Gene Expression — Q-Bank
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Unit 26 Question Bank

Operons · the lac operon · catabolite repression · lambda · chromatin · DNA-binding motifs
25 MCQ · five options6 Definitions2 Written answersHarper's verified
Format note: the TMU Biochemistry paper gives five suggested answers (A–E), not four — these MCQs match that. Items tagged TMU 2019 or TMU 2020/21 come from the real papers. Answers are verified against Harper's Illustrated Biochemistry; the "marking schemes" in the source folder are other students' answer sheets, not official, so they are never used as the authority.
0 / 25 answered
1Regulated expression of genes is required for ( ).
A. maintaining the genetic code itself
B. development, differentiation and adaptation
C. preventing mutation of the genome
D. DNA replication and nothing else
E. protein folding in the cytosol
Answer: B
Harper's chapter title states it directly. The purposes are that expression is regulated during ontogeny and differentiation of the organism, that the organism can adapt to its environment and conserve energy and nutrients, and that it can respond to complex environmental challenges.TMU Lecture 24 · Harper's ch.38
2A protein that mediates POSITIVE regulation of transcription is called ( ).
A. a repressor
B. an operator
C. an activator
D. a promoter
E. an inducer
Answer: C
That mediating positive regulation is a positive regulator or activator. Note that operator and promoter are DNA sequences, not proteins — a distinction examiners test — and an inducer is a small molecule.TMU Lecture 24 · Harper's ch.38
3Derepression works because ( ).
A. the activator is synthesised de novo
B. the promoter sequence is altered
C. RNA polymerase is phosphorylated
D. a double negative acts as a positive
E. the operator becomes methylated
Answer: D
More than wordplay — it is a design principle. A gene under negative control is off by default and needs no continuous input to stay off; switching it on requires only that the repressor be removed, and removal can be triggered by the substrate itself. The signal that a pathway is needed is the arrival of the molecule the pathway acts on.TMU Lecture 24 · Harper's ch.38
4An operon is ( ).
A. the genetic unit encoding one polypeptide
B. a diffusible regulatory protein factor
C. the site at which a repressor binds DNA
D. a eukaryotic enhancer element
E. a cluster of genes under one promoter
Answer: E
Option A defines a cistron — the “one cistron, one subunit” concept, refining the older “one gene, one enzyme”. An operon is transcribed as polycistronic mRNA, giving coordinate expression of all its genes.TMU Lecture 24 · Harper's ch.38
5Polycistronic mRNA is characterised by ( ).
A. one transcript with several start and stop codons
B. one transcript with a single open reading frame
C. several small transcripts sharing one promoter
D. an mRNA that lacks any stop codon at all
E. an mRNA read in three overlapping frames
Answer: A
Eukaryotes cannot use this arrangement, and the reason connects to Unit 25: the 5′ cap directs the 40S ribosomal subunit to the 5′ end, which then scans to the first suitable AUG. One entry point means one protein per message. Cap-dependent scanning is precisely what makes operons impossible in eukaryotes.TMU Lecture 24 · Harper's ch.37 and ch.38
6Which lac gene encodes the permease?
A. lacZ
B. lacY
C. lacA
D. lacI
E. lacO
Answer: B
lacY encodes a permease, for the permeation of lactose into the cell. lacZ encodes β-galactosidase; lacA a thiogalactoside transacetylase; lacI the repressor protein, and it lies outside the operon with its own promoter. Mnemonic: Zap it, Yank it in, Acetylate it.TMU Lecture 24 · Harper's ch.38
7The lac repressor protein is ( ).
A. a dimer binding only in the presence of cAMP
B. a protein identical to CAP in sequence
C. a tetramer of identical 38,000-MW subunits
D. an RNA molecule rather than a protein
E. a monomer of MW 150,000 in solution
Answer: C
A refinement worth quoting: although the repressor is a tetramer covering 17 base pairs of the operator, only two subunits of the repressor appear to bind. The other two are structural.TMU Lecture 24 · Harper's ch.38
8The lac operator locus is ( ).
A. a sequence identical to the CAP-binding site
B. a single-stranded region of 17 nucleotides
C. the sequence to which RNA polymerase binds
D. 27 bp of dsDNA, an inverted palindrome
E. a 40-nucleotide A+T-rich stretch of DNA
Answer: D
The palindrome is a consequence of protein shape, not decoration: a protein with twofold rotational symmetry must bind a site with twofold rotational symmetry. Predict it elsewhere — the λ operator elements are 17-bp sites bound by dimers, and leucine zipper and helix-turn-helix proteins bind palindromes as dimers. Protein symmetry predicts DNA symmetry.TMU Lecture 24 · Harper's ch.38
9A mutation in lacI such that LacI cannot bind operator DNA results in ( ).
A. permanent repression of the operon
B. expression only in the presence of glucose
C. loss of β-galactosidase activity
D. no change, because CAP still controls the operon
E. constitutive expression of the lac operon
Answer: E
With no functional repressor the operator is permanently free. Contrast the mirror-image mutation, also set in the lecture: a LacI protein that cannot bind the INDUCER gives the opposite result — the operon can never be induced, because lactose can no longer remove a repressor that still binds the operator normally.TMU Lecture 24, review question
10A mutation in the lac OPERATOR that prevents binding of a normal repressor differs from a lacI mutation in that ( ).
A. it acts only in cis, affecting just the operon physically attached to it
B. it acts in trans, affecting all copies in the cell
C. it prevents induction rather than causing constitutive expression
D. it can be complemented by a normal operator supplied on a plasmid
E. it has no effect on transcription
Answer: A
Both mutations give constitutive expression, so the discriminating point is the mode of action. lacI encodes a diffusible protein and therefore acts in trans — a normal copy elsewhere rescues it. The operator is a DNA site and acts only in cis — it cannot be rescued by a normal operator on another molecule. This is the cis/trans distinction in its original setting.TMU Lecture 24, review question
11Induction of the lac operon by lactose or IPTG occurs because ( ).
A. the inducer is a substrate for RNA polymerase
B. the inducer binds the repressor, freeing the operator
C. the inducer methylates the promoter region
D. the inducer binds to the operator directly
E. the inducer activates the CAP protein
Answer: B
IPTG is called a gratuitous inducer because it induces the operon without being metabolised by it — which makes it invaluable experimentally. The kinetics are the classic type A response: lac-specific mRNAs are fully induced within 5–6 minutes and β-galactosidase protein is maximal within 10 minutes.TMU Lecture 24 · Harper's ch.38
12Catabolite repression is mediated by ( ).
A. direct inhibition of RNA polymerase by glucose
B. the LacI repressor bound to glucose itself
C. catabolite gene activator protein (CAP) with cAMP
D. accelerated degradation of the lac mRNA
E. methylation of the lac promoter region
Answer: C
The observation it explains: bacteria given both sugars first metabolize the glucose and then temporarily stop growing, until the genes of the lac operon become induced. The CAP-cAMP regulator acts as a POSITIVE regulator.TMU Lecture 24 · Harper's ch.38
13Glucose reduces cAMP in E. coli by ( ).
A. activating the phosphodiesterase instead
B. inhibiting the synthesis of CAP protein
C. binding to the cAMP molecule directly
D. inhibiting adenylyl cyclase, which makes cAMP
E. exporting the cAMP out of the cell
Answer: D
When glucose or glycerol is present in concentrations sufficient for growth, the bacteria will lack sufficient cAMP to bind to CAP. Note that cAMP means the same thing here as in Unit 12: glucose is scarce. In the hepatocyte, glucagon raises cAMP as blood glucose falls; in the bacterium, glucose itself suppresses it. The same messenger with the same meaning, three billion years apart.TMU Lecture 24 · Harper's ch.38
14Maximal transcription of the lac operon requires ( ).
A. lactose present AND glucose present
B. lactose absent AND glucose absent
C. lactose absent AND glucose present
D. lactose present, regardless of glucose
E. lactose present AND glucose absent
Answer: E
The operon is controlled by two regulatory proteins: one acting positively (the cAMP-CRP complex) and one acting negatively (the LacI repressor). Each answers a different question — the repressor asks is there lactose?, CAP-cAMP asks is there anything better? Only “lactose yes, glucose no” satisfies both. It is an AND gate built from one negative and one positive regulator.TMU Lecture 24 · Harper's ch.38
15In bacteriophage lambda, when the repressor (cI) gene is on ( ).
A. the cro gene is off and the phage stays lysogenic
B. the phage immediately enters the lytic cycle
C. the cro gene is also on, and lysis follows
D. the host bacterium dies within minutes
E. the phage DNA is degraded by the host
Answer: A
When the repressor gene is on, the cro gene is off — its prophage state; when the cro gene is on, the repressor gene is off — lytic growth. Two mutually repressing genes make a bistable memory device, with no unstable intermediate. The same architecture underlies differentiation decisions in our own cells.TMU Lecture 24 · Harper's ch.38
16Induction of a lambda prophage into the lytic cycle is triggered by ( ).
A. binding of lactose to the cI repressor protein
B. UV light, generating ssDNA that activates recA
C. depletion of glucose in the growth medium
D. methylation of the right operator region
E. a rise in the intracellular cAMP level
Answer: B
The virus is eavesdropping on the host's own damage-response protein. A prophage in a healthy bacterium is copied free of charge at every division; a prophage in a bacterium whose DNA is being shredded would die with it. The protease hydrolyzes the repressor, it dissociates from OR2 and OR1, and RNA polymerase immediately has access to the rightward promoter.TMU Lecture 24 · Harper's ch.38
17The lambda right operator (O_R) consists of ( ).
A. a single 27-bp inverted palindrome
B. two 40-bp elements separated by a spacer
C. three evenly spaced 17-bp elements
D. a 100-bp A+T-rich region of the DNA
E. an inverted repeat followed by poly-A
Answer: C
The point of “similar but not identical” is that the relative affinities of cI and Cro for each of the sites varies — which is what makes the switch directional. In the lysogen the repressor's order is OR1 > OR2 > OR3. Option E describes an intrinsic transcription terminator (Unit 24).TMU Lecture 24 · Harper's ch.38
18Histone acetylation activates transcription because ( ).
A. it increases the positive charge of the tails
B. it links histones covalently to polymerase
C. it degrades the histone octamer entirely
D. it neutralises the tails' charge, loosening the grip
E. it methylates CpG dinucleotides instead
Answer: D
Acetylation occurs on lysine residues in the amino terminal tails, and the consequence is access of transcription factors to cognate regulatory DNA elements and enhanced binding of the basal transcription machinery to the promoter. Histone deacetylation would have the opposite effect. The mechanism is purely electrostatic: basic protein, acidic DNA.TMU Lecture 24 · Harper's ch.38
19DNA methylation silences genes when it occurs ( ).
A. on adenine residues in GATC sequences
B. on guanine residues in the TATA box
C. on histone lysine residues instead
D. on the 5′ cap of the mRNA itself
E. on deoxycytidine in the sequence 5′-mCpG-3′
Answer: E
Harper's gives two lines of evidence: in mouse liver, only the unmethylated ribosomal genes can be expressed, and many animal viruses are not transcribed when their DNA is methylated. Crucially, the pattern is copied to the daughter strand after replication — which is what makes it heritable, and hence a mechanism of differentiation rather than mere adaptation.TMU Lecture 24 · Harper's ch.38
20Which factor in the β-interferon enhanceosome is described as an ARCHITECTURAL transcription factor?
A. HMG I(Y)
B. NF-κB
C. IRF
D. ATF-2/c-Jun
E. TFIID
Answer: A
HMG I(Y) induces a significant bend in the DNA and, along with the three trans factors, by inducing a series of critically spaced DNA bends, brings about the formation of a unique, stereospecific, three-dimensional structure in which all four factors are active. It does not activate transcription itself — the complex, not any component, is the activator. It also makes the enhanceosome a coincidence detector, firing only when all four signals are present.TMU Lecture 24 · Harper's ch.38, p.442
21The β-interferon gene enhancer is located ( ) and contains ( ).
A. between nucleotides −35 and −10; two elements
B. between −110 and −45; four clustered cis elements
C. 10⁵ bp upstream; only a single element
D. within the first intron; three elements
E. downstream of the poly(A) site; four elements
Answer: B
The gene is induced upon viral infection of mammalian cells. The four trans factors are NF-κB, a member of the IRF (interferon regulatory factor) family, the heterodimeric leucine zipper factor ATF-2/c-Jun, and HMG I(Y). Option A is the bacterial promoter (Unit 24).TMU Lecture 24 · Harper's ch.38
22Which three motifs mediate the binding of regulatory proteins to DNA?
A. α-helix, β-sheet, β-turn
B. Rossmann fold, TIM barrel, coiled coil
C. Helix-turn-helix, zinc finger, leucine zipper
D. SH2, SH3, PH domains
E. TATA box, Inr, DPE
Answer: C
Option A lists elements of secondary structure (Unit 3); option E lists DNA elements, not protein motifs (Unit 24). All three real motifs converge on the same solution — presenting a short α-helix to the major groove — because the edges of the base pairs are exposed at the floor of the major groove and the groove is about the width of an α-helix.TMU Lecture 24 · Harper's ch.38
23In the Cro protein, the DNA recognition surface is ( ).
A. the amino terminus of the polypeptide chain
B. the β1–β3 antiparallel sheet region
C. a zinc-coordinated recognition loop
D. the α3 helix, at 90° to α2 by a four-residue turn
E. the α1 helix at the amino terminus
Answer: D
The Cro monomer consists of three antiparallel β sheets (β1–β3) and three α-helices (α1–α3). A dimer places one recognition helix in each of two successive major grooves — the distance between comparable points on the two DNA α-helices is 34 Å, exactly one turn of B-DNA (Unit 23). Note also that Cro's single domain mediates both operator binding and dimerization.TMU Lecture 24 · Harper's ch.38
24A leucine zipper is defined by ( ).
A. a leucine-rich loop coordinating a zinc ion
B. two leucines forming a covalent cross-link
C. a leucine residue at every third position
D. alternating leucine and lysine residues
E. leucine at every seventh position, on one face
Answer: E
The wheel consists of seven spokes that correspond to the seven amino acids of each helical turn, so a residue at every seventh position always faces the same way. The zipper itself mediates dimerisation; an adjacent basic region binds the DNA. Heterodimers such as ATF-2/c-Jun let a limited set of proteins generate combinatorial specificity.TMU Lecture 24 · Harper's ch.38
25Which level of transcriptional control is available to eukaryotes but NOT to prokaryotes?
A. Chromatin structure and nucleosome positioning
B. Repressor proteins binding operator sequences
C. Activator proteins binding DNA
D. Regulation by small-molecule inducers
E. Feedback by the pathway's end product
Answer: A
Chromatin structure provides an additional level of control of gene transcription, and it is the level that makes durable, heritable silencing possible — a repressor must be continuously present and is diluted at every division, whereas packaging is copied to both daughter cells. A bacterium regulates to adapt; a eukaryote regulates to differentiate.TMU Lecture 24 · Harper's ch.38
1 Operon — 3′+
A cluster of genes that can be regulated by a single promoter or regulatory region, transcribed together as one unit.

It yields POLYCISTRONIC mRNAtranscribed into one large mRNA molecule containing multiple independent translation start (AUG) and stop (UAA) codons for each cistron — and therefore gives coordinate expression of all its genes. A cistron is the genetic unit encoding one polypeptide: the “one cistron, one subunit” concept, refining “one gene, one enzyme”.

The lac operon is the model: lacZ (β-galactosidase), lacY (a permease, for the permeation of lactose into the cell) and lacA (a thiogalactoside transacetylase), with lacI, encoding the repressor, outside the operon.

Operons do not occur in eukaryotes, because cap-dependent scanning permits only one translation initiation site per mRNA.TMU Lecture 24 · Harper's ch.38
2 The lac operon — 3′+
The E. coli operon whose analysis led to the operon model of gene regulation.

Structural genes: lacZ — β-galactosidase; lacY — a permease, the permeation of lactose into the cell; lacA — a thiogalactoside transacetylase, transcribed as one polycistronic mRNA.

Negative control: lacI encodes the lac operon repressor proteinfour identical subunits of molecular weight 38,000, with high affinity for the operator locus. The operator is a region of double-stranded DNA 27 base pairs long with twofold rotational symmetry — an inverted palindrome; LacI binding covers 17 base pairs, and only two subunits appear to bind. Addition of lactose or of a gratuitous inducer such as IPTG causes derepression.

Positive control: catabolite gene activator protein (CAP), also called cAMP regulatory protein (CRP), in conjunction with cAMP.

Maximal activity requires lactose present AND glucose absent: the operon has one regulator that acts positively (the cAMP-CRP complex) and one that acts negatively (the LacI repressor). Induction is fast — mRNA fully induced within 5–6 minutes, β-galactosidase maximal within 10.TMU Lecture 24 · Harper's ch.38
3 Catabolite repression — 3′+
The suppression of the lac and other catabolic operons when glucose is available.

When bacteria are exposed to both lactose and glucose as sources of carbon, they first metabolize the glucose and then temporarily stop growing, until the genes of the lac operon become induced and they gain the ability to metabolize lactose as a usable energy source.

Mechanism: it is mediated by a catabolite gene activator protein (CAP) in conjunction with cAMP. When glucose or glycerol is present in concentrations sufficient for growth, the bacteria lack sufficient cAMP to bind to CAP, because the glucose inhibits adenylyl cyclase, the enzyme that converts ATP to cAMP. Without cAMP, CAP cannot bind DNA and cannot activate transcription.

The CAP-cAMP regulator acts as a POSITIVE regulator, so the operon is under dual control — an AND gate requiring lactose present and glucose absent.TMU Lecture 24 · Harper's ch.38
4 Positive and negative regulation — 2′+
Negative regulation: the regulatory element is present and expression is decreased; the protein is a REPRESSOR.

Positive regulation: the regulatory element is present and expression is increased; that mediating positive regulation is a positive regulator or ACTIVATOR.

Derepression is removal of a repressor, and works because a double negative has the effect of acting as a positive.

Related terms: inducible genes have relatively low basal rates of transcription; housekeeping genes are expressed constantly; a constitutive mutation makes an inducible gene expressed permanently.

The lac operon uses both logics at once — one regulator acting positively (cAMP-CRP) and one acting negatively (LacI).TMU Lecture 24 · Harper's ch.38
5 Chromatin remodelling — 3′+
An important aspect of eukaryotic gene expression: chromatin structure provides an additional level of control of gene transcription that prokaryotes do not possess, and it is the basis of differential expression between tissues.

Histone acetylation and deacetylation occur on lysine residues in the amino terminal tails of histone molecules. Acetylation reduces the positive charge of these tails, decreases the binding affinity of histone for the negatively charged DNA, and causes disruption of nucleosomal structure, allowing access of transcription factors to cognate regulatory DNA elements and enhancing binding of the basal transcription machinery to the promoter. Histone deacetylation has the opposite effect.

Methylation of deoxycytidine residues in the sequence 5′-mCpG-3′ silences genes: in mouse liver, only the unmethylated ribosomal genes can be expressed, and many animal viruses are not transcribed when their DNA is methylated.

Because both marks are copied through cell division, this level of control is heritable — a liver cell's daughters are liver cells.TMU Lecture 24 · Harper's ch.38
6 DNA-binding motifs — 2′+
Several motifs mediate the binding of regulatory proteins to DNA: the helix-turn-helix, the zinc finger, and the leucine zipper.

General principles: binding must be of high affinity to the specific site and of low affinity to other DNA; binding is usually by a dimer, matching the twofold symmetry of a palindromic site; and the protein-DNA interactions are maintained by hydrogen bonds and van der Waals forces.

Helix-turn-helix — illustrated by Cro: three antiparallel β sheets and three α-helices, with α3 and α2 held at about 90 degrees to each other by a turn of four amino acids; the α3 helix is the DNA recognition surface. In the dimer, the two recognition helices are 34 Å apart — one turn of B-DNA.

Zinc finger — a domain folded around a zinc ion that stabilises a short recognition helix.

Leucine zipper — a helical wheel of seven spokes corresponding to the seven amino acids, with leucine at every seventh position; the zipper mediates dimerisation while an adjacent basic region binds DNA.

All three converge on the same solution: presenting an α-helix to the major groove.TMU Lecture 24 · Harper's ch.38
1 Describe the lac operon and explain how it is regulated. 10′

Why it matters

Analysis of lactose metabolism in E. coli led to the operon model, and prokaryotes provide models for the study of gene expression in mammalian cells. The vocabulary of this one system — promoter, operator, repressor, activator, induction, cis and trans — is the vocabulary of the whole field.

Structure

An operon can be regulated by a single promoter or regulatory region. The lac operon comprises three structural genes:

  • lacZβ-galactosidase, which cleaves lactose
  • lacYa permease, for the permeation of lactose into the cell
  • lacAa thiogalactoside transacetylase

These are transcribed into one large mRNA molecule containing multiple independent translation start (AUG) and stop (UAA) codons for each cistron — a polycistronic mRNA giving coordinate expression. Translation can occur even before transcription is completed.

lacI lies outside the operon with its own promoter and encodes the lac operon repressor protein.

Negative control — the repressor

The repressor has four identical subunits of molecular weight 38,000 and a high affinity for the operator locus. The operator is a region of double-stranded DNA 27 base pairs long, with a twofold rotational symmetry and an inverted palindrome; LacI repressor binding covers 17 base pairs, and only two subunits of the repressor appear to bind.

The palindrome is not incidental. A protein with twofold rotational symmetry must bind a DNA site with twofold rotational symmetry — a rule that recurs at the λ operator and at every dimeric transcription factor in this unit.

Addition of lactose or of a gratuitous inducer such as IPTG causes the inducer to bind the repressor, which releases the operator: an inducer derepresses the lac operon. Because this is a double negative acting as a positive, the gene is off by default and needs no continuous input to stay off. Induction is fast — lac-specific mRNAs are fully induced within 5–6 minutes, and β-galactosidase protein is maximal within 10 minutes (a type A response).

Positive control — catabolite repression

When bacteria are exposed to both lactose and glucose as sources of carbon, they first metabolize the glucose and then temporarily stop growing, until the genes of the lac operon become induced. This is catabolite repression, mediated by a catabolite gene activator protein (CAP) in conjunction with cAMPalso referred to as the cAMP regulatory protein (CRP).

When glucose or glycerol is present in concentrations sufficient for growth, the bacteria will lack sufficient cAMP to bind to CAP, because the glucose inhibits adenylyl cyclase, the enzyme that converts ATP to cAMP. The CAP-cAMP regulator acts as a positive regulator.

The two signals together

LactoseGlucoseRepressorCAP-cAMPTranscription
AbsentPresentBoundInactiveOff
AbsentAbsentBoundActiveOff
PresentPresentReleasedInactiveVery low
PresentAbsentReleasedActiveMAXIMAL

The logic is worth stating explicitly: the repressor asks “is there lactose to eat?” and CAP-cAMP asks “is there anything better?” The operon commits only when the answer is lactose yes, glucose no. It is an AND gate assembled from one negative and one positive regulatorone that acts positively (the cAMP-CRP complex) and one that acts negatively (the LacI repressor).

Mutations — and the cis/trans distinction

  • lacI mutated so LacI cannot bind operator DNAconstitutive expression.
  • lacI mutated so LacI cannot bind the inducerthe operon can never be induced — permanently repressed.
  • Operator mutated so it cannot bind a normal repressorconstitutive expression, but acting only in cis. lacI encodes a diffusible protein and acts in trans, so a normal copy elsewhere rescues it; an operator is a DNA site and cannot be rescued.
Marking guide: the three structural genes with correct products 2 · polycistronic mRNA and coordinate expression 1 · repressor structure and the operator description 2 · derepression by inducer 1 · catabolite repression with the adenylyl cyclase mechanism 2 · the condition for maximal transcription 1 · one mutation analysis, ideally with the cis/trans distinction 1.
2 How does the regulation of gene expression in eukaryotes differ from that in prokaryotes? 8′

The organising difference

A bacterium regulates to adapt; a eukaryote regulates to differentiate. A bacterium must respond to a sugar appearing in its medium within 5–6 minutes and reverse the decision as quickly; a liver cell must keep the muscle genes off permanently, through every division, for the life of the organism. Almost every difference below follows from that.

ProkaryoteEukaryote
Gene organisationOperons — polycistronic mRNA, coordinate expressionOne gene, one mRNA
ChromatinNoneNucleosomes — an additional level of control
DNA methylationRestriction/modification5′-mCpG-3′ silences genes, heritably
Distance of controlOperator adjacent to promoterEnhancers at 1000–10⁵ bp, either orientation
Transcription/translationCoupledSeparated by the nuclear membrane
Post-transcriptional controlLimitedSplicing, alternative promoters, RNA editing, miRNA, stability

Why eukaryotes cannot use operons

Polycistronic mRNA requires a ribosome to initiate internally. Eukaryotic ribosomes cannot: the 5′ cap directs the 40S subunit to the 5′ end, which then scans to the first suitable AUG. One entry point means one protein per message, so related genes must be coordinated by shared regulatory elements rather than by physical clustering.

The distinctively eukaryotic mechanism — chromatin

Chromatin remodeling is an important aspect of eukaryotic gene expression; chromatin structure provides an additional level of control of gene transcription, and it is what produces differential expression between tissues.

  • Histone acetylation and deacetylation occur on lysine residues in the amino terminal tails of histone molecules. Acetylation reduces the positive charge of these tails, decreases the binding affinity of histone for the negatively charged DNA, and disrupts nucleosomal structure, giving access of transcription factors to cognate regulatory DNA elements and enhancing binding of the basal transcription machinery to the promoter. Deacetylation has the opposite effect.
  • Methylation of deoxycytidine residues in the sequence 5′-mCpG-3′ silences genes: in mouse liver, only the unmethylated ribosomal genes can be expressed, and many animal viruses are not transcribed when their DNA is methylated.

The decisive property is that both marks are copied through cell division. A repressor protein must be continuously present and is diluted at every division; packaging a gene away makes it off by default, at no ongoing cost, and heritably.

Enhancers and combinatorial control

Certain DNA elements enhance or repress transcription of eukaryotic genes, acting at up to 10⁵ bp and in either orientation, the intervening DNA looping out. The β-interferon gene, induced upon viral infection, has an enhancer between nucleotides −110 and −45 containing four distinct clustered cis elements, bound by NF-κB, an IRF family member, the heterodimeric leucine zipper factor ATF-2/c-Jun, and the ubiquitous architectural factor HMG I(Y). HMG I(Y) induces a significant bend in the DNA, and along with the three trans factors, by inducing a series of critically spaced DNA bends, brings about the formation of a unique, stereospecific, three-dimensional structure in which all four factors are active — the enhanceosome, which fires only when all four signals coincide.

Combinations of DNA elements and associated proteins provide diversity in responses, and tissue-specific expression may result from the action of enhancers or repressors.

What is shared

The underlying logic is identical. Both use positive and negative regulation through the interaction of specific binding regulatory proteins with various regions of DNA; both distinguish cis elements from trans factors; and both bind DNA through the same helix-turn-helix, zinc finger and leucine zipper motifs. The eukaryotic cell did not replace the bacterial logic — it added layers on top of it.

Marking guide: the adapt-versus-differentiate contrast 1 · at least four correct table contrasts 2 · why operons are impossible in eukaryotes 1 · histone acetylation mechanism 1.5 · DNA methylation with its heritability 1 · enhancers or the enhanceosome 1 · a statement of what is shared 0.5.