RNA & Transcription — Q-Bank
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Unit 24 Question Bank

RNA classes · the promoter · RNA polymerase · capping · polyadenylation · splicing
25 MCQ · five options5 Definitions2 Written answersHarper's verified
Format note: the TMU Biochemistry paper gives five suggested answers (A–E), not four — these MCQs match that. Items tagged TMU 2019 or TMU 2020/21 come from the real papers. Answers are verified against Harper's Illustrated Biochemistry; the "marking schemes" in the source folder are other students' answer sheets, not official, so they are never used as the authority.
0 / 25 answered
1A promoter is best defined as ( ).
A. the region of DNA that includes the signals for initiation, elongation and termination
B. the site at which the ribosome binds the mRNA
C. the sequence at which transcription terminates
D. the first exon of a transcription unit
E. the DNA sequence to which RNA polymerase binds to initiate transcription of a gene
Answer: E
Set in Section I of BOTH papers — write this sentence verbatim. Option A is the transcription unit, a distinct term that is often set alongside it. The promoter determines two things: where transcription is to commence along the DNA, and how frequently this event is to occur.TMU Lecture 22 · Harper's ch.36, p.398
2The site to which RNA polymerase binds on the DNA template prior to the initiation of transcription is ( ).
A. the promoter
B. an intron/exon junction
C. the terminator
D. the initiator methionine codon
E. the open reading frame
Answer: A
A real MCQ from the TMU deck, reproduced verbatim. Note how the distractors are drawn from every other stage of the pathway — the initiator methionine codon belongs to translation (Unit 25), the terminator to the end of transcription, and intron/exon junctions to splicing.TMU Lecture 22, MCQ
3The enzyme that synthesises RNA from a double-stranded DNA template is ( ).
A. RNA-dependent RNA polymerase
B. DNA-dependent RNA polymerase
C. DNA-dependent RNA convertase
D. RNA-dependent replicase
E. reverse transcriptase
Answer: B
Another real slide MCQ. The name states the logic: DNA-dependent (the template is DNA), RNA polymerase (the product is RNA). Reverse transcriptase is the opposite — RNA template, DNA product — and is what telomerase resembles (Unit 23).TMU Lecture 22, MCQ
4Which statement about RNA polymerase is correct?
A. It requires an RNA primer made by primase
B. It requires a DNA primer
C. It initiates synthesis de novo and requires no primer
D. It synthesises in the 3′→5′ direction
E. It possesses 3′→5′ proofreading exonuclease activity
Answer: C
This is the sharpest contrast with DNA polymerase, and a favourite examination point. A primer is not involved in RNA synthesis, as RNA polymerases have the ability to initiate synthesis de novo. Synthesis is 5′→3′, with the template strand read 3′→5′. Proofreading is much weaker than in replication — errors matter less, because transcripts are disposable.TMU Lecture 22 · Harper's ch.36
5The bacterial RNA polymerase HOLOENZYME has the subunit composition ( ).
A. α₂ββ′
B. αββ′σ
C. α₂β₂σ
D. α₂ββ′σ
E. ββ′σ₂
Answer: D
The core enzyme is α₂ββ′; σ makes it the holoenzyme. Subunit functions: α — assembly of the tetrameric core; β — ribonucleoside triphosphate binding site; β′ — DNA template binding region; σ — helps the core enzyme recognize and bind to the promoter region.TMU Lecture 22 · Harper's ch.36
6The σ subunit is significant because ( ).
A. it removes introns from the primary transcript
B. it catalyses phosphodiester bond formation
C. it terminates transcription at the hairpin
D. it binds the ribonucleoside triphosphates
E. promoter recognition is a detachable function
Answer: E
One catalytic machine, many programmes. Alternative σ factors direct transcription of heat-shock genes, sporulation genes and so on. The eukaryotic solution differs in form but is identical in logic: all eukaryotic RNA polymerase forms require other proteins known as general transcription factors (GTFs), and it is those, not the polymerase, that recognise the promoter.TMU Lecture 22 · Harper's ch.36
7The transcription “bubble” is about ( ) bp, and the entire complex covers about ( ) bp.
A. 20; 30–75
B. 10; 20–30
C. 40; 100–150
D. 75; 200
E. 5; 10–15
Answer: A
Compare the bacterial promoter, which is approximately 40 nucleotides in length, with an eight-nucleotide-pair sequence about 35 bp upstream of the start site and a six-nucleotide-pair A+T-rich sequence about 10 nucleotides upstream — the −35 and −10 boxes. A+T-rich, of course, because it must melt.TMU Lecture 22 · Harper's ch.36
8Promoter clearance occurs ( ).
A. immediately on σ binding, before any nucleotide
B. after 3 to ~10 nucleotides, when the polymerase moves away
C. only when the termination sequence is reached
D. when the rho factor arrives at the complex
E. after the 5′ cap has been added to the RNA
Answer: B
It is the commitment step. Until it happens, the polymerase repeatedly makes and releases very short abortive transcripts. In eukaryotes, CTD phosphorylation is critical for promoter clearance as well as for elongation, termination and mRNA processing.TMU Lecture 22 · Harper's ch.36
9Which mechanism does NOT terminate bacterial transcription?
A. An intrinsic terminator — an inverted hyphenated repeat followed by a stretch of AT base pairs
B. Formation of an RNA hairpin that causes the polymerase to pause
C. Binding of the σ subunit to the terminator sequence
D. Rho, an ATP-dependent RNA-stimulated helicase
E. Disruption of the ternary complex of polymerase, nascent RNA and DNA
Answer: C
σ acts at initiation, not termination, and is released early in elongation. The intrinsic mechanism is mechanically elegant: the hairpin is too bulky for the RNA exit channel and causes RNA polymerase to pause, and the following AT stretch leaves only the weakest possible rU:dA hybrid holding the transcript on. A sequence, transcribed, becomes a mechanical device.TMU Lecture 22 · Harper's ch.36, p.400
10Mammalian cells possess how many distinct nuclear DNA-dependent RNA polymerases, and which makes mRNA?
A. One; it makes all RNA
B. Two; polymerase I
C. Three; polymerase I
D. Three; polymerase II
E. Four; polymerase III
Answer: D
Pol I — most rRNA. Pol II — mRNA, and most snRNAs and miRNAs. Pol III — tRNA and 5S rRNA. They are distinguished experimentally by α-amanitin, a specific differential inhibitor of the eukaryotic nuclear polymerases which blocks the translocation of RNA polymerase during phosphodiester bond formation.TMU Lecture 22 · Harper's ch.36, p.398
11Which eukaryotic promoter element has a particularly rigid requirement for both position and orientation?
A. The initiator sequence (Inr)
B. The downstream promoter element (DPE)
C. An enhancer
D. A silencer
E. The TATA box
Answer: E
Enhancers are the opposite extreme — they work at 1000–10⁵ bp away, in either orientation. Note also that the TATA box is not universal: the combinations occur as TATA+Inr 30%, Inr alone 30%, Inr+DPE 25%, all three 15% — so a majority of genes have no TATA box at all.TMU Lecture 22 · Harper's ch.36
12cis-acting elements and trans-acting factors are, respectively ( ).
A. DNA sequences on the molecule; diffusible proteins
B. diffusible proteins; DNA sequences in turn
C. RNA molecules; the DNA sequences they bind
D. enhancers; the silencers that oppose them
E. exons; the introns that separate them
Answer: A
The names come from genetics: a cis element can only affect a gene physically joined to it, whereas a trans factor diffuses and can act on any copy. Transcription factors have two functional parts — DNA-binding domains (DBDs) and activation domains (ADs) — an arrangement Unit 26 exploits.TMU Lecture 22
13TFIID binds the TATA box through ( ), and consists of ( ).
A. its TAF1 subunit; six subunits in total
B. its TBP subunit; 15 subunits, TBP plus 14 TAFs
C. the σ factor; four subunits in total
D. Mediator; some 50 subunits in total
E. its CTD tail; 12 subunits in total
Answer: B
RNA polymerase II requires TFIIA, B, D (or TBP), E, F and H to facilitate promoter-specific binding and formation of the preinitiation complex (PIC). But note the crucial limitation: RNA polymerase II and the GTFs can only catalyze basal or unregulated transcription in vitro. Regulated transcription needs coactivators and chromatin remodellers.TMU Lecture 22 · Harper's ch.36
14The carboxyl terminal repeat domain (CTD) of RNA polymerase II ( ).
A. is cleaved off immediately after initiation
B. is the ribonucleoside triphosphate site
C. the consensus Tyr-Ser-Pro-Thr-Ser-Pro-Ser
D. is found only in polymerases I and III
E. binds the TATA box element directly
Answer: C
Think of it as a moving scaffold whose phosphorylation state encodes the stage of transcription. Capping must happen immediately after initiation, splicing during elongation, polyadenylation at termination — and different phosphorylation patterns recruit each set of enzymes in turn. This is why eukaryotic processing is cotranscriptionally coupled. Eukaryotic pol II consists of 12 subunits.TMU Lecture 22 · Harper's ch.36
15RNA polymerase locates a promoter among millions of base pairs by ( ).
A. diffusing in three dimensions until it collides with the sequence
B. cleaving DNA at random until it finds the promoter
C. being guided there by the mRNA product
D. binding weakly and scanning at ≥10³ bp/s to find it
E. binding only to methylated cytosines
Answer: D
The scale of the problem: E. coli has 4 × 10³ transcription initiation sites in 4.2 × 10⁶ bp, and humans about 10⁵ promoters in 3 × 10⁹ bp. Because binding affinity is continuous rather than all-or-none, a stronger promoter is transcribed more often — which is how one element sets both where and how much.Harper's ch.36 · TMU Lecture 22
16The 5′ cap of eukaryotic mRNA is ( ) and functions to ( ).
A. a poly(A) sequence; blocks 3′→5′ exonucleases
B. a triphosphate group; signals the splicing
C. N-formylmethionine; initiates translation
D. an AAUAAA sequence; directs the cleavage
E. 7-methylguanosine; aids initiation, blocks nucleases
Answer: E
Note the symmetry with the tail: each end is protected against the exonuclease that attacks from its own direction, and both promote translation. They also cooperate — the cap and poly(A) tail have a synergistic effect on protein synthesis, because initiation factors bridge them and effectively circularise the message.TMU Lecture 22 · Harper's ch.36
17Polyadenylation of eukaryotic mRNA involves ( ).
A. cleavage ~20 nt after AAUAAA, then ~200 A residues added
B. cleavage at the 5′ end and 30 A residues added
C. A residues added by pol II during elongation
D. ~200 A residues added without prior cleavage
E. a poly(A) tail added to tRNA and rRNA too
Answer: A
The tail protects the 3′ end of mRNA from 3′→5′ exonuclease attack and facilitates translation. The exception worth knowing is histone mRNA, which lacks a poly(A) tail — appropriately, since histones are needed in a sharp burst during S phase and their message should be short-lived.TMU Lecture 22 · Harper's ch.36
18Exons and introns are, respectively ( ).
A. intervening sequences; the sequences that appear in mature RNA
B. sequences appearing in mature RNA; those cleaved out
C. the 5′ and 3′ untranslated regions
D. the promoter and the terminator
E. coding and template strands
Answer: B
Harper's phrasing is worth borrowing: introns neither appear in mature mRNA, nor contribute to the genetic information ultimately translated into the amino acid sequence. They are cleaved out of the transcript, and the exons appropriately spliced together IN THE NUCLEUS before the mRNA appears in the cytoplasm.TMU Lecture 22 · Harper's ch.36, p.404
19The spliceosome is composed of ( ).
A. TFIID together with the Mediator complex
B. Drosha together with the Dicer enzyme
C. snRNAs and snRNPs together with the pre-mRNA
D. ribosomal subunits together with tRNA
E. DNA polymerase together with primase
Answer: C
The sequence is: pre-mRNA combines with the snRNPs and other proteins to form a spliceosome; within it, snRNA base-pairs with nucleotides at the ends of the intron; the transcript is cut to release the intron, the exons are spliced together, and the spliceosome comes apart. Note that splicing is catalysed by RNA, not protein — snRNAs are ribozymes.TMU Lecture 22 · Harper's ch.36
20Alternative splicing is biologically important because ( ).
A. it allows translation to begin before transcription ends
B. it increases the overall rate of transcription
C. it protects the mRNA from degradation
D. one gene can give rise to several different proteins
E. it removes the need for a 5′ cap
Answer: D
It is also the answer to why introns are tolerated at all despite the metabolic cost of transcribing and discarding them. A related device is alternative promoter utilization: in the glucokinase gene, the β-cell promoter and exon 1B lie about 30 kbp upstream of the liver promoter and exon 1L; exons 2–10 are identical and the proteins have identical kinetic propertiestwo jobs, two control systems, one coding sequence.TMU Lecture 22 · Harper's ch.36
21Which RNA is NOT correctly matched with its function?
A. mRNA — carries the coding sequence to the ribosome
B. tRNA — the adapter molecule, recognising codons through its anticodon
C. rRNA — the structural and catalytic core of the ribosome
D. siRNA — RNA interference, protecting the host from RNA viruses
E. snRNA — carries amino acids to the ribosome
Answer: E
Carrying amino acids is tRNA's job. snRNAs serve rRNA and mRNA processing and gene regulation — they are the spliceosome's components. The four classes also differ in abundance, size, function and general stability: rRNA is most abundant, mRNA least stable — appropriately, since a regulatory message that persisted could not be switched off.TMU Lecture 22 · Harper's ch.34
22RNA differs chemically from DNA in that RNA ( ).
A. is hydrolysed by alkali to 2′,3′ cyclic diesters
B. is stable to alkali, whereas DNA is not
C. obeys Chargaff's base-pairing rule too
D. cannot act as a catalyst in any form
E. contains 2′-deoxyribose as its sugar
Answer: A
All of it follows from the 2′-OH, which sits beside the phosphodiester bond and attacks it when deprotonated. RNA is chemically self-destructive; DNA is not — which is why DNA is the archive and RNA the working copy. The same reactive hydroxyl, plus the freedom of a single strand to fold, is what allows ribozymes such as peptidyl transferase to exist. Note that Chargaff's rule does not apply to RNA.Harper's ch.34 · TMU Lecture 22
23microRNAs silence their targets by all of the following mechanisms EXCEPT ( ).
A. promoting mRNA degradation directly
B. cleaving the target gene's DNA
C. stimulating CCR4/NOT-mediated poly(A) tail degradation
D. inhibiting translation by targeting the cap-binding factor eIF4
E. annealing to the 3′ untranslated region of the target mRNA
Answer: B
miRNAs act on RNA, not DNA. Their processing route is worth knowing: transcribed by RNA pol II as pri-miRNAs, cut by Drosha into hairpins, transported to the cytoplasm and cut by Dicer. siRNAs, of 21–28 bp, are also generated by Dicer and act through the RNA-induced silencing complex (RISC).TMU Lecture 22
24RNA editing explains the relationship between apo B-100 and apo B-48 as follows ( ).
A. the intestinal gene uses another promoter
B. the two proteins come from separate genes
C. intestinal editing creates a new UAA stop codon
D. apo B-48 is proteolysed from apo B-100
E. apo B-48 arises by alternative splicing
Answer: C
This closes a loop from Unit 18, where you learned that apo B-48 is 48% of the length of B-100, from the same gene, and lacks the receptor-binding domain — hence chylomicron remnants must be cleared through apo E. A single C→U edit turns a glutamine codon into a stop. One base, edited in one tissue, redirects an entire lipoprotein pathway.TMU Lecture 22 · Harper's ch.25
25Which statement contrasting prokaryotic and eukaryotic transcription is FALSE?
A. In prokaryotes translation can begin before transcription is complete
B. Eukaryotic processing occurs primarily within the nucleus
C. Eukaryotes have three nuclear RNA polymerases, prokaryotes one
D. In eukaryotes the primary transcript is equivalent to the mRNA molecule
E. The eukaryotic pre-mRNA is modified at both ends and has introns removed
Answer: D
That is the prokaryotic case. In eukaryotes the primary transcript (pre-mRNA) is a PRECURSOR to the mRNA. The nuclear membrane is what makes processing possible — you cannot splice a message a ribosome is already reading. The cost is speed; the return is alternative splicing, and a whole class of disease: errors or changes in synthesis, processing, splicing, stability or function of mRNA transcripts are a cause of disease.TMU Lecture 22 · Harper's ch.36
1 Promoter — 3′ — PROVEN in BOTH papers+
A promoter is the DNA sequence to which RNA polymerase binds to initiate transcription of a gene.

DNA-dependent RNA polymerase attaches at this specific site on the template strand; this is followed by initiation of RNA synthesis at the starting point, and the process continues until a termination sequence is reached.

The promoter determines two things: where transcription is to commence along the DNA, and how frequently this event is to occur.

In bacteria promoters are relatively simple — approximately 40 nucleotides long, with an eight-nucleotide-pair sequence about 35 bp upstream of the start and a six-nucleotide-pair A+T-rich sequence about 10 nucleotides upstream; the σ subunit helps the core enzyme recognize and bind to the promoter region.

In eukaryotes promoters are more complex, built from the TATA box, initiator sequence (Inr) and downstream promoter element (DPE), together with promoter-proximal elements (50–200 bp) and distal enhancers and repressors (1000–10⁵ bp). The TATA box has a particularly rigid requirement for both position and orientation, and is bound by TFIID through its TATA-binding protein (TBP) subunit.TMU Lecture 22 · Harper's ch.36, p.398 · 2019 and 2020/21 papers, Section I
2 Transcription — 3′+
RNA biosynthesis from a DNA template. Its products are mRNA, tRNA and rRNA.

It is catalysed by DNA-dependent RNA polymerase, the enzyme responsible for the polymerization of ribonucleotides into a sequence complementary to the template strand of the gene, and proceeds in three general steps: initiation, elongation and termination.

Key features: synthesis has 5′→3′ polarity, with the template strand read 3′→5′; substrates are ATP, GTP, CTP and UTP, U replacing T; and a primer is NOT involved, as RNA polymerases can initiate synthesis de novo. Only one strand — the template strand — is copied, and it will not necessarily be the same strand of the double helix for every gene.

Initiation: polymerase binds the promoter and a transcription “bubble” of 20 bp forms; the whole complex covers 30–75 bp. Elongation: 3′,5′-phosphodiester bonds are formed 5′→3′. Termination: at a termination sequence the transcript is released — in bacteria by an intrinsic terminator (hairpin plus AT stretch) or by rho, an ATP-dependent RNA-stimulated helicase.TMU Lecture 22 · Harper's ch.36
3 The transcription unit — 2′+
The region of DNA that includes the signals for transcription initiation, elongation and termination.

Position +1 is the transcript initiation site.
Upstream sequences constitute the promoter.
Downstream sequences comprise the introns and exons.
The RNA product is the primary transcript.

Do not confuse it with the promoter, which is only the initiation-signal part of it — the two are commonly set together, and the distinction is the mark.TMU Lecture 22
4 Introns and exons — 2′+
EXONS are the RNA sequences that appear in mature RNAs.

INTRONS are intervening sequences that interrupt the exons of mRNA-encoding genes and that neither appear in mature mRNA nor contribute to the genetic information ultimately translated into the amino acid sequence of a protein.

The intron RNA sequences are cleaved out of the transcript, and the exons of the transcript are appropriately spliced together IN THE NUCLEUS before the resulting mRNA molecule appears in the cytoplasm for translation.

Splicing depends on consensus sequences at the splice junctions and an internal branch site, and is performed by the spliceosome, assembled from snRNAs and snRNPs.

Alternative splicing provides for different mRNAs — one gene, several proteins — which is why the apparent wastefulness of introns is tolerated.TMU Lecture 22 · Harper's ch.36, p.404
5 Post-transcriptional processing of eukaryotic mRNA — 3′+
The three modifications that convert a pre-mRNA primary transcript into a mature, exportable message. Processing occurs primarily within the nucleus, and is cotranscriptionally coupled to transcription through the phosphorylated CTD of RNA polymerase II.

1 · Capping. A 7-methylguanosine cap is added at the 5′ terminal. The 5′ cap is required both for efficient translation initiation and protection of the 5′ end from attack by 5′→3′ exonucleases.

2 · Polyadenylation. The mRNA is cleaved about 20 nucleotides downstream from an AAUAAA sequence, and poly(A) polymerase adds a tail subsequently extended to about 200 A residues. The poly(A) tail both protects the 3′ end from 3′→5′ exonuclease attack and facilitates translation. (Histone mRNA lacks a poly(A) tail.)

3 · Splicing. Introns are removed and exons are spliced together by the spliceosome.

The cap and poly(A) tail have a synergistic effect on protein synthesis: initiation factors bridge them, circularising the message — which also serves as a check that the transcript was completed and processed properly.TMU Lecture 22 · Harper's ch.36
1 Describe the process of transcription in prokaryotes, and compare it with transcription in eukaryotes. 10′

Definition and general features

Transcription is RNA biosynthesis from a DNA template, catalysed by DNA-dependent RNA polymerase, the enzyme responsible for the polymerization of ribonucleotides into a sequence complementary to the template strand of the gene. Its products are mRNA, tRNA and rRNA.

Four features distinguish it from replication: it adheres to Watson-Crick base-pairing rules using ATP, GTP, CTP and UTP, U replacing T; it proceeds 5′→3′, reading the template strand 3′→5′; a primer is NOT involved, as RNA polymerases can initiate synthesis de novo; and it copies only the template strand — which is not necessarily the same strand of the helix for every gene.

The bacterial enzyme

Core enzyme α₂ββ′; holoenzyme α₂ββ′σ. α — assembly of the tetrameric core; β — ribonucleoside triphosphate binding site; β′ — DNA template binding region; σ — helps the core enzyme recognize and bind to the promoter region.

Initiation

The holoenzyme must bind DNA and locate a promoter — a search it performs by binding many regions of DNA with low affinity and scanning at ≥10³ bp/s until it recognizes a region it binds with higher affinity. E. coli has 4 × 10³ promoters in 4.2 × 10⁶ bp.

Then follows localized unwinding of the two strands to provide a single-stranded template — a transcription bubble of 20 bp, the whole complex covering 30–75 bp — and formation of phosphodiester bonds between the first few ribonucleotides of the nascent chain, which is attached to the polymerization site on the β subunit. After nucleotides 3 to ~10, the polymerase undergoes a conformational change and moves away from the promoter — PROMOTER CLEARANCE.

Elongation and termination

The polymerase catalyzes formation of 3′,5′-phosphodiester bonds in the 5′→3′ direction, using NTPs as building units.

Termination occurs by two mechanisms. Intrinsic terminators contain an inverted, hyphenated repeat followed by a stretch of AT base pairs; the inverted repeat, when transcribed into RNA, generates an RNA hairpin which causes RNA polymerase to pause, and the weak rU:dA hybrid then releases the transcript. Rho-dependent termination uses rho, an ATP-dependent RNA-stimulated helicase that disrupts the ternary transcription elongation complex composed of RNA polymerase, nascent RNA and DNA.

Comparison with eukaryotes

ProkaryoteEukaryote
PolymerasesOne, α₂ββ′ + σThree — Pol I (rRNA), Pol II (mRNA), Pol III (tRNA, 5S)
Promoter recognitionσ factorGeneral transcription factors (GTFs)
Promoter~40 nt; −35 and −10 boxesTATA / Inr / DPE + proximal (50–200 bp) + distal (1000–10⁵ bp) elements
Primary transcriptEquivalent to the mRNAPre-mRNA — a precursor
ProcessingNone for mRNACap, poly(A) tail, splicing, in the nucleus
CouplingTranslation begins before transcription endsSeparated by the nuclear membrane
InhibitorRifampicinα-Amanitin

The eukaryotic complication

A complex consisting of 50 unique proteins provides accurate and regulatable transcription of eukaryotic genes. RNA polymerase II requires TFIIA, B, D (or TBP), E, F and H to facilitate promoter-specific binding and formation of the preinitiation complex (PIC); TFIID binds the TATA box through its TATA-binding protein subunit and consists of 15 subunits — TBP and 14 TAFs.

But RNA polymerase II and the GTFs can only catalyze basal or unregulated transcription in vitro. Regulated transcription additionally requires coactivators, Mediator, chromatin remodellers and chromatin modifying factors — because promoter accessibility, and hence PIC formation, is often modulated by nucleosomes, and nucleosome eviction by chromatin-active coregulators facilitates PIC formation and transcription.

Finally, eukaryotic pol II carries a carboxyl terminal repeat domain (CTD) of consensus Tyr-Ser-Pro-Thr-Ser-Pro-Ser, whose phosphorylation and dephosphorylation is critical for promoter clearance, elongation, termination, and even appropriate mRNA processing — the device that couples transcription to processing.

Marking guide: definition and the de novo initiation point 1.5 · subunit composition and σ's role 1.5 · initiation with the bubble size 1.5 · both termination mechanisms 1.5 · at least five correct prokaryote/eukaryote contrasts 3 · TFIID/TBP or the CTD 1.
2 Describe the post-transcriptional processing of eukaryotic mRNA. 6′

Why processing exists

The RNA molecules synthesized in mammalian cells are made as precursor molecules that have to be processed into mature, active RNA. In prokaryotes the primary transcript is equivalent to the mRNA molecule; in eukaryotes it is a pre-mRNA, and processing occurs primarily within the nucleus. The nuclear membrane is what makes this possible — a message a ribosome was already reading could not be spliced.

The processes of transcription, RNA processing, and RNA transport from the nucleus are highly coordinated, being cotranscriptionally coupled through the phosphorylated CTD of RNA polymerase II, which carries the processing machinery along with the enzyme.

1 · Capping the 5′ end

Mammalian mRNA molecules contain a 7-methylguanosine cap structure at their 5′ terminal. The 5′ cap is required both for efficient translation initiation and protection of the 5′ end of mRNA from attack by 5′→3′ exonucleases. Capping also occurs on snRNAs.

2 · Polyadenylation of the 3′ end

The mRNA is first cleaved about 20 nucleotides downstream from an AAUAAA sequence; poly(A) polymerase then adds a poly(A) tail, subsequently extended to about 200 A residues. The poly(A) tail both protects the 3′ end from 3′→5′ exonuclease attack and facilitates translation. Histone mRNA is the notable exception, lacking a tail.

Note the symmetry: each end is protected against the exonuclease that attacks from its own direction, and both promote translation. Moreover the cap and poly(A) tail have a synergistic effect on protein synthesis, because initiation factors bridge them and circularise the message — which also serves as a check that the transcript was completed properly.

3 · Splicing

Exons are the RNA sequences that appear in mature RNAs; introns are intervening sequences that neither appear in mature mRNA nor contribute to the genetic information ultimately translated. The intron RNA sequences are cleaved out and the exons appropriately spliced together in the nucleus before the mRNA appears in the cytoplasm.

Splicing requires consensus sequences at the splice junctions and an internal branch site, and is carried out by the spliceosome: pre-mRNA combines with the snRNPs and other proteins to form a spliceosome; within it, snRNA base-pairs with nucleotides at the ends of the intron; the transcript is cut to release the intron and the exons are spliced together; the spliceosome then comes apart, releasing mRNA which now contains only exons. The catalysis is performed by RNA, not protein — the snRNAs are ribozymes.

Alternative splicing provides for different mRNAs, so one gene may specify several proteins — the reason introns are worth their cost.

Other processing, and editing

  • Both ribosomal RNAs and most transfer RNAs are processed from larger precursors — the 45S transcript is cleaved to give the 18S, 5.8S and 28S rRNAs, and tRNAs and rRNAs undergo base modifications.
  • RNA editingreactions that change the nucleotide sequence of an mRNA by non-splicing mechanisms; the change may include nucleotide change, deletion or insertion. The classic case: the mRNA for apolipoprotein B in the liver is translated to apo B-100, while in the small intestine the mRNA is changed to yield a new termination codon (UAA), resulting in a much shorter protein, apo B-48.

Errors or changes in synthesis, processing, splicing, stability or function of mRNA transcripts are a cause of disease.

Marking guide: the pre-mRNA/mRNA distinction 0.5 · capping with both functions 1.5 · polyadenylation with AAUAAA and both functions 1.5 · splicing with the spliceosome named 1.5 · alternative splicing or RNA editing 1.