two codons for arginine, AGA and AGG, can bind to the same anticodon. Inosine, one of the unusual bases of tRNA, is the classic wobble base.
  • Consequence: one tRNA can read several codons, so the cytoplasmic translation system possesses a full complement of 31 tRNA species for 61 codons, and mitochondria require only 22 tRNA molecules.
Why it matters

Degeneracy and wobble are the same molecular property described twice β€” the code is degenerate BECAUSE the third pairing is loose. It is also why third-base mutations are so often silent.

Harper's ch.37, p.416 Read the unit β†’
Aminoacyl-tRNA synthetase
+

The enzyme that charges a tRNA with its specific amino acid. There is one for each amino acid.

The marks are in these
  • It forms an activated intermediate of aminoacyl-AMP-enzyme complex, and the amino acid remains attached to its specific tRNA in an ESTER linkage at the 3β€²-CCA of the acceptor arm. Two high-energy phosphate bonds are spent.
  • The charging reactions have an error rate of less than 10⁻⁴ and so are extremely accurate.
Why it matters

That accuracy is critical because the ribosome inspects only the codon-anticodon pairing, never the identity of the attached amino acid. The fidelity of the genetic code is enforced at charging, not at the ribosome.

TMU Lecture 23 Β· Harper's ch.37 Read the unit β†’
Operon
+

A cluster of genes that can be regulated by a single promoter or regulatory region, transcribed together as one unit.

The marks are in these
  • It yields POLYCISTRONIC mRNA β€” transcribed into one large mRNA molecule containing multiple independent translation start (AUG) and stop (UAA) codons for each cistron β€” giving coordinate expression. A cistron is the genetic unit encoding one polypeptide: the β€œone cistron, one subunit” concept, refining β€œone gene, one enzyme”.
  • The lac operon is the model: lacZ (Ξ²-galactosidase), lacY (a permease, for the permeation of lactose into the cell) and lacA (a thiogalactoside transacetylase), with lacI, encoding the repressor, outside the operon.
Why it matters

Operons do not occur in eukaryotes, because cap-dependent scanning permits only one translation initiation site per mRNA. One feature of initiation determines an entire architecture of gene organisation.

TMU Lecture 24 Β· Harper's ch.38 Read the unit β†’
The lac operon
+

The E. coli operon whose analysis of lactose metabolism led to the operon model of gene regulation.

The marks are in these
  • Structural genes: lacZ β€” Ξ²-galactosidase; lacY β€” a permease, the permeation of lactose into the cell; lacA β€” a thiogalactoside transacetylase, transcribed as one polycistronic mRNA.
  • Negative control: lacI encodes the lac operon repressor protein β€” four identical subunits of molecular weight 38,000, with a high affinity for the operator locus. The operator locus is a region of double-stranded DNA 27 base pairs long, with a twofold rotational symmetry and an inverted palindrome; LacI repressor binding is 17 base pairs, and only two subunits of the repressor appear to bind. Addition of lactose or of a gratuitous inducer such as IPTG causes derepression.
  • Positive control: catabolite gene activator protein (CAP), also referred to as the cAMP regulatory protein (CRP), in conjunction with cAMP.
  • Kinetics: lac-specific mRNAs are fully induced within 5–6 minutes; Ξ²-galactosidase protein is maximal within 10 minutes β€” a type A response.
Why it matters

Maximal activity requires lactose present AND glucose absent β€” an AND gate built from one regulator that acts positively (the cAMP-CRP complex) and one that acts negatively (the LacI repressor).

TMU Lecture 24 Β· Harper's ch.38 Read the unit β†’
Catabolite repression
+

The suppression of the lac and other catabolic operons when glucose is available.

The marks are in these
  • When bacteria are exposed to both lactose and glucose as sources of carbon, they first metabolize the glucose and then temporarily stop growing, until the genes of the lac operon become induced and they gain the ability to metabolize lactose as a usable energy source.
  • It is mediated by a catabolite gene activator protein (CAP) in conjunction with cAMP. When glucose or glycerol is present in concentrations sufficient for growth, the bacteria will lack sufficient cAMP to bind to CAP, because the glucose inhibits adenylyl cyclase, the enzyme that converts ATP to cAMP.
  • The CAP-cAMP regulator is acting as a POSITIVE regulator.
Why it matters

cAMP means the same thing here as in the hepatocyte of [[unit 12]]: glucose is scarce. The same messenger with the same meaning, three billion years apart.

TMU Lecture 24 Β· Harper's ch.38 Read the unit β†’
Positive and negative regulation
+

Negative regulation: the regulatory element is present and expression is decreased; the protein responsible is a REPRESSOR. Positive regulation: the element is present and expression is increased; that mediating positive regulation is a positive regulator or ACTIVATOR.

The marks are in these
  • Derepression is removal of a repressor, and works because a double negative has the effect of acting as a positive.
  • Inducible genes have relatively low basal rates of transcription; housekeeping genes are expressed constantly; a constitutive mutation makes an inducible gene expressed permanently.
  • cis-acting elements are DNA sequences acting only on the molecule they are part of; trans-acting factors are diffusible proteins acting on any copy. This is why a lacI mutation can be complemented and an operator mutation cannot.
Why it matters

A gene under negative control is off by default and needs no continuous input to stay off, and can be switched on by the substrate itself β€” which is exactly what lactose does.

TMU Lecture 24 Β· Harper's ch.38 Read the unit β†’
Chromatin remodelling
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An important aspect of eukaryotic gene expression: chromatin structure provides an additional level of control of gene transcription that prokaryotes do not possess, and it is the basis of differential expression between tissues.

The marks are in these
  • Histone acetylation and deacetylation occur on lysine residues in the amino terminal tails of histone molecules. Acetylation reduces the positive charge of these tails, decreases the binding affinity of histone for the negatively charged DNA, and causes disruption of nucleosomal structure, allowing access of transcription factors to cognate regulatory DNA elements and enhancing binding of the basal transcription machinery to the promoter. Histone deacetylation would have the opposite effect.
  • Methylation of deoxycytidine residues in the sequence 5β€²-mCpG-3β€² silences genes: in mouse liver, only the unmethylated ribosomal genes can be expressed, and many animal viruses are not transcribed when their DNA is methylated.
Why it matters

Because both marks are copied through cell division, this level of control is heritable β€” which is what a repressor protein can never be, since it must be continuously present and is diluted at every division.

TMU Lecture 24 Β· Harper's ch.38 Read the unit β†’
DNA-binding motifs
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Several motifs mediate the binding of regulatory proteins to DNA: the helix-turn-helix, the zinc finger, and the leucine zipper.

The marks are in these
  • General principles: binding must be of high affinity to the specific site and of low affinity to other DNA; binding is usually by a dimer, matching the twofold symmetry of a palindromic site; and the protein-DNA interactions are maintained by hydrogen bonds and van der Waals forces.
  • Helix-turn-helix β€” illustrated by Cro: the monomer consists of three antiparallel Ξ² sheets (Ξ²1–β3) and three Ξ±-helices (Ξ±1–α3); the Ξ±3 and Ξ±2 helices are held at about 90 degrees to each other by a turn of four amino acids; the Ξ±3 helix of Cro is the DNA recognition surface. The distance between comparable points on the two DNA Ξ±-helices is 34 Γ… β€” one turn of B-DNA.
  • Zinc finger β€” a domain folded around a zinc ion stabilising a short recognition helix.
  • Leucine zipper β€” a helical wheel consisting of seven spokes that correspond to the seven amino acids, with leucine residues at every seventh position; it mediates dimerisation while an adjacent basic region binds DNA.
Why it matters

All three converge on the same solution β€” presenting a short Ξ±-helix to the major groove β€” because the edges of the base pairs are exposed there and the groove is about the width of an Ξ±-helix.

TMU Lecture 24 Β· Harper's ch.38 Read the unit β†’
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