Pentose Phosphate — Q-Bank
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Unit 14 Question Bank

NADPH and ribose · the two phases · G6PD deficiency · glutathione
25 MCQ · five options3 Definitions2 Written answersHarper's verified
Format note: the TMU Biochemistry paper gives five suggested answers (A–E), not four — these MCQs match that. Items tagged TMU 2019 or TMU 2020/21 come from the real papers. Answers are verified against Harper's Illustrated Biochemistry; the "marking schemes" in the source folder are other students' answer sheets, not official, so they are never used as the authority.
0 / 25 answered
1The pentose phosphate pathway has two major functions. They are ( ).
A. transfer of reducing equivalents into the mitochondrion
B. the oxidation of pyruvate and the production of CO₂
C. the generation of ATP and the production of lactate
D. the storage of glucose and release of free glucose
E. NADPH for reductive synthesis, and ribose for nucleotides
Answer: E
And the third half of the answer, which also scores: it does not generate ATP. Unit 7's rule — NADH is for making ATP, NADPH is for building things — and this pathway is the supplier of that second currency.TMU “Chapter 20” Slide 2 · Harper's ch.20
2How much ATP does the pentose phosphate pathway generate?
A. None
B. Two per glucose 6-phosphate
C. One per turn
D. Three per glucose 6-phosphate
E. Ten per glucose 6-phosphate
Answer: A
No ATP is generated in the pentose phosphate pathway, whereas ATP is a major product of glycolysis. This is not a footnote — it is the defining contrast, and a favourite MCQ.TMU “Chapter 20” Slides 2, 14
3Which coenzyme is the hydrogen acceptor in the pentose phosphate pathway?
A. NAD⁺
B. NADP⁺
C. FAD
D. FMN
E. Coenzyme Q
Answer: B
“As in glycolysis, oxidation is achieved by dehydrogenation; but NADP⁺ and not NAD⁺ is the hydrogen acceptor.” This is one of the three ways to recognise a pentose phosphate question — the others being CO₂ produced and no ATP.TMU “Chapter 20” Slide 10 · Harper's ch.20
4The pathway is called a “shunt” because ( ).
A. it transfers carbon between cytosol and matrix
B. it operates only when glycolysis is blocked
C. it leaves and rejoins glycolysis further along
D. it shunts its electrons directly to oxygen
E. it bypasses the mitochondrion altogether
Answer: C
A siding, not a branch line. Glucose 6-phosphate leaves glycolysis, travels round, and rejoins the same line further down — having produced NADPH and pentoses on the way. It is an alternative route, not an alternative fate.TMU “Chapter 20” Slide 4
5Three molecules of glucose 6-phosphate entering the pathway give rise to ( ).
A. three CO₂ and three molecules of pyruvate formed
B. three ribose 5-phosphate and three ATP
C. one CO₂ and two fructose 6-phosphate
D. three CO₂, two hexose phosphate and one triose
E. six NADPH and three molecules of ATP
Answer: D
Three G6P give three CO₂ and three five-carbon sugars, which are rearranged to regenerate two molecules of glucose 6-phosphate and one of glyceraldehyde 3-phosphate. Since two glyceraldehyde 3-phosphate can themselves regenerate glucose 6-phosphate, the pathway can account for the complete oxidation of glucose.TMU “Chapter 20” Slide 9
6The enzymes of the pentose phosphate pathway are located in ( ).
A. the mitochondrial matrix
B. the inner mitochondrial membrane
C. the endoplasmic reticulum
D. peroxisomes
E. the cytosol
Answer: E
“The enzymes of the pentose phosphate pathway, as of glycolysis, are cytosolic.” That shared location is what allows glucose 6-phosphate to move freely between the two pathways.TMU “Chapter 20” Slide 10
7The pathway divides into two phases. They are ( ).
A. an oxidative irreversible, then a reversible phase
B. a reductive phase and a decarboxylating phase
C. a cytosolic phase and a mitochondrial phase
D. an anaerobic phase and an aerobic phase
E. an investment phase and a payoff phase
Answer: A
In the first phase, glucose 6-phosphate undergoes dehydrogenation and decarboxylation to yield the pentose ribulose 5-phosphate. In the second, ribulose 5-phosphate is converted back to glucose 6-phosphate by reactions involving mainly transketolase and transaldolase.TMU “Chapter 20” Slide 10
8The first enzyme of the pentose phosphate pathway is ( ).
A. 6-phosphogluconate dehydrogenase
B. glucose-6-phosphate dehydrogenase
C. gluconolactone hydrolase
D. transketolase
E. ribulose 5-phosphate 3-epimerase
Answer: B
It dehydrogenates glucose 6-phosphate to 6-phosphogluconolactone and is NADP-dependent. Being the first enzyme of an irreversible phase makes it the rate-limiting, committed step — which is exactly why its deficiency has such consequences.TMU “Chapter 20” Slide 12
9Which enzyme hydrolyses 6-phosphogluconolactone?
A. Glucose-6-phosphate dehydrogenase
B. 6-Phosphogluconate dehydrogenase
C. Gluconolactone hydrolase
D. Transaldolase
E. Ribose 5-phosphate ketoisomerase
Answer: C
The three enzymes of the oxidative phase in order: glucose-6-phosphate dehydrogenase (NADPH), gluconolactone hydrolase, then 6-phosphogluconate dehydrogenase (NADPH + CO₂).TMU “Chapter 20” Slide 12
10The second oxidative step, catalysed by 6-phosphogluconate dehydrogenase, involves ( ).
A. reduction of NADP⁺ without any CO₂ release
B. isomerisation directly to an aldopentose
C. transfer of a two-carbon unit onward
D. decarboxylation, giving ribulose 5-phosphate
E. hydrolysis of the lactone ring only
Answer: D
It also requires NADP⁺ as hydrogen acceptor. So the oxidative phase yields two NADPH and one CO₂ per glucose 6-phosphate — and CO₂ is a characteristic product, not produced in glycolysis at all.TMU “Chapter 20” Slides 12, 14
11Ribulose 5-phosphate 3-epimerase produces ( ).
A. ribose 5-phosphate, an aldopentose
B. sedoheptulose 7-phosphate
C. erythrose 4-phosphate
D. fructose 6-phosphate
E. xylulose 5-phosphate, another ketopentose
Answer: E
It alters the configuration about carbon 3. The other enzyme acting on ribulose 5-phosphate is ribose 5-phosphate ketoisomerase, which converts it to the corresponding aldopentose, ribose 5-phosphate.TMU “Chapter 20” Slide 13
12Which product of the pathway is the precursor of the ribose required for nucleotide and nucleic acid synthesis?
A. Ribose 5-phosphate
B. Ribulose 5-phosphate
C. Xylulose 5-phosphate
D. 6-Phosphogluconate
E. Sedoheptulose 7-phosphate
Answer: A
Formed from ribulose 5-phosphate by ribose 5-phosphate ketoisomerase. This is the pathway's second major function, and the link forward to Unit 21, nucleotide metabolism — where ribose 5-phosphate becomes PRPP.TMU “Chapter 20” Slide 13
13Which two enzymes dominate the non-oxidative phase?
A. Aldolase and enolase
B. Transketolase and transaldolase
C. Hexokinase and phosphofructokinase
D. G6PD and 6-phosphogluconate dehydrogenase
E. Epimerase and isomerase
Answer: B
They rearrange the carbon skeletons, regenerating glucose 6-phosphate and glyceraldehyde 3-phosphate. Note clinically that transketolase requires thiamin diphosphate, so erythrocyte transketolase activity is used as an index of thiamin status — the third enzyme in this course crippled by thiamin deficiency.TMU “Chapter 20” Slide 10 · Harper's ch.20
14Which is a characteristic product of the pentose phosphate pathway that is NOT produced in glycolysis at all?
A. Lactate
B. NADH
C. CO₂
D. ATP
E. Pyruvate
Answer: C
This is the subtlest of the three recognition cues. Glycolysis produces no CO₂ whatever, so carbon dioxide arising from a cytosolic glucose pathway can only mean the pentose phosphate pathway. The other two cues: NADP appears, and no ATP appears.TMU “Chapter 20” Slide 14
15In which of the following tissues is the pentose phosphate pathway LEAST active?
A. Liver
B. Adipose tissue
C. Adrenal cortex
D. Skeletal muscle
E. Lactating mammary gland
Answer: D
Its activity is low in non-lactating mammary gland and skeletal muscle — tissues that neither synthesise fat nor make steroids. It is active in liver, adipose tissue, adrenal cortex, thyroid, erythrocytes, testis and lactating mammary gland. Read that list as job descriptions: fat-makers, steroid-makers, and the red cell.TMU “Chapter 20” Slide 15
16NADPH produced by the pathway is used in reductive syntheses of ( ).
A. glycogen, starch and the cellulose polymers
B. ATP, GTP and creatine phosphate stores
C. urea and uric acid for excretion
D. purines and pyrimidines, directly
E. fatty acids, steroids and reduced glutathione
Answer: E
Four uses, and the last of them is the one that matters in the erythrocyte — which synthesises nothing but still needs NADPH for reduced glutathione.TMU “Chapter 20” Slide 15
17Synthesis of glucose-6-phosphate dehydrogenase and 6-phosphogluconate dehydrogenase may be induced by ( ).
A. insulin, in the fed state when lipogenesis increases
B. epinephrine, during vigorous physical exercise
C. cortisol, during the stress response
D. growth hormone, during rapid growth
E. glucagon, during a prolonged fast
Answer: A
This is Unit 7's long-term regulation by enzyme induction — changing the amount of enzyme over hours. It fits the pathway's purpose exactly: the fed state is when the liver and adipose tissue are making fat, and fat synthesis consumes NADPH.TMU “Chapter 20” Slide 15
18In the erythrocyte, NADPH from the pentose phosphate pathway is used to ( ).
A. synthesise fatty acids for the cell membrane
B. reduce oxidised glutathione, via glutathione reductase
C. reduce methaemoglobin back to haemoglobin
D. reduce pyruvate to lactate anaerobically
E. generate the ATP used by the sodium pump
Answer: B
Glutathione reductase is a flavoprotein containing FAD. Reduced glutathione then removes H₂O₂ in a reaction catalysed by glutathione peroxidase. The erythrocyte synthesises nothing — it needs NADPH purely for this antioxidant chain.TMU “Chapter 20” Slide 16
19Glutathione peroxidase is unusual in that it contains ( ) at its active site.
A. pyridoxal phosphate
B. a haem group
C. selenocysteine
D. a zinc finger
E. biotin
Answer: C
The selenium analogue of cysteine — and this is what Unit 1's “21st amino acid” is actually for. It also explains why selenium is a dietary trace element: a Unit 1 fact that only makes sense thirteen units later.TMU “Chapter 20” Slide 16 · Harper's ch.3, p.16
20Accumulation of H₂O₂ in the erythrocyte is harmful because it ( ).
A. it denatures glutathione reductase irreversibly
B. it oxidises haemoglobin to carboxyhaemoglobin
C. it inhibits glycolysis at phosphofructokinase
D. it oxidises the membrane, shortening red cell life
E. it precipitates 2,3-bisphosphoglycerate
Answer: D
This is the final link in the chain from enzyme to symptom: no G6PD → no NADPH → glutathione cannot be reduced → glutathione peroxidase cannot remove H₂O₂ → oxidative membrane damage → haemolysis.TMU “Chapter 20” Slide 16
21Genetic deficiency of glucose-6-phosphate dehydrogenase affects approximately how many people worldwide?
A. 1 million
B. 10 000
C. 500
D. 2 billion
E. 100 million
Answer: E
It is a major cause of haemolysis of red blood cells, resulting in haemolytic anaemia — one of the commonest enzymopathies in humans. Its prevalence reflects the protection heterozygosity confers against malaria, the same evolutionary logic as sickle cell trait (Unit 4).TMU “Chapter 20” Slide 8
22Why is the ERYTHROCYTE specifically vulnerable to G6PD deficiency?
A. it has no other NADPH source and no nucleus to make more
B. it contains more G6PD than any other cell type
C. its membrane contains no antioxidant lipids
D. it cannot take up glutathione from plasma
E. it lacks glutathione peroxidase entirely
Answer: A
Every other cell has alternatives; the red cell does not. It is also, by profession, the most oxidatively stressed cell in the body — permanently carrying oxygen. Compare Unit 10, where the same lack of alternatives makes glycolytic enzyme defects present as haemolytic anaemia.TMU “Chapter 20” Slides 8, 16 · Harper's ch.20
23Glucuronic acid is synthesised from glucose via the uronic acid pathway, which is of major significance for ( ).
A. the reabsorption of glucose in the renal tubule
B. excretion of metabolites and drugs as glucuronides
C. the generation of NADPH for steroid synthesis
D. the synthesis of ascorbic acid in humans
E. the formation of glycogen branch points
Answer: B
This is the biochemistry behind hepatic drug conjugation — every drug you will later meet as “glucuronidated in the liver” passes through here. A deficiency in the pathway leads to essential pentosuria.TMU “Chapter 20” Slide 8
24Which statement comparing the two major pathways of glucose catabolism is CORRECT?
A. Both produce CO₂ and ATP in similar amounts
B. Glycolysis uses NADP⁺ and the pentose phosphate pathway uses NAD⁺
C. The pentose phosphate pathway produces CO₂ and no ATP; glycolysis produces ATP and no CO₂
D. The pentose phosphate pathway occurs in mitochondria and glycolysis in the cytosol
E. Neither pathway shares any intermediate with the other
Answer: C
“Although glucose 6-phosphate is common to both pathways, the pentose phosphate pathway is markedly different from glycolysis. Oxidation utilises NADP rather than NAD, and CO₂, which is not produced in glycolysis, is a characteristic product. No ATP is generated in the pentose phosphate pathway, whereas ATP is a major product of glycolysis.TMU “Chapter 20” Slide 14
25Which hexoses are the main sugars absorbed from the gastrointestinal tract?
A. Glucose, ribose and xylulose
B. Fructose, mannose and sorbitol
C. Glucose, sucrose and lactose
D. Glucose, fructose and galactose
E. Galactose, maltose and starch
Answer: D
Derived principally from dietary starch, sucrose and lactose respectively. Fructose and galactose are converted to glucose, mainly in the liver. Note that sucrose, lactose and starch are not hexoses but the disaccharides and polysaccharide they come from.TMU “Chapter 20” Slide 7
1 The pentose phosphate pathway — 3′+
An alternative route for the metabolism of glucose, occurring in the cytosol, which does not generate ATP but has two major functions:

1. The formation of NADPH for the synthesis of fatty acids and steroids.
2. The synthesis of ribose for nucleotide and nucleic acid formation.

Oxidation is by dehydrogenation, but NADP⁺ and not NAD⁺ is the hydrogen acceptor. It has an oxidative, non-reversible phase (glucose 6-phosphate → ribulose 5-phosphate, yielding 2 NADPH and CO₂) and a non-oxidative, reversible phase (ribulose 5-phosphate back to glucose 6-phosphate, mainly via transketolase and transaldolase).

It is called a shunt because it begins with the glycolytic intermediate glucose 6-phosphate and rejoins glycolysis at glyceraldehyde 3-phosphate and fructose 6-phosphate.TMU “Chapter 20” Slides 2, 4, 10 · Harper's ch.20
2 Glucose-6-phosphate dehydrogenase deficiency — 3′+
Genetic deficiency of glucose-6-phosphate dehydrogenase, the first enzyme of the pentose phosphate pathwaya major cause of haemolysis of red blood cells, resulting in haemolytic anaemia and affecting approximately 100 million people worldwide.

Mechanism: without G6PD the erythrocyte cannot make NADPH; glutathione reductase (a flavoprotein containing FAD) therefore cannot regenerate reduced glutathione; glutathione peroxidase (which contains selenocysteine at its active site) cannot remove H₂O₂; and accumulating peroxide causes oxidative damage to the cell membrane, decreasing the life span of the erythrocyte and leading to haemolysis.

The erythrocyte is uniquely vulnerable because it has no other source of NADPH and no nucleus with which to make more enzyme.TMU “Chapter 20” Slides 8, 16
3 The uronic acid pathway — 2′+
The pathway by which glucuronic acid is synthesised from glucose.

It is of major significance for the excretion of metabolites and foreign chemicals (xenobiotics) as glucuronides — the biochemical basis of hepatic drug conjugation. A deficiency in the pathway leads to essential pentosuria.TMU “Chapter 20” Slide 8
1 Outline briefly the pentose phosphate pathway and its biomedical importance. 5′ — 'outline briefly'

Definition and functions

The pentose phosphate pathway is an alternative route for the metabolism of glucose. It does not generate ATP, but has two major functions: the formation of NADPH for the synthesis of fatty acids and steroids, and the synthesis of ribose for nucleotide and nucleic acid formation.

Location and the “shunt”

The enzymes, as of glycolysis, are cytosolic. The pathway begins with the glycolytic intermediate glucose 6-phosphate and reconnects with glycolysis, since two of its end products — glyceraldehyde 3-phosphate and fructose 6-phosphate — are intermediates further down that pathway. It is for this reason that it is called a shunt.

Overall, three molecules of glucose 6-phosphate give rise to three molecules of CO₂ and three five-carbon sugars, rearranged to regenerate two glucose 6-phosphate and one glyceraldehyde 3-phosphate.

The two phases

Oxidative, non-reversible. Glucose-6-phosphate dehydrogenase, an NADP-dependent enzyme, dehydrogenates glucose 6-phosphate to 6-phosphogluconolactone, hydrolysed by gluconolactone hydrolase to 6-phosphogluconate. 6-Phosphogluconate dehydrogenase, also NADP⁺-requiring, then carries out decarboxylation followed by formation of the ketopentose ribulose 5-phosphate. This phase yields 2 NADPH and CO₂.

Non-oxidative, reversible. Ribulose 5-phosphate 3-epimerase forms xylulose 5-phosphate; ribose 5-phosphate ketoisomerase forms ribose 5-phosphate, the precursor of the ribose required for nucleotide synthesis. Transketolase and transaldolase then rearrange the carbon skeletons back to glucose 6-phosphate.

Distinction from glycolysis

Although glucose 6-phosphate is common to both, oxidation utilises NADP rather than NAD; CO₂, which is not produced in glycolysis, is a characteristic product; and no ATP is generated.

Biomedical importance

The pathway is active in liver, adipose tissue, adrenal cortex, thyroid, erythrocytes, testis and lactating mammary gland, and low in non-lactating mammary gland and skeletal muscle. These tissues use NADPH in reductive syntheses — of fatty acids, steroids, amino acids via glutamate dehydrogenase, and reduced glutathione. The two dehydrogenases may be induced by insulin in the fed state, when lipogenesis increases.

Genetic deficiency of glucose-6-phosphate dehydrogenase is a major cause of haemolysis of red blood cells, resulting in haemolytic anaemia and affecting approximately 100 million people worldwide. Separately, glucuronic acid is synthesised from glucose via the uronic acid pathway, of major significance for the excretion of metabolites and xenobiotics as glucuronides; a deficiency leads to essential pentosuria.

Marking guide: two functions plus the absence of ATP 1.5 · cytosolic location and the shunt explanation 1 · the two phases named with at least three enzymes 1.5 · NADP versus NAD and CO₂ as distinguishing features 0.5 · one item of biomedical importance, ideally G6PD deficiency 0.5.
2 Elucidate how the pentose phosphate pathway protects erythrocytes against haemolysis. 8′ — 'elucidate'

The problem the erythrocyte faces

The erythrocyte is, by profession, the most oxidatively stressed cell in the body — it carries oxygen continuously. Yet it has no mitochondria, no nucleus with which to synthesise fresh enzyme, and no other source of NADPH. It also synthesises nothing, so its need for NADPH is not for biosynthesis at all but purely for antioxidant defence.

The protective chain

  1. The pentose phosphate pathway provides NADPH. The oxidative phase — glucose-6-phosphate dehydrogenase and 6-phosphogluconate dehydrogenase, both NADP-dependent — yields two molecules of NADPH per glucose 6-phosphate.
  2. Glutathione reductase, a flavoprotein containing FAD, uses that NADPH to reduce oxidised glutathione.
  3. Reduced glutathione removes H₂O₂, in a reaction catalysed by glutathione peroxidase, an enzyme that contains the selenium analogue of cysteine — selenocysteine — at its active site.

This last point connects to the classification of the amino acids: selenocysteine is the 21st protein amino acid, and glutathione peroxidase is one of its principal uses in the human body — which is also why selenium is an essential dietary trace element.

Why removing H₂O₂ matters

Accumulation of H₂O₂ may decrease the life span of the erythrocyte by causing oxidative damage to the cell membrane, leading to haemolysis. The red cell has no capacity to repair or replace damaged membrane protein, so oxidative injury is cumulative and terminal.

What happens when the chain breaks — G6PD deficiency

Genetic deficiency of glucose-6-phosphate dehydrogenase, the first enzyme of the pentose phosphate pathway, is a major cause of haemolysis of red blood cells, resulting in haemolytic anaemia and affecting approximately 100 million people worldwide.

The mechanism follows the chain in reverse: no G6PD → no NADPH → glutathione reductase cannot regenerate reduced glutathione → glutathione peroxidase cannot remove H₂O₂ → peroxide accumulates → oxidative damage to the membrane → haemolysis.

G6PD is the appropriate site for such a defect to matter because it is the first enzyme of the irreversible oxidative phase, and therefore the committed, rate-limiting step — there is no route around it.

Clinical corollary

Because the defect only manifests under oxidative load, haemolysis in G6PD deficiency is typically episodic, precipitated by oxidant drugs, infection or certain foods, rather than continuous. Compare the analogous logic in sickle cell disease, where polymerisation requires the deoxygenated T state, and the crisis is likewise precipitated rather than constant.

Marking guide: the erythrocyte's particular vulnerability — no mitochondria, no nucleus, no alternative NADPH 1.5 · the pathway supplying NADPH 1 · glutathione reductase named as an FAD flavoprotein 1.5 · glutathione peroxidase named with selenocysteine 1.5 · the consequence of H₂O₂ accumulation for the membrane 1.5 · G6PD deficiency with its prevalence and the mechanism traced 1.