Chapter 01 — Introduction to Organic Chemistry
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Chapter 01 · Foundation

Introduction to Organic Chemistry

TMU Slide: Organic Chemistry 1 — 2024 (Dr Heli Fan, 55 slides) Textbook: McMurry & Ballantine 8e, Ch 12 Exam Weight: ★ Foundation — vocabulary for every later chapter
1.1

What are Organic Compounds? — Vital Force Theory and Wöhler

Pick up a bottle of paracetamol from your hospital pharmacy. Every white tablet is an organic compound — yet for most of recorded human history, no chemist alive could have manufactured it in a laboratory. The prevailing belief, held with complete certainty until 1828, was that organic substances required something living to produce them: a mysterious animating force that no flask, furnace or mineral acid could ever replicate. This belief was called the Vital Force Theory, and it was so deeply accepted that most early chemists did not even try to synthesise organic compounds from scratch.

The theory collapsed in an unremarkable Berlin laboratory when Friedrich Wöhler, attempting nothing more than to prepare ammonium cyanate, discovered that his flask contained something else entirely — urea, the unmistakably organic compound that mammals excrete in urine. An inorganic salt had rearranged itself, without any cells or living tissue, into an organic product. The boundary between the living and the non-living dissolved in an afternoon, and modern organic chemistry was born.

◆ Vital Force Theory

A mysterious "vital force" (vis vitalis) present only in living organisms was needed to make organic substances. Therefore organic compounds could be produced only by plants and animals, never from purely mineral starting materials.

In 1828, the young German chemist Friedrich Wöhler (1800–1882) was heating ammonium cyanate (an inorganic salt) when it rearranged to give urea — an unmistakably organic compound, identical to the urea isolated from mammalian urine.

NH₄OCN —heat→ (NH₂)₂C=O (urea)

This single experiment disproved the Vital Force Theory: an organic compound could be made from an inorganic precursor, with no living tissue involved. Modern organic chemistry begins from this date.

⚠ Past-paper T/F — 2019 Q1
"Wöhler's synthesis of urea demonstrated that Vital Force Theory was correct."
FALSE. Wöhler's synthesis disproved the theory — he made an organic compound (urea) from an inorganic salt (ammonium cyanate), showing no vital force was needed.
◆ Modern Definition

Organic compounds are carbon-containing compounds, with a small number of exceptions that are by convention classed as inorganic: CO, CO₂, the carbonates (MCO₃), bicarbonates (MHCO₃), cyanides (MCN), and cyanates (MOCN). There is no strict boundary between organic and inorganic substances (Slide p.8).

⚠ High-yield T/F
"All carbon-containing compounds are organic compounds."
FALSE. CO, CO₂, H₂CO₃, carbonates, bicarbonates, cyanides and cyanates contain carbon but are classed as inorganic.
Test yourself • Who disproved the Vital Force Theory, and when? → Friedrich Wöhler, 1828
• What was the reaction that disproved it? → Ammonium cyanate (NH₄OCN) → urea (NH₂)₂C=O on heating
• Were the starting materials organic or inorganic? → Inorganic (ammonium cyanate is an inorganic salt)
• Name 4 carbon-containing compounds classed as inorganic → CO, CO₂, carbonates (MCO₃), bicarbonates (MHCO₃)
• True or false: all C-containing compounds are organic? → False — the inorganic exceptions listed above
1.2

Features that Distinguish Organic from Inorganic Compounds

Why does gasoline dissolve engine grease but water does not? Why does alcohol catch fire but saltwater is used to douse flames? Why does sugar melt at 186 °C while table salt requires 801 °C to liquefy? All of these everyday contrasts trace back to one fundamental difference: organic compounds are held together by covalent bonds (shared electrons), while many inorganic compounds are held together by ionic bonds (transferred electrons). This single distinction ripples out into every physical and chemical property listed in the table below.

Think of the difference this way: ionic compounds like NaCl are fully charged — positive Na⁺ and negative Cl⁻ ions are locked in a rigid crystal lattice by strong electrostatic forces. That lattice takes enormous heat to break, so m.p. is high. When water surrounds the ions and pulls them apart, the salt dissolves instantly. Organic compounds are electrically neutral, covalent molecules. There is no lattice, so less energy breaks them — low m.p. And because water molecules cannot grip them electrostatically, most organic compounds are insoluble in water but dissolve freely in other covalent organic solvents. This is the chemist’s rule: like dissolves like.

FeatureOrganic compoundsInorganic compounds
ElementsMainly C and H, plus O, N, S, P, halogens (Cl, Br, I, F)Most elements of the periodic table
Bond typePredominantly covalent bondsOften ionic (e.g. Na⁺Cl⁻) — transfer of electrons
Melting / boiling pointLow (most organics melt < 300 °C)Usually high (NaCl m.p. 801 °C)
DensityUsually < 1 g/mL (lighter than water)Often > 1 g/mL
SolubilityLow in water; good in organic solvents (like-dissolves-like)Many soluble in water (ionic salts)
Stability / reactivityPoor stability, easily combustible; slow reactions, side products, low yieldsUsually fast, clean ionic reactions
◆ "Like-dissolves-like"

Polar substances dissolve in polar solvents; nonpolar in nonpolar. Most organic molecules have low polarity and therefore dissolve in organic solvents rather than water. Exceptions are small polar organics (ethanol, glucose) that do dissolve in water because they can hydrogen-bond.

⚔ Medical Relevance

Drug lipophilicity (logP) is grounded in "like-dissolves-like". Lipid-soluble drugs (e.g. anaesthetics, steroids) cross the blood-brain barrier; highly water-soluble drugs do not. Every prescription decision — oral vs IV, half-life, distribution — ultimately rests on the polarity of an organic molecule.

Test yourself • What bond type dominates organic chemistry? → Covalent (shared electrons, not transferred)
• Why do organic compounds have lower melting points than ionic ones? → No rigid ionic lattice; weaker intermolecular forces
• Why are most organics insoluble in water? → Nonpolar molecules cannot interact with polar water; like-dissolves-like
• Name one organic compound that IS soluble in water and why → Ethanol (can H-bond with water via –OH group)
• Clinical consequence of high lipophilicity? → Drug crosses the blood-brain barrier (e.g. general anaesthetics, steroids)
1.3

The Covalent Bond

In ionic bonding one atom outright takes an electron from another. Covalent bonding is more cooperative: two atoms share a pair of electrons, both nuclei attracted to the same electron cloud. This sharing holds the atoms together. In organic chemistry, almost every bond you will ever encounter is covalent — the C–H bonds in methane, the C–C backbone of an amino acid, the C=O of a ketone. Understanding how electrons are shared, and how evenly or unevenly, is the foundation on which all organic reactivity is built.

◆ Covalent Bond

A chemical bond formed by the sharing of one or more pairs of electrons between two atoms. In organic compounds almost every bond is covalent.

1.3.1 — Electronegativity, polar vs nonpolar bonds

Sharing is rarely equal. Imagine two people pulling a rope — if one is much stronger, the rope ends up closer to them. Atoms do the same with shared electrons. The measure of an atom’s ability to pull shared electrons toward itself is called electronegativity. Fluorine is the strongest puller on the Pauling scale (4.0); caesium is the weakest. The practical consequence for medicine: every C–O, C–N, and O–H bond in a drug or biomolecule is polar, and that polarity determines where electrons attack, what bonds break in a reaction, and whether the molecule will dissolve in a patient’s bloodstream or diffuse through a lipid membrane.

A critical distinction examiners love: a molecule can contain polar bonds and still be nonpolar overall if the dipoles are arranged symmetrically and cancel. Carbon tetrachloride (CCl₄) is the classic example — four polar C–Cl bonds pointing to the corners of a perfect tetrahedron, each equal and opposite, so the net dipole is zero. Replace just one Cl with H (giving chloroform, CHCl₃) and the symmetry breaks: the three strong C–Cl dipoles no longer cancel the one weak C–H dipole, so the molecule has a net dipole and is polar.

◆ Electronegativity (χ)

The tendency of an atom to attract the bonding electrons of a covalent bond toward itself. The Pauling scale gives: F (4.0) > O (3.5) > N, Cl (3.0) > Br (2.8) > C, S (2.5) > H (2.1).

  • Nonpolar covalent bond — two identical atoms (H–H, C–C) or very similar electronegativities (C–H, Δχ ≈ 0.4). Electrons are shared equally.
  • Polar covalent bond — unequal sharing; the more electronegative atom carries δ− and the other δ+. The bond has a dipole moment. Examples: C–O, C–Cl, O–H.
  • Any diatomic molecule of two different elements is polar: HCl, HF, CO.
◆ Polar bonds ≠ polar molecule

A molecule can contain polar bonds yet be nonpolar overall if the bond dipoles are arranged symmetrically and cancel.

MoleculeGeometryBond dipolesNet molecular dipole
CCl₄ carbon tetrachlorideTetrahedral, symmetric4 polar C–Cl bonds, equal magnitudes pointing to corners of a tetrahedronCancel → nonpolar molecule
CHCl₃ chloroformTetrahedral but unsymmetric (3 Cl + 1 H)3 strong C–Cl dipoles + one weak C–H; do not cancelNet dipole → polar molecule
CO₂Linear O=C=OTwo equal opposing C=O dipolesCancel → nonpolar
H₂OBent (104.5°)Two O–H dipoles addStrongly polar
⚠ Classic past-paper MCQ
Which of CCl₄, CHCl₃, CO₂, H₂O is a polar molecule with polar bonds whose dipoles do not cancel?
CHCl₃ (and H₂O). CCl₄ and CO₂ have polar bonds but symmetric geometry, so the molecule is nonpolar overall.
Test yourself • EN order (high to low, 5 atoms)? → F (4.0) > O (3.5) > N=Cl (3.0) > C=S (2.5) > H (2.1)
• Is C–H polar or nonpolar? → Essentially nonpolar (Δχ ≈ 0.4, too small to be significant)
• Why is CCl₄ nonpolar despite having polar bonds? → Tetrahedral symmetry — four equal C–Cl dipoles cancel exactly
• Why is CHCl₃ polar? → Three C–Cl dipoles cannot be cancelled by the weak C–H; net dipole remains
• Which linear molecule is nonpolar despite polar bonds? → CO₂ (two equal, opposite C=O dipoles cancel)
1.3.2 — Covalent bond parameters

Three numbers describe any covalent bond: how long it is, how much energy it stores, and what angle it makes with adjacent bonds. These three parameters are not independent — they follow a single clean rule: more bonds between two atoms means shorter, stronger, and with a wider angle at the atom. A carbon–carbon triple bond (120 pm) is shorter than a double (134 pm) which is shorter than a single (154 pm). And the bond energy mirrors this: more electron density between the nuclei means you need more energy to pull them apart. These numbers show up directly in exam MCQs about which bond is “shortest” or “strongest”.

ParameterDefinitionTypical values
Bond lengthDistance between the centres of two covalently bonded atomsC–C 154 pm, C=C 134 pm, C≡C 120 pm, C–H 110 pm
Bond (dissociation) energyEnergy needed to homolytically break a bond in 1 mol of moleculesC–C ~347 kJ/mol, C=C ~614, C≡C ~839, C–H ~414
Bond angleAngle between two adjacent bonds at a central atomsp³ 109.5°, sp² 120°, sp 180°

Note the trend: shorter bonds are stronger. A triple bond is shorter and stronger than a double, which is shorter and stronger than a single — but a triple bond is not three times as strong as a single, because only the σ component is the same; the two π bonds are weaker.

Test yourself • Shortest C–C bond? → C≡C triple (120 pm)
• Strongest bond (highest BDE)? → C≡C (~839 kJ/mol)
• Bond angle around sp² carbon? → 120° (trigonal planar)
• Is a triple bond 3× stronger than a single? → No — 839 vs 347 kJ/mol is ~2.4×; the two π bonds are weaker than the σ
• What bond angle in methane? → 109.5° (sp³ tetrahedral)
1.4

How Carbon Bonds — Hybridization & VSEPR ★

Here is the puzzle that puzzled Pauling. Carbon’s ground-state electron configuration is 1s² 2s² 2p² — only two unpaired electrons sit in the 2p subshell. By simple orbital theory, carbon should form two bonds. But methane is unambiguously CH₄ with four equivalent C–H bonds, all of identical length (110 pm) and angle (109.5°). Worse, if carbon simply used one 2s and three 2p orbitals, those four bonds should be different — one shaped like an s-orbital, three shaped like p-orbitals, pointing in strange directions. No such difference is observed. Pauling’s solution in 1931 was orbital hybridization.

The idea is elegant: mathematically blend the s and p atomic orbitals before bonding occurs, producing a new set of equivalent hybrid orbitals that point in the directions geometry demands. Think of it like making a smoothie. You start with one banana (the s orbital) and three apples (the three p orbitals), blend them completely, and get four identical banana-apple smoothies (four sp³ hybrids). Each smoothie is the same — because the ingredients were blended equally — and they point apart as far as possible (tetrahedral, 109.5°) to minimise repulsion between the electron pairs.

◆ Orbital Hybridization (Linus Pauling, 1931)

Atomic orbitals of similar energy in the same atom are mathematically recombined to give a new set of equivalent hybrid orbitals with different shape, energy and direction. The total number of orbitals is conserved: mix 4 atomic orbitals (one 2s + three 2p) and you get 4 hybrid orbitals.

◆ VSEPR — Valence-Shell Electron-Pair Repulsion

"The best arrangement of a given number of electron domains is the one that minimises the repulsion among them." VSEPR is the rule that decides the geometry the hybrid orbitals adopt in 3-D space.

1.4.1 — The three hybridization states of carbon ★

As you remove p orbitals from the blend — going from sp³ (all three p orbitals mixed in) to sp² (only two p orbitals mixed in) to sp (only one) — two things happen. First, the bond angle opens: 109.5° → 120° → 180°, because with fewer orbitals to accommodate, the remaining ones spread further apart. Second, the leftover unhybridised p orbitals don’t vanish — they stick out sideways perpendicular to the hybrid framework, and it is these leftover p orbitals that overlap with a neighbour’s leftover p orbital to form the π bonds of double and triple bonds. So the rule is: every π bond in a double or triple bond comes from a leftover unhybridised p orbital. Sp² has one leftover → one π bond. Sp has two leftovers → two π bonds.

Hybrid stateMixNumber of hybrid orbitalsGeometry / shapeBond angleExample
sp³1 × s + 3 × p4Tetrahedral109.5°CH₄ methane, all alkanes, R–OH, R–NH₂
sp²1 × s + 2 × p (1 unhybridised p remains)3 + 1 leftover pTrigonal planar (with π bond from the leftover p)120°C=C alkene, C=O carbonyl, benzene
sp1 × s + 1 × p (2 unhybridised p remain)2 + 2 leftover pLinear (with two perpendicular π bonds)180°C≡C alkyne, HCN, CO₂
✨ Memory aid — "tetra, tri, line"

Count the bonded atoms + lone pairs: 4 → sp³ (tetrahedral), 3 → sp² (trigonal planar), 2 → sp (linear). The angle pattern 109.5° → 120° → 180° opens out as you remove a p orbital from the mix.

⚠ Past-paper T/F — 2019 Q2
"Orbital hybridization is the mixing of atomic orbitals to provide new orbitals that point in a different direction than the atomic orbitals."
TRUE. Hybridization recombines s and p orbitals of the same atom into new hybrid orbitals with different shape, energy and direction.
Test yourself • sp³ hybridisation: how many bonds? geometry? angle? → 4 bonds; tetrahedral; 109.5°
• sp² hybridisation: leftover orbitals? what do they form? → 1 leftover p; forms 1 π bond (gives the double bond)
• sp hybridisation: geometry and angle? → Linear; 180°
• Hybridisation of carbon in CO₂? → sp (2 double bonds; each C=O has 1 σ + 1 π)
• Where does the π bond come from? → Sideways overlap of two unhybridised p orbitals (one per atom)
1.4.2 — Single, double and triple bonds

Every C–C bond has a σ component — the head-on overlap of two hybrid orbitals along the bond axis. This σ bond is the skeleton. But when sp² or sp carbons are involved, the leftover unhybridised p orbitals project sideways above and below the bonding axis, and when two of these sideways lobes overlap, they form a π bond. A double bond is one σ plus one π; a triple bond is one σ plus two π. The σ and π bonds are not identical: the σ is stronger (head-on overlap is greater), the π bonds are weaker (sideways overlap is less efficient). This is why a triple bond, though the sum of three, is only about 2.4 times stronger than a single bond.

BondCompositionHybridizationExampleLength / Strength
C–C single1 σsp³–sp³Ethane CH₃–CH₃154 pm, 347 kJ/mol
C=C double1 σ + 1 πsp²–sp²Ethene CH₂=CH₂134 pm, 614 kJ/mol
C≡C triple1 σ + 2 πsp–spEthyne HC≡CH120 pm, 839 kJ/mol

"C=C counts as 2 bonds, C≡C as 3 bonds" when applying the rule that carbon always has 4 bonds in stable organic molecules.

⚠ Past-paper T/F — 2019 Q4
"In alkene molecules, the carbon–carbon double bond consists of two identical π bonds."
FALSE. A C=C double bond is one σ + one π, not two π's. (Two π's belong to the triple bond, which is 1 σ + 2 π.)
Test yourself • What is the composition of a C=C double bond? → 1 σ (head-on) + 1 π (sideways) — NOT 2 π
• Which is stronger, σ or π? → σ (greater overlap); π is weaker
• Hybridisation in ethyne (HC≡CH)? → sp; angle 180°; 1 σ + 2 π per C–C
• How many π bonds does benzene have? → 3 (one per C=C in the ring, delocalised)
• Carbon always has how many bonds in a stable organic molecule? → 4
1.4.3 — Free rotation around single bonds; conformations

Rotate a single C–C bond. Does the molecule change? Yes — but not permanently. A σ bond is formed by end-to-end overlap that is perfectly symmetrical around the bond axis; rotating one end relative to the other does not break the overlap. This is why single bonds rotate freely at room temperature, interconverting millions of slightly different three-dimensional arrangements every second. Each distinct arrangement is a conformation. The most stable is the staggered arrangement (H’s on adjacent carbons offset by 60°; lowest electron-pair repulsion) and the least stable is the eclipsed (H’s lined up; torsional strain highest). Double and triple bonds do not rotate because the π bond requires the two p orbitals to remain parallel — rotation would break the sideways overlap and break the π bond. This immobility is what locks alkene groups into fixed cis and trans arrangements (Chapter 3).

  • Eclipsed — H's on adjacent carbons line up; higher energy due to torsional strain.
  • Staggered — H's offset by 60°; most stable conformation of ethane.
  • Ethane has an "infinite number" of conformations between these extremes, but they interconvert ~10¹⁰ times/s and we treat them as one compound.

Double and triple bonds do NOT rotate — the π bond's sideways overlap would have to break. This is what locks cis/trans isomers of alkenes (covered in Chapter 3).

Test yourself • Why do single bonds rotate freely? → σ overlap is symmetric around the axis; rotation doesn’t break it
• Most stable conformation of ethane? → Staggered (lowest torsional strain)
• Why can’t double bonds rotate? → π bond requires parallel p orbitals; rotation would break it
• What does locked rotation cause in Chapter 3? → cis/trans (geometric) isomerism in alkenes
• What is torsional strain? → Repulsion energy between eclipsed electron pairs on adjacent carbons
1.5

Structural Representations of Organic Compounds

Organic molecules are three-dimensional objects, but chemistry communicates on paper in two dimensions. Over the past two centuries, chemists have developed four increasingly compact ways to draw the same molecule. You will encounter all four in this course and need to convert between them fluently, because an exam might give you a skeletal formula and ask you to name it, or give you a name and ask you to draw the Lewis structure. The key insight is that each representation just hides more implicit information — the Lewis structure shows everything; the skeletal formula hides every carbon atom and every C–H hydrogen, relying on you to reconstruct them mentally.

The skeletal (bond-line) formula is particularly important in medicine because drug structures in pharmacology textbooks and in the BNF are always drawn this way. A zig-zag line means a chain of carbons; each bend or endpoint is a carbon atom. Heteroatoms (O, N, Cl, etc.) are written in explicitly. Every carbon in the picture carries enough implicit H atoms to bring its bond count to exactly 4. Once you internalise that rule, you can “read” any drug structure you encounter in your clinical years.

Four ways to draw the same molecule — you must be fluent in moving between them, because the exam will give you any one and demand any other.

RepresentationWhat is shownExample — ethanol
1. Lewis dotEvery valence electron drawn as a dot or pairH:C(H⋅⋅H):C(H⋅⋅H):Ö:H — lone pairs on O visible
2. Full (expanded) / dash-line structural formulaEvery atom and every bond drawn as a lineH–C(H)(H)–C(H)(H)–O–H
3. CondensedC–H bonds omitted; H's written next to each carbonCH₃CH₂OH or CH₃–CH₂–OH
4. Bond-line (skeletal)Carbons are line vertices/ends; H's on C are implicit; only heteroatoms (O, N, X) are writtenZig-zag of 2 carbons with –OH at the end
◆ The "4-bond rule" for reading bond-line drawings

Every carbon must have exactly 4 bonds in total. To count hydrogens at a vertex: add up the bonds you can see to neighbours, then add enough implicit H's to bring the total to 4.

✨ Valence shortcut

Carbon = 4 bonds, Halogen (X) = 1, Oxygen and Sulfur = 2, Nitrogen and Phosphorus = 3, Hydrogen = 1. Remember "1, 2, 3, 4 across the row" for X, O, N, C.

Test yourself • In a skeletal formula, what does each bend or endpoint represent? → A carbon atom
• Which atoms must be written explicitly in a skeletal formula? → All heteroatoms: O, N, S, halogens (not C or H on C)
• How many implicit H's on a skeletal CH–vertex with 2 visible bonds? → 2 (needs 4 total; 2 visible + 2 implicit)
• Valence of N in amines? → 3 bonds; in ammonia: 3 N–H + 1 lone pair
• Which representation shows lone pairs most clearly? → Lewis dot structure
1.6

Functional Groups & Classification of Organic Compounds ★

There are more than 10 million known organic compounds, a number that grows every year as synthetic chemists build new drugs and materials. At first glance this seems impossibly complex to memorise. The saving grace is that these 10 million molecules are all built from a small number of functional groups — specific atoms or clusters of atoms that react in predictable, characteristic ways regardless of what carbon scaffold they sit on. Learn the ~13 functional groups in the table below, and you know the chemical personality of every member of each family. The carboxylic acid group (–COOH) in aspirin behaves like the –COOH group in penicillin; the amine (–NH₂) in dopamine behaves like the amine in amphetamine.

For a medical student, functional groups are not just a chemistry exercise — they are the vocabulary of pharmacology. When you see a drug structure in the formulary, the functional groups immediately tell you: is it acidic or basic in plasma? Will it ionise? Does it H-bond? How will it be metabolised? Aspirin’s –COOH is deprotonated at pH 7.4 (so it stays in plasma); morphine’s –NH is protonated at stomach pH (so it is absorbed in the small intestine, not the stomach). Every drug interaction begins with a functional group.

◆ Functional Group

A specific atom, or a small group of atoms, embedded in a molecule that undergoes characteristic chemical reactions and therefore determines the molecule's main chemical behaviour. The carbon skeleton is the scaffolding; the functional group is the "business end".

FamilyFunctional groupGeneral formulaExampleName suffix / prefix
AlkaneNone (only C–C, C–H single bonds)CnH2n+2CH₃CH₂CH₃ propane–ane
AlkeneC=CCnH2nCH₂=CH₂ ethene–ene
AlkyneC≡CCnH2n−2HC≡CH ethyne–yne
AromaticBenzene ringC6+nH6+2nBenzene C₆H₆(ring)
Alcohol–OH (on sp³ C)R–OHEthanol CH₃CH₂OH–ol
Phenol–OH on aromatic ringAr–OHPhenol C₆H₅OH(ring + -ol)
EtherR–O–R′R–O–R′Diethyl ether CH₃CH₂OCH₂CH₃oxy- / "ether"
Aldehyde–CHO (carbonyl at end)R–CHOAcetaldehyde CH₃CHO–al
Ketone>C=O (carbonyl inside chain)R–CO–R′Acetone CH₃COCH₃–one
Carboxylic acid–COOHR–COOHAcetic acid CH₃COOH–oic acid
Ester–COO–R′R–COO–R′Ethyl acetate CH₃COOCH₂CH₃–oate
Amine–NH₂ (1°), >NH (2°), >N– (3°)R–NH₂Methylamine CH₃NH₂–amine
Amide–CONH₂ (carbonyl + amine N)R–CONH₂Acetamide CH₃CONH₂–amide
Thiol–SHR–SHEthanethiol CH₃CH₂SH–thiol
Haloalkane–X (F, Cl, Br, I)R–XCH₃Cl chloromethanehalo-
1.6.1 — Homologous series

Within any one functional-group family, the members form a homologous series — a ladder of compounds where each rung is one CH₂ longer than the last. All members share the same chemical reactions (because the functional group is the same), but their physical properties change predictably as the chain grows. Boiling points rise with chain length (more C atoms → larger surface area → stronger van der Waals forces), while water solubility falls (more non-polar CH₂ groups dilute the effect of the polar functional group). This is why methanol is miscible with water but 1-decanol (C₁₀) is almost insoluble.

◆ Homologous series

A family of compounds with the same functional group and the same general formula, where each successive member differs from the previous one by one CH₂ unit. Adjacent members are homologs.

Each homolog has very similar chemical reactivity (same functional group), with physical properties (b.p., m.p., density) that change gradually as the carbon chain grows.

⚔ Medical Relevance

Recognising a functional group on a drug's structural formula is how you predict its pharmacology. –COOH → acidic, ionised in plasma (aspirin, NSAIDs). –NH₂ → basic, ionised in stomach acid (morphine, amphetamines). –OH → hydrogen-bonds, water-soluble (mannitol). Amide → the peptide bond of every protein and the β-lactam ring of penicillin.

Test yourself • What does a functional group determine? → The characteristic chemical reactions and behaviour of the compound
• Functional group of a carboxylic acid? suffix? → –COOH; suffix –oic acid
• Difference between aldehyde and ketone? → Aldehyde = –CHO at chain end; ketone = C=O inside the chain
• How does boiling point change in a homologous series as chain length increases? → Rises (more surface area → stronger van der Waals forces)
• Clinical example of an amide functional group? → Peptide bond (–CO–NH–) in every protein; β-lactam ring of penicillin
1.7

Isomerism (Structural / Constitutional)

Same molecular formula, completely different compound. Isomerism is one of the most clinically important concepts in organic chemistry, because it means that two molecules built from exactly the same atoms can have radically different shapes, solubilities, and biological activities. The antibiotic ampicillin and a related compound with the same formula can have vastly different bacterial kill rates; the two enantiomers of thalidomide include one that treats morning sickness and one that caused thousands of birth defects. In Chapter 1 we begin with the simplest type: structural (constitutional) isomers — the atoms are connected in a different order, even though the overall count is the same.

Think of it with Lego bricks. Give someone 4 red and 10 white bricks and ask them to build something. Two people can build quite different structures with the same pieces — a long straight tower vs a branched one. Those are chain isomers. Or they could build the same tower shape, but put the red bricks at position 1 vs position 2 — those are positional isomers. Or they could use the same pieces to build a car (an alcohol) vs a boat (an ether) that look nothing alike functionally — functional-group isomers. In all cases, the brick count is identical.

◆ Isomers

Compounds that share the same molecular formula but have different arrangements of atoms. Isomerism is the phenomenon of isomers existing.

In Chapter 1 we meet only structural (constitutional) isomers — atoms connected in a different order. Stereoisomers (cis/trans, R/S, enantiomers) are introduced in Chapters 3 & 8.

TypeDifferenceExample (same MF)
Chain (skeletal) isomerismCarbon skeleton arranged differentlyn-Butane CH₃CH₂CH₂CH₃ vs isobutane (CH₃)₃CH — both C₄H₁₀
Positional isomerismFunctional group at a different position on the chain1-Propanol CH₃CH₂CH₂OH vs 2-propanol CH₃CH(OH)CH₃ — both C₃H₈O
Functional-group isomerismSame atoms, different functional group entirelyEthanol CH₃CH₂OH (alcohol) vs dimethyl ether CH₃OCH₃ (ether) — both C₂H₆O
⚠ Practice (Slide p.45)
Draw the structural isomers of C₄H₁₀.
Two: n-butane CH₃CH₂CH₂CH₃ (straight) and isobutane / 2-methylpropane (CH₃)₃CH (branched).
Draw the structural isomers of C₅H₁₂.
Three: n-pentane, 2-methylbutane (isopentane), 2,2-dimethylpropane (neopentane).
Draw the structural isomers of C₂H₆O.
Two: ethanol CH₃CH₂OH (alcohol) and dimethyl ether CH₃OCH₃ (ether). Functional-group isomers.
Test yourself • Define structural isomers → Same molecular formula, different connectivity of atoms
• C₄H₁₀ has how many structural isomers? Name them → 2: n-butane (straight) and 2-methylpropane (isobutane)
• C₂H₆O isomers? → Ethanol (alcohol) and dimethyl ether — functional-group isomers
• What type of isomerism: 1-propanol vs 2-propanol? → Positional isomerism (–OH at C1 vs C2)
• Which type of isomers are introduced later in Ch 3 and 8? → Stereoisomers (cis/trans geometric; R/S enantiomers)
1.8

Why Organic Chemistry Matters for Medicine

A medical student once asked: “Why do I need organic chemistry? I’m going to be a doctor, not a chemist.” The answer is that the human body is an organic chemistry laboratory running 24 hours a day. Every breath, every heartbeat, every thought is the product of thousands of simultaneous organic reactions — oxidations, reductions, condensations, hydrolyses, phosphorylations — all happening in aqueous solution at 37 °C without any glass flasks. When any one of those reactions goes wrong, disease follows. Understanding the chemistry is the same as understanding the disease at its molecular root, which is increasingly where modern medicine operates.

  • The body is ~70% water, but its dry mass is overwhelmingly organic. Proteins, carbohydrates, triglycerides and nucleic acids are all organic polymers built from a few dozen monomer types — amino acids, monosaccharides, fatty acids, nucleotides.
  • Every metabolic step is an organic reaction. Glycolysis, the Krebs cycle, fatty-acid oxidation, the synthesis of neurotransmitters — all are oxidations, reductions, condensations, hydrolyses, substitutions you will meet in this course.
  • Most disease processes are organic-chemistry failures. Diabetes — impaired glucose metabolism (Chapter 9). Cancer — mutated proteins (Ch 8) and dysregulated organic signalling. Sickle-cell anaemia — a single amino-acid substitution (Glu→Val at position 6 of β-globin).
  • Almost every drug is an organic molecule. Aspirin, ibrutinib, antibiotics, anaesthetics, anti-virals — you cannot understand pharmacology without organic chemistry.
  • Modern medicine is moving to the molecular level. CRISPR gene editing, mRNA vaccines, monoclonal antibodies, targeted small-molecule oncology — all rest on organic and biochemistry.
⚔ Case: Sickle-cell anaemia

A single point mutation in the β-globin gene changes glutamate (polar, –COOH side chain, δ− in plasma) at position 6 to valine (hydrophobic, isopropyl side chain). The new hydrophobic patch lets deoxygenated HbS polymerise into long fibres → sickled erythrocytes → vaso-occlusion. One organic-chemistry change → lifelong disease.

Test yourself • Name two organic polymers in the body and their monomers → Protein (amino acids); DNA (nucleotides)
• Which amino acid replaces which in sickle-cell anaemia, and at what position? → Valine replaces glutamate at position 6 of β-globin
• Why does that substitution cause sickling? → Valine is hydrophobic; creates sticky patch → deoxyHbS polymerises into fibres
• Name one metabolic pathway that is an organic reaction sequence → Glycolysis (phosphorylation, oxidation, condensation steps on glucose)
• How does an organic chemist’s “like-dissolves-like” rule apply to drugs? → Lipophilic drugs cross cell membranes/BBB; hydrophilic drugs stay in plasma

Past-Paper Drill — Chapter 1 Items

All items below are taken or close-paraphrased from TMU past papers (2019–2022). True/False statements (Part III) are the most common Chapter-1 format.

⚠ Part III T/F — verbatim from past papers
2019 Q1 — "Wöhler's synthesis of urea demonstrated that Vital force theory was correct."
F. It disproved the theory.
2019 Q2 — "Orbital hybridization is the mixing of atomic orbitals to provide new orbitals that point in a different direction than the atomic orbitals."
T. Definition of hybridization.
2019 Q4 — "In alkene molecules, the C=C double bond consists of two identical π bonds."
F. One σ + one π, not two π's.
Recurring — "Organic compounds always contain carbon, and all carbon-containing compounds are organic."
F. CO, CO₂, carbonates, cyanides etc. contain C but are inorganic.
Recurring — "Single (σ) bonds in organic molecules can rotate freely; double and triple bonds cannot."
T. π overlap is sideways and breaks on rotation.
⚠ Part IV MCQ — concept checks
The carbon atom in methane (CH₄) is hybridised:
(A) sp   (B) sp²   (C) sp³   (D) unhybridised. 4 equivalent C–H bonds at 109.5° ⇒ sp³.
Which molecule has polar bonds but is a nonpolar molecule overall?
(A) HCl   (B) H₂O   (C) CCl₄   (D) CHCl₃. Symmetric tetrahedral geometry cancels the four C–Cl dipoles.
The carbon–carbon bond length is shortest in:
(A) ethane   (B) ethene   (C) ethyne   (D) butane. Triple bond → sp–sp → 120 pm, the shortest of the three.
Which class of compound contains the functional group –COOH?
(A) Aldehyde   (B) Ester   (C) Carboxylic acid   (D) Amide.
✨ Chapter-1 high-yield checklist

(1) Wöhler 1828 disproved vital force. (2) Organic = mostly C, H, O, N, S, P, X; covalent bonds; low m.p.; nonpolar; insoluble in water. (3) Carbon hybridises sp³ (4 bonds, 109.5°), sp² (3 bonds + 1 π, 120°), sp (2 bonds + 2 π, 180°). (4) Polar bonds ≠ polar molecule (CCl₄ nonpolar, CHCl₃ polar). (5) Memorise the 13-row functional group table. (6) Structural isomers: chain, positional, functional. (7) Single bonds rotate freely; double and triple do not.

Final rapid-fire recall • Wöhler’s experiment: reactant → product → year → implication? → NH₄OCN → urea; 1828; disproved Vital Force Theory
• sp², leftover p orbitals? bond type? geometry? → 1 leftover p; forms π bond; trigonal planar, 120°
• C₄H₁₀ isomers? → n-butane and 2-methylpropane (isobutane)
• Functional group in an amide? → –CONH₂ (carbonyl directly bonded to nitrogen)
• Why is CCl₄ nonpolar but CHCl₃ polar? → CCl₄: perfect tetrahedral symmetry cancels dipoles; CHCl₃: asymmetric, dipoles don’t cancel