MedStudy · Organic Chemistry
TMU MBBS 1st Year · Semester 2
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Chapter 7 · Organic Chemistry

Amines

Dopamine, adrenaline, serotonin, histamine, GABA — the neurotransmitters and signalling molecules that run the nervous system are almost all amines. Understanding their chemistry explains how antidepressants, antihistamines, local anaesthetics, and dozens of drugs work at the molecular level.

1°/2°/3°/quaternary Basicity order Alkylation & acylation Diazotisation Sandmeyer reaction Azo dyes
7.1

Structure & Classification

Amines are derivatives of ammonia (NH₃) where one, two, or three hydrogen atoms are replaced by organic groups. The nitrogen atom has three bonds and one lone pair of electrons — it is this lone pair that gives amines their basic character and nucleophilic reactivity. Think of nitrogen as always carrying a small negative charge cloud (the lone pair) that it is ready to share with anything positive or electrophilic.

Classification depends on how many carbon groups are attached to nitrogen. A primary (1°) amine has one carbon group and two N–H bonds (RNH₂). A secondary (2°) amine has two carbon groups and one N–H (R₂NH). A tertiary (3°) amine has three carbon groups and no N–H (R₃N). A quaternary ammonium salt (R₄N⁺) has four carbon groups and a positive charge — it has no lone pair and is not basic in the usual sense. This classification refers to the nitrogen, not the carbon attached to it (unlike alcohols).

Classification Summary
ClassFormulaN–H bondsExample
Primary (1°)RNH₂2Methylamine (CH₃NH₂)
Secondary (2°)R₂NH1Dimethylamine (CH₃)₂NH
Tertiary (3°)R₃N0Trimethylamine (CH₃)₃N
QuaternaryR₄N⁺0Tetramethylammonium (CH₃)₄N⁺
Aromatic amines: N directly attached to benzene ring (e.g., aniline, C₆H₅NH₂). Lone pair partially delocalised into ring — much less basic than aliphatic amines.
Test yourself — 7.1
• What makes an amine primary vs secondary? → Count the carbon groups on nitrogen: 1 = primary, 2 = secondary, 3 = tertiary.
• Does a quaternary ammonium ion have a lone pair? → No — all four valences on N are bonds to C. It carries a permanent positive charge.
• Give the structural formula for a secondary amine. → R₂NH (e.g., (CH₃)₂NH — dimethylamine).
7.2

IUPAC Nomenclature

For primary amines, replace the terminal “-e” of the alkane with -amine, or add “amino-” as a prefix when the amine is a substituent. For secondary and tertiary amines, name the largest group as the parent and use N-alkyl prefixes for the smaller groups attached to nitrogen (N- indicates the substituent is on N, not C).

Naming Examples
CH₃NH₂ → methanamine (methylamine)
(CH₃)₂NH → N-methylmethanamine (dimethylamine)
CH₃CH₂NHCH₃ → N-methylethanamine
C₆H₅NH₂ → benzenamine (aniline — common name required)
H₂NCH₂CH₂NH₂ → ethane-1,2-diamine (ethylenediamine)
Test yourself — 7.2
• IUPAC suffix for a primary amine? → -amine (e.g., propan-1-amine).
• How are substituents on nitrogen indicated? → With N- prefix (e.g., N-methylpropan-1-amine).
• Common name for C₆H₅NH₂? → Aniline.
7.3

Basicity of Amines

Amines are basic because the nitrogen lone pair can accept a proton. The strength of this basicity — measured as pKb or, more usefully, as the pKa of the conjugate acid (the ammonium ion R-NH₃⁺) — varies enormously between amine types. Understanding these differences is clinically important because the degree of ionisation at physiological pH determines how well an amine drug crosses membranes.

Aliphatic amines (alkyl groups on N) are more basic than ammonia because alkyl groups are electron-donating — they push electron density toward nitrogen, making the lone pair more available to accept a proton. Aromatic amines (like aniline) are far less basic because the nitrogen lone pair is partially delocalised into the π system of the benzene ring, making it less available for protonation. The nitrogen in aniline is essentially "distracted" by the ring, so it is a much weaker base.

Basicity Order (pKa of conjugate acid)
Aliphatic amines (pKa ~10–11) > Ammonia (pKa 9.25) > Aniline (pKa 4.6)

Amine typepKa (conjugate acid)Relative basicity
Diethylamine (2°)10.98Strongest common amine
Methylamine (1°)10.64Strong
Ammonia (NH₃)9.25Reference
Aniline (ArNH₂)4.63Very weak base
Note: in aqueous solution, 2° amines are often slightly stronger than 1° due to better solvation of their conjugate acids.
Clinical — pH and Drug Absorption (Henderson-Hasselbalch)
Most amine drugs (e.g., morphine, local anaesthetics, antihistamines) are weak bases. At pH 7.4 (blood), the ratio of ionised (RNH₃⁺) to unionised (RNH₂) depends on the pKa. Only the unionised form crosses lipid membranes. In inflamed tissue (pH ~6.8), more drug becomes ionised — this is why local anaesthetics work poorly in infected tissue: the acid environment traps them in the charged form that can't penetrate nerve membranes.
Test yourself — 7.3
• Why are aliphatic amines more basic than ammonia? → Alkyl groups are electron-donating, increasing electron density on N.
• Why is aniline a weaker base than methylamine? → The N lone pair is delocalised into the benzene π system, making it less available for protonation.
• Which is more basic: aniline or methylamine? → Methylamine (pKa 10.64 vs 4.63).
• Why do local anaesthetics fail in acidic infected tissue? → Low pH protonates the amine → charged form can't cross lipid nerve membranes.
7.4

Physical Properties

Primary and secondary amines can form hydrogen bonds through their N–H bonds, but nitrogen is less electronegative than oxygen. So amines have higher boiling points than alkanes of similar mass, but lower than comparable alcohols. Lower-molecular-weight amines (methylamine, ethylamine) are gases at room temperature and have a distinctly unpleasant fishy smell. Trimethylamine is the compound responsible for the smell of rotting fish. Many amines are water-soluble due to hydrogen bonding with water. Tertiary amines cannot donate H-bonds but can accept them.

Test yourself — 7.4
• BP order for same MW: amine vs alcohol vs alkane? → Alkane < Amine < Alcohol (N–H bonds are weaker H-bond donors than O–H).
• What compound gives rotting fish its smell? → Trimethylamine (and related amines from bacterial decomposition of amino acids).
7.5

Reactions: Alkylation & Acylation

Because the nitrogen lone pair is nucleophilic, amines react with electrophiles. Alkylation occurs when an amine attacks an alkyl halide (RX). The nitrogen attacks the electrophilic carbon, displacing the halide — an SN2 reaction. The problem is that the initial product (a secondary amine salt) is itself nucleophilic and reacts further with more alkyl halide, giving a mixture of primary, secondary, tertiary amines and quaternary salt. This over-alkylation makes simple N-alkylation a poor synthetic route to a specific product.

Acylation is far more selective. Reacting an amine with an acid chloride (or anhydride) gives an amide. The amide product is no longer basic (the lone pair is delocalised into the C=O), so it does not react further. This is the basis of the Schotten-Baumann reaction (amine + acid chloride with aqueous NaOH as base to neutralise HCl). Acylation is used to protect amines in synthesis and forms the basis of peptide bond formation.

Alkylation (over-alkylation problem) RNH₂ + R′X → RR′NH·HX → (RR′₂N → R′₄N⁺) [multiple products] Acylation (clean, one product) RNH₂ + R′COCl → R′CONHR + HCl    [amide formed; no further reaction]
Test yourself — 7.5
• Why does alkylation of amines give mixed products? → Each product is still nucleophilic and reacts with more alkyl halide (over-alkylation).
• Why does acylation stop after one step? → The amide product is not nucleophilic — N lone pair is delocalised into the C=O.
• What is the Schotten-Baumann reaction? → Acylation of an amine with acid chloride in aqueous NaOH; NaOH neutralises HCl byproduct.
7.6

Diazotisation

When a primary aromatic amine (ArNH₂, like aniline) reacts with nitrous acid (HNO₂, generated in situ from NaNO₂ + HCl) at 0–5°C, a diazonium salt (ArN₂⁺Cl⁻) forms. This is diazotisation. The diazonium group (–N≡N⁺) is an excellent leaving group and is the key to converting anilines into a vast range of other benzene derivatives.

Temperature is critical. Diazonium salts are unstable above 5°C — they decompose rapidly. The reaction must be performed in an ice bath, and the diazonium salt must be used immediately (it is never isolated as a dry solid — it can explode). Primary aliphatic amines also react with HNO₂, but give unstable diazonium ions that decompose immediately to carbocations — useful for creating carbocations, but not for the controlled chemistry of aromatic diazonium salts.

Diazotisation of aniline C₆H₅NH₂ + NaNO₂ + HCl (0–5°C) → C₆H₅N₂⁺Cl⁻ + NaCl + H₂O (benzenediazonium chloride)
Test yourself — 7.6
• What reagents produce a diazonium salt? → Primary aromatic amine + NaNO₂ + HCl at 0–5°C.
• Why must diazotisation be done below 5°C? → Diazonium salts are thermally unstable and decompose (or explode) at higher temperatures.
• What is the diazonium group? → –N≡N⁺ (a positively charged nitrogen–nitrogen triple bond), excellent leaving group.
7.7

Diazonium Salt Reactions

Diazonium salts are extraordinarily versatile — they allow us to introduce almost any substituent onto a benzene ring that would be impossible by direct electrophilic substitution. The N₂⁺ group leaves as N₂ gas (an excellent, irreversible driving force), and the carbon that was bonded to it is left as an aryl carbocation (or radical) that reacts with a variety of nucleophiles or coupling partners.

Sandmeyer & Other Diazonium Reactions
ReactionReagentProduct
Sandmeyer → ClCuCl / HClArCl (aryl chloride)
Sandmeyer → BrCuBr / HBrArBr (aryl bromide)
Sandmeyer → CNCuCNArCN (aryl nitrile)
→ F (Balz-Schiemann)HBF₄ then heatArF (aryl fluoride)
→ IKIArI (no Cu needed)
→ OHH₂O / heatArOH (phenol)
→ H (reduction)H₃PO₂ArH (deamination)
Azo couplingArNH₂ or ArOHAr–N=N–Ar (azo dye)
Diazonium Salt (ArN₂⁺) — Reaction Map Ar–N₂⁺Cl⁻ diazonium salt · keep at 0–5°C Ar–H H₃PO₂ (deamination) Ar–Cl CuCl / HCl Ar–Br CuBr / HBr Ar–CN CuCN (nitrile) Ar–I KI (no Cu) Ar–OH H₂O / heat + ArNH₂ or ArOH → Ar–N=N–Ar (azo dye, coupling reaction)
The diazonium cation is a powerful synthetic hub. N₂ gas leaves irreversibly, driving each reaction. Sandmeyer reactions (CuX catalyst) give aryl halides and nitriles. ArI and ArOH are special: no Cu needed for iodo; warm water gives phenol.
Clinical & Industrial — Azo Dyes & Sulfonamides
Azo coupling (diazonium + activated aromatic compound) gives brightly coloured azo dyes — used in textile colouring and as biological stains (e.g., Congo red for amyloid, Sudan stains for lipids). Sulfonamide antibiotics (sulfanilamide, sulfamethoxazole) were synthesised by coupling diazonium chemistry with sulfonyl groups — they were the first class of antibiotics, before penicillin. Sulfa drugs inhibit bacterial folic acid synthesis by competing with PABA (para-aminobenzoic acid), a substrate structurally similar to sulfanilamide.
Test yourself — 7.7
• What is the Sandmeyer reaction? → Diazonium salt + CuX → ArX (substitutes N₂⁺ with halide using copper catalyst).
• Which halide substitution does NOT need copper? → Iodo (ArN₂⁺ + KI → ArI directly).
• How is a phenol made from aniline? → Diazotise aniline → diazonium salt → warm with water → phenol + N₂.
• What is an azo dye? → Product of diazonium coupling with ArNH₂ or ArOH → Ar–N=N–Ar, intensely coloured.
• How do sulfonamides work? → Structural analogue of PABA; competitively inhibits dihydropteroate synthase in bacterial folic acid synthesis.
🎓

Past-paper Drill — Amines

1. Arrange in order of increasing basicity: aniline, dimethylamine, ammonia, trimethylamine.
Aniline < Ammonia < Trimethylamine < Dimethylamine. (Aniline: lone pair in ring. NH₃ reference. Alkylamines: electron donation increases basicity; in aqueous solution, 2° > 3° due to solvation.)
2. Starting from aniline, outline how you would make: (a) chlorobenzene, (b) bromobenzene, (c) iodobenzene, (d) phenol.
(a) Aniline + NaNO₂/HCl (0–5°C) → diazonium salt + CuCl → chlorobenzene (Sandmeyer). (b) Same but CuBr. (c) Diazonium + KI → iodobenzene (no Cu needed). (d) Diazonium + H₂O (warm) → phenol + N₂.
3. Why is the reaction of methylamine with CH₃Br a poor route to dimethylamine?
Over-alkylation: CH₃NH₂ reacts with CH₃Br → (CH₃)₂NH·HBr (secondary). But the secondary amine is still nucleophilic, reacts further → trimethylamine → tetramethylammonium salt. A mixture of all four products forms.
4. A student diazotises aniline at room temperature (25°C) and gets a very poor yield. Explain.
Diazonium salts are thermally unstable. Above ~5°C they decompose (ArN₂⁺ → Ar⁺ + N₂ → phenol + other products). The reaction MUST be performed at 0–5°C in an ice bath.
Chapter 7 Master Summary
Basicity: Aliphatic amine > NH₃ > Aromatic amine (lone pair in ring = less available)
Diazotisation: ArNH₂ + NaNO₂/HCl, 0–5°C → ArN₂⁺Cl⁻
Sandmeyer: Cu catalyst for Cl, Br, CN  |  KI direct for I  |  H₂O for OH
Acylation beats alkylation: amide product stops further reaction